3 like 0 dislike
9.6k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 9.6k views

86 Answers

0 like 0 dislike
Hidden content!
* * ** ** **********
int main()
{
* * * * * ** ** ***** ** * a,b,c,d;
*** ** * ** * * ** **** * *** * * ** **
* * *** * * ** * * * * *** Ratio: *** ***** * *
** * *** **** ** *** ** **** Ratio: %g%%",100*(b/(a+b)));
* ** * ************** *** *** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
0 like 0 dislike
Hidden content!
#include * * ***
int main()
{
** ** ** * a, b, ans, sr, fr;

* ** **** * ** ** * * * *** *** * &a, &b);

* * * ** ****** ***** * **
* *** ** * * * * ** * *** ** **
* ** ****** * * ** * ** * *

**** * **** *** ***** * * * ** * ** Ratio: * * * * sr);
* * * **** *** ***** * ** ** ** * * Ratio: **** ** fr);
** * **** ** * * ** 0;
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** * *
int main()
{
********* * ** * * * a, b, ans, sr, fr;

** ** * * **** *** * ** ********* * ** * ** &a, &b);

* ** * *** *** *** ** * * * * **
* * * * **** *** ** ** ** * *
* * * * * ** * *** *** * * *** *

* *** * ** **** ***** **** ** * *** * * Ratio: * * ** ** sr);
*** ** * * * *** * ***** * *** * Ratio: ****** ** fr);
*** * * * * ** * * * 0;
}
answered by (-168 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
             ^
prog.c:6:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d", &a, &b);
                ^
0 like 0 dislike
Hidden content!
* * * *****
int * *

{

int a,b;
** c;
* **

* * *
* ** *

* ** * *** * ** * * * ** * **
****
* ** * * * 100;
* * *** - good;

** ** ***** ** ** c)
* **** * *** * **** ** d)*/

* * ** ****** * **** ** * * * * *
* * * * * * * * ** *** **


}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include * ******* * *
int main ()
{

* *** ** * *** * ** * * * * pass, fail;
* ** **** **** ** ** ** **** *
* ** * ** ** * * ** * * * *** * * &pass,

* * * * ** ** *** * = * **** *** * ;
* ** * * ** ** *** * ** * = ** * * *
******** ** ** **** *** * * * ** Ratio: *** **** ** ** * passratio);

* * *** * *** *** ********** * * Ratio: * * ** * * failratio);

** * *** **** * * ** 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include ****** * ** *
int main ()
{

** **** * ** * *** * * pass, fail;
* * * ***** ** * * * ** * * * * *
*** *** * **** ** *** ** * ********* &pass, * ** ** *

*** *** * ** * * ** **** = * * * ** ;
* ** *** ***** * * **** * = *** ** *
** * * * * * * * * Ratio: ** * passratio);

*** ** * ********** * *** ** * Ratio: * ** ** failratio);

* * * * * * 0;




}
answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include *** * ** * *

int main() {
* *** ** * *
** ***** *** **** * n1,n2;
*** ** *** * * * ** * tot=0;
** * *** ***** * ** * pass,fail;
* * * ******* * ****
****** * ******* * ** * * * * * &n1, &n2);
* * **** * * ** * *
***** *** *** * *** * *** = n1+n2;
** * * ** ** * * * = ((n1*100)/tot);
* * ** *** * * *
****** *** ** * * ** = ((n2*100)/tot);
** ** * ** ** * * **
** ** * * *** ********* ** * * * Ratio: ** ** pass);
** ** *** * **** * * * * **** * Ratio: %d%%", fail);
* * ** * *** * * * **
* * * * * ***** *
** * * ** * ** * * * * * *** 0;
}
answered by (323 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include ***********

int main() {
*** * * *** **** ** ** ** **
*** * ** ** **** **** n1,n2;
* ** *** * ****** *** tot=0;
***** *** ** * * * ** * * * pass,fail;
* ** *** ***** * *
**** ** * * ** **** ** * ** ****** &n1, &n2);
* **** * **
** * * ** *** = n1+n2;
* ** * * * * ** * ** = ((n1*100)/tot);
**** * ****** * * *
** ** * ** ** * ** * ** ** * = ((n2*100)/tot);
* * ** * ** *** ** *** *
* * ** * ** ** * ** *** * ** Ratio: * ** ** *** * pass);
*************** **** ****** * * * ** Ratio: %d%%", fail);
*** * * ***** * * ***
** *** ** ** * **** ** **
** * * *** ** * * ** * 0;
}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()
{
** ** ***** * ** ** ** pass;
*** * *** * * * * ** * * * fail;
**** * * ** * * * * ** sum;
*** ** * * ** ***** avg1;
*** ******* *** * *** * ** avg2;
* * * ** *** * * * *
** * * * *** * * * ***
* ** * ** ** * * ***
** * *** **** * ** * ** **** *** * * %d",&pass, &fail);
**** * * ** **** ** *
* ** ****** ** * *** * * **** * *
* *** * * * ** * *** * **
* ** * ****** ** ** * * ** ** *
*** *** * * * * * * * *
** * **** *** * *** * * ***** *** * ** Ratio: %d%%\n",avg1);
*** * ** ** ** * ***** * ** Ratio: %d%%",avg2);
******** * * ** ** *
* *** * **** * *** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * * * * ***

* * ****

{

int a,b;

** ** ***** *** * **** * ** *
* * *** * *** %d %% * * ** * **
* *** * * %d %% * * * * ** *
*** 0;

}
answered by (-66 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.196
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users