3 like 0 dislike
12.5k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.5k views

86 Answers

0 like 0 dislike
Hidden content!
#include ****** *

int main()
{
*** *** * * ** * *** * * x,y;
* * * ** ** * * a=0,b=0;
* * ****** ** ** * * ** * **** *** * **** *
*** * ** ** **** ** * ** * * * * **
* * * * *** ***** ** ** * * **
* * * * * *** ** * ** * * * Ratio: %g%%",a);
* * * * * ******* * * ** ** * ** * *** ** *
**** * ***** * ** ** **** * **** Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include ** ** ** *

int main (void)

{
** ** ** * * * * ** * a,b;
**** * ***** ** ** *** * ** * **** *** ** ****** * ** *
** ** *** *** *** ** ** ** ** ** Ratio: %g%%\nFail Ratio: * * ** ** * * ***** * * *

* ***** ** ** * ** * ** 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * * *** * *

int main() {
******* * * **** ** ** * a,b;
* * * *** ** ******* ** c;
**** * ** * *** **** * ** *** * %d", &a, &b);
** *** * ** * * * ****
* * ****** * * * * * * p,f;
* ** * ** * *** * * *
*** * * * * * * **** *** * **
** *** * *** ***** * ** p2,f2;
* * *** *** **** ** * ** * *
* * *** * * * * ** ** ** ** **
* * * * ** *** * * * ** * ***** Ratio: %d%%\n", p2);
* * ** * ** * *** ** ** ****** * **** Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** * * * *** ****



int main() {
***** *** * * * ** ** a,b;
* ** * * ** *** * * c;
* * * *** * * ** * * * * * * ** * %d", &a, &b);
* ** *** * * * *** ** ** *
* * * * * * * * * * *** * p,f;
** ** ** ***** * *
* ** ** ** ** **** * *
* ** * * *** *** ***** p2,f2;
* * *** ** ****** * *** ** *
** ** * * * ** ******* * *
* ** ** * *** ** * ** * * *** ********* *** Ratio: %d%%\n", p2);
** *** ** * * ** * * ** *** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
* * *** **** * **



int main() {
**** * * * * * *** * * a,b,c;
** ******* * * * ***** * * * * * %d", &a, &b);
*** * ********* *** **
* ** *** * ** ****** p,f;
** * ** * * * *** **
**** **** ** * **** * ** * ** *
*** *** * ****** ** *** p2,f2;
* * **** *** * * * *
****** ** ** * * * ****
*** * **** * * ** * Ratio: %d%%\n", p2);
** * * ** * ** ** ** **** * ** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include ****** *****

int main(void)
{
* * ** * ******** * * ** a,b,sum1,sum2;
* * * * * * * * ** * *** * ** *** * *** * **** * * *
*** * ** * * ******** *** = a*100/(a+b);
* **** *** *** * * * **** = b*100/(a+b);
** * *** * *** *** * ** * * Ratio: * *
***** *** ** ** * **** ** *** Ratio: * ** * * ***

* ** * ** *** *** * ** * 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* ** *** * ****** ** a,b,sum1,sum2;
* * ** * ** * ** **** * ** ** *** ** * * *** *
*** * *** ***** * ** * * = a*5;
* *** * * * * * ** ** ** * = b*5;
* * ** * * *** *** (sum1>40)
*** *** ** * * * ** * * ** * ** * * * **** * ** * * Ratio: %d%%\n",sum1);
* * * * * * * **
**** ** ** * *** * ** **** * * * ***** ***** * ** ** Ratio: %d%%",sum1);
* ***** **** * ** * * * * *****
* * ** ** *** * * * * * ** * *** ** ** * Ratio: * ** **
* * * * * * * ** *
** *** * * * ******* * ******** ** ******* **** * * ** * ** Ratio: %d%%",sum2);
*** * *** ** * * * 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
* **** * *
int main(void)
{
** * * *** * *** a, b,success, fail ;
** * *** **** * * *** ** * * * * *** * * * * * **
* * ****** * ** * * ** ** ***** **
** ** * * ** * ** * * * **** ***
********* ** * * ** ** ** * * Ratio: %g%%\nFail Ratio: * * * success, fail);
* ** *** ** * * ** ** ***** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
* * ** ** ** *



int main() {
*** **** * * * * * a,b,c;
* * ***** * * * ** **** * %d", &a, &b);
**** ** ** ** ** * * ****
*** ** * * *** * * ** p,f;
**** **** * ** * * *** *
* ** * * * ** * ** **
* * * * ** *** p2,f2;
* * * * * ** *
****** *** * *** * **** * * *
*** ** * * ** ** * ** ** Ratio: %d%%\n", p2);
** ****** * * * * * * ** ****** Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* * * ** **** * * a,b,sum1,sum2;
*** *** ** ** ** ** * * * ** * * * ** **** ****
**** * **** *** ** = a*5;
*** * * * *** **** = b*5;
** * * * * *** ** ** (sum1>40)
*** * ** * ******* * ** **** **** * * ** ******** ** Ratio: %d%%\n",sum1);
* **** * **** ****** * ** ***
** *** *** *** * * ********* *** * * ** ***** * * * * * ** *** Ratio: %d%%",sum1);
*** *** * * ** **** * * *** *
** * * * ** * ** ** * ** * ** * ** * * ******* * Ratio: * * *** *
* ** *** **** * ** ***
******** * * ***** * * * **** * * **** * ** Ratio: %d%%",sum2);
** * *** ***** ** * * * 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.82
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users