10-05: A program that reads the exams result and displays the percentages.

Question

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%

Answer 1

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int main()
{
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*  *      *  * * * ** **        **  *  ** * Ratio: %g%%",100*(b/(a+b)));
** *** *      *     * ** **  *  0;
}

Comments

prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^

Answer 2

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int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output

Answer 3

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int main()
{
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}

Comments

prog.c: In function 'main':
prog.c:6:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
             ^
prog.c:6:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
                ^

Answer 4

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Comments

Case 0: Correct output
Case 1: Correct output

Answer 5

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int main ()
{

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}

Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 6

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int main ()
{

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}

Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 7

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int main() {
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}

Comments

Case 0: Correct output
Case 1: Correct output

Answer 8

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}

Comments

Case 0: Wrong output
Case 1: Wrong output

Answer 9

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#include <stdio.h>

int main()
{
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}

Comments

Case 0: Correct output
Case 1: Correct output

Answer 10

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}

Comments

Case 0: Wrong output
Case 1: Wrong output