3 like 0 dislike
12.8k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.8k views

86 Answers

0 like 0 dislike
Hidden content!
#include * * * *****

int main()
{
** * * * * * *** x,y;
*** * ** * ** ** a=0,b=0;
***** ***** ** * * *** ** * * * *** * ** * *
**** ** ******* ** * *** * *** * * ***
*** ***** * * ***** * *
*** * * * * *** * ***** Ratio: %g%%",a);
* ** ** * *** ** * **** * * * *** * * *
* ** *** ** ** ** * *** * ** * * Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include ** * * *

int main (void)

{
*** * ** * * * *** * ** a,b;
* * ** * *** ** ** * * ** * ** * * * * *** **
*** * ** *** * * ** ** ** ** * ** Ratio: %g%%\nFail Ratio: *** * ** *

* *** ** * *** * 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** ** * *

int main() {
* * * *** * * * ** ** a,b;
* **** * ** ** * ** ** ** c;
* * ** * ** * * * ** * ** %d", &a, &b);
* *** * * * **** *
** * * * * ********* * p,f;
* ** * * * ** *** * ****
* **** * ** ** *****
******* ** * * *** p2,f2;
* ***** ***** * * ** **
* * * ** * * * * * *
* *** * * ** ** * * ** ** Ratio: %d%%\n", p2);
* *** * * ******* **** *** * * * Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
**** * ** * *****



int main() {
** ** ** ** * ** ** ** a,b;
** * ** *** *** **** * ** * ** ** c;
* *** * * *** ** ** * *** * %d", &a, &b);
* *** **** * * ** * * *
* * ** ** * *** * * * ** p,f;
** ** * * * * ** *
* * * *** **** * * *
*** * **** ** *** * * ** p2,f2;
******** * * * * ***
* * ** * ******* *** *
* * **** * * ** ** *** * * Ratio: %d%%\n", p2);
* ** ** * * * ** * * * * * ** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
* * *** * * **



int main() {
* * * ** * * ** ********** a,b,c;
****** *** ** * * * ** *** ** ** %d", &a, &b);
** ***** ** ** * * * ** * *
*** * **** ***** ** * ** ** * p,f;
*** *** * * * ** * ** *
* * * *** **** **** ****
* * *** *** ** ** ** * **** p2,f2;
* * * * ***** * * ********
*** * * ** * ** * ***** ***
* * ** *** ******* * ** * ** * Ratio: %d%%\n", p2);
** * ** * ****** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include *** * *****

int main(void)
{
******* * * *** * a,b,sum1,sum2;
* **** * * * ** * ******* * * * ** * ** ** ** * ** *
* ***** * **** * * = a*100/(a+b);
* * * ***** **** *** * * *** = b*100/(a+b);
** * ***** * ***** * * **** * *** Ratio: ** * *** **
** ** * *** ** ** * ********* Ratio: ** ***

** ** * * *** * * ** ** 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
** ** * ******** ** ** a,b,sum1,sum2;
* * * ** * * ***** **** * * * * *** * * ** *
* * ** * * * ** * = a*5;
* * * *** * * ******* = b*5;
* * ** ** * * *** (sum1>40)
* * ** * * *** * * ** ** **** ** *** ** ****** * * Ratio: %d%%\n",sum1);
** * ** * ** * * ** *
** * **** ** * **** ** ** **** * * ** *** *** * ** Ratio: %d%%",sum1);
* *** ** * **** ** * **
* ** ** ****** **** * ** ** * * * * **** ** ** ** * Ratio: * **** * *
* ***** ** ** **** **
* * * ** * * * ** * * *** * * * ***** * * * * * * * *** Ratio: %d%%",sum2);
* ** * *** * * *** * * * * ** 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
**** **** * ** * *
int main(void)
{
** ***** * ** * *** * *** a, b,success, fail ;
** *** * * * * ** **** *** ** **** *** * * ****
** * **** *** ** *** ***** * *
* * * * ** * **** **** * * * ***
* * * * * * * * * ** ** ** * ** Ratio: %g%%\nFail Ratio: * * ** success, fail);
** * **** * *** * * * * 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
* *** ** ** ***



int main() {
**** * * *** * *** **** **** a,b,c;
* ** * * * * * ** * ** *** %d", &a, &b);
** * * ** ** * *** * * * **
** * ****** ** * * * p,f;
*** ** * * * ** **** **
* * ** ** * * * * ** ** *
* ** *** * ** ** * *** p2,f2;
**** ** *** * * * ** * *** **
* *** *** * * ** * ***
* * ** * * * *** * ** * * ** ***** * Ratio: %d%%\n", p2);
**** * **** ***** * ****** ***** Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* ** *** ** ** * * * a,b,sum1,sum2;
*** * **** *** ** * ** * * *** ** * * * ** ** *
* * * ** * * * * ** *** * = a*5;
** ***** * * * ****** * ** ** = b*5;
** * *** * * (sum1>40)
** ** * ** * * * * ** *** * * **** * * ** *** * Ratio: %d%%\n",sum1);
* * *** **** ** **
** *** * ** ****** * * * ** ** * * ********** ** * Ratio: %d%%",sum1);
** **** **** * **** ** * * * * * *
** * **** ** * ** *** **** *** * * **** * ** Ratio: *** *** *
* * ** *** ** * * * ** * **
**** * * * **** * ** * *** * ** * * **** * Ratio: %d%%",sum2);
* * ** * ** * * 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users