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請撰寫一個程式,使用者會輸入一行字元,換行字元代表輸入結束,請計算所有的輸入當中有多少個英文字母,多少個數字,以及多少個其他的字元,並依照範例的格數輸出。

Sampile input:

1234567890ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Sample output:

digit:10
alphabet:26
other:13
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 17667 - Available when: Unlimited - Due to: Unlimited

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#include <stdio.h>

#include ** * *** *

#include <ctype.h>



int main()

{
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* *** * * * * 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * ** * * * **

#include ** *



int main()

{
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}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * * ***

#include <ctype.h>



int main()

{
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** ** * *** * ** 0;

}
answered by (-188 points)
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Hidden content!
***** * *** ** *
** * ** ******* * **
* * ** * ** * *

int main()



{
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}
answered by (-110 points)
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Hidden content!
* *** ** * **
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* ************ *

int main()



{
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}
answered by (-110 points)
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Hidden content!
** * * * * * * *
* **** *** ***
* * **** ** * *

int main ( ** ****
* ** * **
* * c ;
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scanf ( * *** * * **** ***
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}

else {
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scanf ( *** * * ** *******
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* * * * ( * * ***** ** ** ,x);

printf ( *** ** * *** *
** * *** *** * * * ***
******** 0;

}
answered by (-304 points)
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Hidden content!
** * * * * * **
* * * * * ****** *
** ** **** ** *

int main ( *
** *
* *** c ;
* * * * * *

scanf ( * * ** ** *** * ** *
***** * ** (c !='\n') ** **



if ( isalpha (c))
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x=x+1;
****

else if ( * (c)){
** * ***** * * ** * **** * * * *** * ** * ***

}

else {
* * * * **
*** *

scanf ( * * * ** * * ** *
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** ** * * ( ****** ** ** ** **** **
* *** ( ** * * * *** * ** ,x);

printf ( * * * **** ******* *
* ** * ** **** *** ** ****
* *** *** 0;

}
answered by (-304 points)
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Hidden content!
* * * * * * *
** * * * ** ** ***
** *** ***** ** *

int main()



{
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****** ** * * *** a=0, b=0, d=0;
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** *** *** ** * ***** 0;

}
answered by (-110 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{

    int a=0,b=0,i=-1;
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}
answered by (-188 points)
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Hidden content!
**** ** * * ** *
* ****** **** * **
*** * *** *

int main (  )
** ***
* c ;
* * * ** * * **


** *** * (c !='\n')  {
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}

else * ** *
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printf ( ******* ** * *
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** * * * 0;

}
answered by (-304 points)
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