3 like 0 dislike
12.8k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.8k views

86 Answers

0 like 0 dislike
Hidden content!
#include * * * * ****

int main()
{
** *** * ** * *** * * x,y;
** ** * **** * ** ****** * a=0,b=0;
** ** **** * *** ** * * ** **** * * **
* * ** ** * ****** *
*** ** * ** **** * * * *
* ** ** ** *** * ** * ** ** * * * *** Ratio: %g%%",a);
*** ** * * * * ** ** ** **** ** ** * * * ** *
*** **** * ** * * * * ****** Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include ** * ** *

int main (void)

{
**** * *** * **** * * a,b;
* * * * * * * ******** ** * * * * *** * **** *** ** *
*** ** * ***** * * ****** ** ** * ** *** Ratio: %g%%\nFail Ratio: * * **** * *** **

** * ** * * * * * *** 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * ****** **

int main() {
** * * * * **** ** *** * a,b;
* ** ** * * * * * *** c;
** * * ** * * ***** *** *** %d", &a, &b);
** ** * *** ******* ** * ****
** * **** * ** *** * * *** p,f;
*** *** *** * *** *
* * * ** **** * ** ***
* * ** ********* * p2,f2;
**** *** ** *** *** * ****
** ** * * * * * **** * *
* * * *** ** * **** * *** *** Ratio: %d%%\n", p2);
* * ** * * ** * ** * ** **** * * Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** * * * ****



int main() {
******* *** * *** * a,b;
** * *** * * ** c;
* **** * * ***** * *** %d", &a, &b);
* * **** * **** **
******** *** ** * ** * ** p,f;
** * * * * * * *****
* * * *** * * *
**** * * *** * p2,f2;
* * ** * * *** * *
* **** * * ** **** ** ***
* * * ** ***** * ** ** ** ** Ratio: %d%%\n", p2);
* ** * * ** * *** ** ***** ** * * * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
****** * * *



int main() {
* *** ** * ** * * a,b,c;
***** ** ** *** ** ** * * %d", &a, &b);
* ** * * * ******* ** ** *
** ** * *** ** ** * * * ** p,f;
* * * * ** * ** * * * * **
* * * *** ***** * * * ** * *
* * * * * * * * *** p2,f2;
* ** **** * ** * *
* * **** *** * ****** ***
* * * * * ** * ** ** *** *** Ratio: %d%%\n", p2);
* ** ** *** **** *** * * * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include * *** ***

int main(void)
{
* * ** * ** ** * a,b,sum1,sum2;
* * ******* * ** *** *** * * * * ** ***** ****** ** * **
**** ** * ****** ** * *** = a*100/(a+b);
******* ** **** *** * * * = b*100/(a+b);
* ** *** * ***** * * ** * * * *** Ratio: * *** ** *
*** *********** * * * ****** ***** Ratio: ** *

* ** ** ** ***** * * **** 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* *** * ** ** *** *** * a,b,sum1,sum2;
** ** * * ** **** *** * **** * * * * * * ***** * * *
* *** ** * ** ** ** = a*5;
**** * ** ** * ** * = b*5;
** * * * * * ** ** ** (sum1>40)
* *** * *** **** ***** *** ** ****** ** *** * * *** * * * * Ratio: %d%%\n",sum1);
* ** ** ** ** ** ** * ** *
* * ** * * ** * * * * * *** * *** * **** * * * Ratio: %d%%",sum1);
* ** ** * **** * * **** ***** *
*** * * * ****** * **** * ** ** * ****** ************* Ratio: ** * ***** **
* ** * * * *** *****
** * ***** ** * ** **** * ** * * ** ********* ** * Ratio: %d%%",sum2);
****** * **** ** ** * * * * * 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
*** * *** *
int main(void)
{
* * *** ** ** ** * a, b,success, fail ;
** *** ** * ***** ** * * * * * * * *** *
* * * * * ***** * * *** ***** ** *
*** * ***** * *** ** * *** * ** *
** *** * ** * * * * *** * **** * ** * * * ** ** Ratio: %g%%\nFail Ratio: * ** * success, fail);
* * * * *** ****** * *** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
* ** ***



int main() {
* ** * * *** * ** a,b,c;
** *** * * ** ***** * * %d", &a, &b);
**** * * * * *** * ** ** ***
*** * * **** * *** ** p,f;
* * * ****** * ** * * *
* * * * * * * * ** *
***** * * **** * ** p2,f2;
** * *** ** * * * ** *** *
* *** ******* * ** ****** * *
* * ****** ** * ****** *** * ** * Ratio: %d%%\n", p2);
* * *** * ** ** **** * * * * Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
** ** *** * ** * * *** ** a,b,sum1,sum2;
* * * *** * * * ****** * * * ** * * * ** * * * **
******* * ****** ** * ** = a*5;
* * * * * * * ** = b*5;
* ** ** *** ** (sum1>40)
* * *** **** * * ** **** ** * ** * * * * * ** * * * Ratio: %d%%\n",sum1);
** * *** * * ** * * *
* ** *** *** * * ** * ** **** **** *** * * ******* * Ratio: %d%%",sum1);
* *** * ***** * ** **** * *
***** ** **** * ** * * * * * ** * * ** * * ** * *** Ratio: * ***** *
* *** *** ****** * * * *
*** * *** * ** * * * *** ** ****** * ** ** ** Ratio: %d%%",sum2);
**** * ** * * **** ** 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.32
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users