10-05: A program that reads the exams result and displays the percentages.

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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited
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86 Answers

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Hidden content!
#include  * ***     **
int main ()
{

* *    * ***  *  * * **** **  *** *  pass, fail;
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  *    ** *   ** ***    ** *  * * *       Ratio:     **** failratio);
return 0;
}
answered by (-167 points)
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include   **    ** * ***
int main ()
{

*       * **   * ***  *  **   * pass, fail;
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  *** *  *    *** * **  *   ** * **  **** Ratio:  ******       * failratio);
return 0;
}
answered by (-167 points)
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Hidden content!
#include *       *** * *   
int main ()
{

   *  *  * * ***   *  *  *  *   pass, fail;
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* *  *  *  *  * * * * *    *   **     **   Ratio:   ****  *     ** failratio);
  * ** * ** 0;
}
answered by (-167 points)
0 0
Case 0: Wrong output
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Hidden content!
#include * * *** ** *  *
int main ()
{

** **** *  ** **  ***  ***  *  * pass, fail;
 **   ** **     *****  **  ***  ****    * 
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 **  *  ***** ***   ** ***  **** *** ** Ratio:  **   ** * *  *** failratio);
return 0;
}
answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:11:32: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("Success Ratio:  %d%\n", passratio);
                                ^
prog.c:13:28: warning: spurious trailing '%' in format [-Wformat=]
     printf("Fail Ratio:  %d%", failratio);
                            ^
commented by (4.3k points)
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Hidden content!
  ** * ***  ** *  *  
int main(void)
{
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 * * *** ***     ***   * **   *  *  **  *  *   * ** *
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**  **** **   **** **    ** **   Ratio: %g%%",b1);
     *  *** **  *  *** 0;
}
answered by (-254 points)
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Hidden content!
     *  ***    **   
int **** 
int * **** p1,p2;
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**  ****
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answered by (-32 points)
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Hidden content!
*   ** * ** **  *  ** 
int main()
{
float a,b,c;
**    *   **       ***** *** *  ****   **  * *  ***  *  *   ***
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 *  ***  *** * * *  ** *** * ***    *   Ratio: %.0f%%",b/c*100);
  * *  *  * ***     ** * *  ** 0;
}
answered by (64 points)
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Case 1: Correct output
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Hidden content!
#include <stdio.h>
int main ()
{
 ****** ***   ***  **  *  *** a,b,c;
** *   ***  ** *  * ** * *** **  * **  * **********  *** ** ** 
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*         *  ** *  *  *   * **  ***  *  * Ratio:     * *** ***  
***  **  *  *  *** ** *** *      *  * 0;
}
answered by (54 points)
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>
int main ()
{
  ** *****  *** ** ******   a,b,c;
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*      ** ** * **    *     *   ****** * Ratio: ***** ********
 * *** * * *     *  *****   * 0;
}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&a,&b);
             ^
prog.c:5:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&a,&b);
                ^
commented by (4.3k points)
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Hidden content!
    * *  ***  *  ***  

int main()

{
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** ** *  *  * ***  * 0;
}
answered by (-32 points)
edited by
0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main(void)
 ^~~~
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0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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0 0
Case 0: Correct output
Case 1: Correct output
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