3 like 0 dislike
11k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 11k views

86 Answers

0 like 0 dislike
Hidden content!
* * *** ***** * *
int main()
{
*** * ** * * * ** * * a,b,c,d;
* *** * ** * * * * * ** * ** * * ****** * * ** *
* ** * ** * * * *** *** * * Ratio: ** *** * * * * ***** *
* *** * * * * ** * ** ** * Ratio: %g%%",100*(b/(a+b)));
* * * ******** *** *** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
0 like 0 dislike
Hidden content!
#include ** * * * * *** *
int main()
{
** *** ** * * ** *** *** a, b, ans, sr, fr;

********* ********** * *** **** * * &a, &b);

* * *** ** **** * ** *
***** **** ** ** *
** **** ** * * ** * ***

**** * ****** *** **** ** ***** * **** Ratio: * *** ** * sr);
* ** ** * * ** **** * ***** * *** Ratio: ***** * fr);
** * * * ** ** * * * *** 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * *
int main()
{
****** ** * * ** ** * ** ** a, b, ans, sr, fr;

*** * ** * * * ** ***** ** ** * * *** * &a, &b);

*** * * * **** * **
** ****** ** *** ** * ** **** ***
***** * * * ** **** * **

* **** ***** ** * * **** * * *** * Ratio: ** ** * *** sr);
* ** **** ***** * ****** * * **** * Ratio: * ** ** fr);
* * ** ** * ** * 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
             ^
prog.c:6:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
                ^
0 like 0 dislike
Hidden content!
* ** *****
int * *

{

int a,b;
** ** c;
*** *

******** *
*** ** **

* ** * * * ** * ** **** *
*
* * * * 100;
***** ** - good;

** ** * ****** c)
* * *** ** ** *** d)*/

** **** *** * ******* *****
* ** * ** * ** ** **


}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include * * * *** ** *
int main ()
{

** ******* **** ** pass, fail;
* **** * * * ** * * ****
** * *** * **** ** ** ** ** * *** ** * ** &pass, *** **** *

** * * * * ** * ** ** = * * * * * ;
**** * * ****** * *** * ** * = ***
** ** ** * * * * * * * * * * Ratio: ***** **** *** ** ** * passratio);

** * * * *** ** * *** * * Ratio: * **** * ** * failratio);

** ** **** ** 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ** ** **
int main ()
{

* *** ** *** ** ****** * * pass, fail;
* *** ** *** ****** * * * * *** *
***** ***** * * * * * ** ** * * &pass, * *** *

***** * * * ** **** ***** ** = * * ** * ;
* * * ** ** * ** = **** * ******
* * ** *** * ** * **** **** ***** * Ratio: * * * passratio);

* * * * ** * ** ** * ***** ** * Ratio: * * * * failratio);

** *** ** * * 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ** * * ***** *

int main() {
** * ** * ******** ****
** * * *** * n1,n2;
* * ***** *** * * * tot=0;
**** * * * * * * * pass,fail;
* ****** ****** *** *
* ** ** *** *** ** ** * ** ** * &n1, &n2);
* **** **** ** *** * **
* * * * ** * ** * * * * = n1+n2;
** * * ********* * * *** = ((n1*100)/tot);
*** ** *** * * * * * *
* * *** * ** ** * * * = ((n2*100)/tot);
** **** ** *** **** * **
* **** * * ****** ******* * ** * *** Ratio: ** * * pass);
*** **** * *** ** * * * * Ratio: %d%%", fail);
* ** * *** * * * * *
* ** * ** ** * ***
* * * ** * ***** ** * * * 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ** ***

int main() {
** ** * ** *** * *
***** * * **** * * * * ***** ** n1,n2;
* ** ** ** **** * *** tot=0;
* * ** ** * *** * pass,fail;
****** *** * ** *** * *
**** ** * * * **** * * ** * * * &n1, &n2);
* ** * *** * * * * *
**** * ** * * * *** * * = n1+n2;
** *** **** * * *** * = ((n1*100)/tot);
*** ** * *** ****
* * * * * * * * = ((n2*100)/tot);
* *** *** **** * * ** **
* ****** **** * ** * * **** * Ratio: *** ** * * pass);
* * * * *** * * * * ** ** ** ********** Ratio: %d%%", fail);
* *** * *
*** * * * * ** * * ***
****** * ** * * * * * * ** 0;
}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
* * *** * * *** ** * * pass;
* ** * ******* * ** ** ** * fail;
** *** **** ** sum;
* ** * ** ******* ***** avg1;
**** * ** * ** **** * ** avg2;
* * **** * * **** * *****
** * * ** * * * *
* ** * * *** **
** *** * * * ** *** *** ** * ** * %d",&pass, &fail);
* * * * **** *** * *****
* **** ** * ***** *** *** * *
* * * **** ***** ** ** ** **** ***
* * ** * *** *** * * * * * **
*** * ** * ** * *
* ** * * * * ** * **** *** Ratio: %d%%\n",avg1);
* * * ***** ** *** ** ** * ** Ratio: %d%%",avg2);
** **** * *** ******
* * ******* ** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * *** ** **** *

**

{

int a,b;

* *** ** * * * *** * * * * ** *
* ** * *** *** * %d %% * * ** **** * *
** * * * * ** %d %% * * * * * * *
* * 0;

}
answered by (-66 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.229
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users