10-05: A program that reads the exams result and displays the percentages.

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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited
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Hidden content!
#include    ** **    ** 
int main ()
{

*  *  ** * * *  ***  * ** * **  pass, fail;
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***** *   * * *  *** **       *  * ** Ratio:  *     *** failratio);
return 0;
}
answered by (-167 points)
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Case 0: Correct output
Case 1: Correct output
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Hidden content!
#include ** *     ** *   *
int main ()
{

*    * ** *    ** *   * **** pass, fail;
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return 0;
}
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Hidden content!
#include * ** * **  **  
int main ()
{

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* *** ****** 0;
}
answered by (-167 points)
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Hidden content!
#include * **  *   * * 
int main ()
{

** ** *   * *****  *  **  * **   pass, fail;
 **  * *   * * *   **  ***** *     ** **  ***  
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*    ***   *    ****   * **** ***        **   Ratio:  * *** ** * *    failratio);
return 0;
}
answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:11:32: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("Success Ratio:  %d%\n", passratio);
                                ^
prog.c:13:28: warning: spurious trailing '%' in format [-Wformat=]
     printf("Fail Ratio:  %d%", failratio);
                            ^
commented by (4.3k points)
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Hidden content!
* * ** ** ** *   
int main(void)
{
* *****     *     *  * a, a1,b,b1;
* * * *** ** *   * * ****  * *   *****      *****   * * **
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***  * *  * *  * **    ***    * *  **  Ratio: %g%%",b1);
** * * **  *   ***      * 0;
}
answered by (-254 points)
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Hidden content!
*  * ******       * *  
int    * 
int  * ** * p1,p2;
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**   0;}
answered by (-32 points)
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Hidden content!
*** * * *  ******
int main()
{
float a,b,c;
* ****** ** *  **  *  *       ** * **  **  **********    * *   
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 * *     ** **   *  * ** *   **** *** ** Ratio: %.0f%%",b/c*100);
     *   **      *** *   *    0;
}
answered by (64 points)
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Hidden content!
#include <stdio.h>
int main ()
{
  ****   *    *** ** *** *  * a,b,c;
** **   *  * * *** * **    * ** *   **  ****      * ** 
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 * **    *** *** ** *  **** ***  0;
}
answered by (54 points)
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Hidden content!
#include <stdio.h>
int main ()
{
**   **  **** *  ****  * * *** a,b,c;
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}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&a,&b);
             ^
prog.c:5:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&a,&b);
                ^
commented by (4.3k points)
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Hidden content!
* ** *      * * ** ****  

int main()

{
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* **  *  ** * ** * * * *  *

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}
answered by (-32 points)
edited by
0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main(void)
 ^~~~
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0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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0 0
Case 0: Correct output
Case 1: Correct output
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