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請撰寫一個程式,使用者會輸入一行字元,換行字元代表輸入結束,請計算所有的輸入當中有多少個英文字母,多少個數字,以及多少個其他的字元,並依照範例的格數輸出。

Sampile input:

1234567890ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Sample output:

digit:10
alphabet:26
other:13
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 17667 - Available when: Unlimited - Due to: Unlimited

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#include <stdio.h>

#include * * ** *** **

#include <ctype.h>



int main()

{
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* ******** * * * **** 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * ** * **

#include ** * ** **



int main()

{
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**** * *** * * ***** * 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include * *** * * ****

#include <ctype.h>



int main()

{
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* * ** *** * * x = 0,y = 0,z = 0;
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*** *** * ** 0;

}
answered by (-188 points)
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Hidden content!
** **** *** *** ******* *
** **** * **** * *
* * ***** ****

int main()



{
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}
answered by (-110 points)
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Hidden content!
* *** ***** *
*** *** * * **
* * ** * ***

int main()



{
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}
answered by (-110 points)
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Hidden content!
* * ** *** **** * * *
* * ****** * * *
** ** ** * * **

int main ( * ****
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scanf ( * ** ** *** ** *** ** **
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else {
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scanf ( * **** * * **** *** **
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printf ( ** * ** **** *** **
*** * * ** *** * * *
* ** ** 0;

}
answered by (-304 points)
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Hidden content!
******* ** *** ** **
** * *** ** * ****
* * ** ** ** * *

int main ( *** * **
* ** **
* ******* c ;
** * * * ** ** **

scanf ( * *** *** ******* **
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* ** **

else if ( ** (c)){
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}

else {
* **
*** *

scanf ( **** ** **** *** **
**
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printf ( *** ** ** * **
*** * * * * * ***** ***
* * * * ** 0;

}
answered by (-304 points)
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Hidden content!
* * * *
**** * * * * * * *
* * ***** * **

int main()



{
* * *** * * * c;
* ** ***** * * * * a=0, b=0, d=0;
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*** ***** ** * * *** *** * ("pause");
* * **** * ** * * ** * 0;

}
answered by (-110 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{

    int a=0,b=0,i=-1;
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}
answered by (-188 points)
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Hidden content!
*** ** * ** **
**** * * *** * *
**** * ** ** ** **

int main (  )

** * ** c ;
* * ***** ** * ***


* * * * (c !='\n')  {
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**** *** ( * ** * * * *** * *** ,x);

printf ( * ** ** * *** * *
* ***** ** * **** * ***
** ***** *** * 0;

}
answered by (-304 points)
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