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請撰寫一個程式,使用者會輸入一行字元,換行字元代表輸入結束,請計算所有的輸入當中有多少個英文字母,多少個數字,以及多少個其他的字元,並依照範例的格數輸出。

Sampile input:

1234567890ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Sample output:

digit:10
alphabet:26
other:13
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 17667 - Available when: Unlimited - Due to: Unlimited

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#include <stdio.h>

#include * * ** *

#include <ctype.h>



int main()

{
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*** * * ** * **** 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include *** ** * ** * * *

#include *** *



int main()

{
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**** **** *** * *** 0;

}
answered by (-188 points)
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Hidden content!
#include <stdio.h>

#include *** * * *** ****

#include <ctype.h>



int main()

{
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***** *** *** * * 0;

}
answered by (-188 points)
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Hidden content!
*** * * *** *****
* * ****** *
* * * *** ** * *

int main()



{
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}
answered by (-110 points)
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Hidden content!
**** * * ***
* ** * ***** * *
* *** ** ** *

int main()



{
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**** * *** ** ** ** a=0, b=0, d=0;
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}
answered by (-110 points)
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Hidden content!
* * * *** * * *
* *** * *
** * * * ** **

int main ( * *
* ** *
* * c ;
* * * ** *** ****

scanf ( *** * *** * **** *** * * **
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***

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}

else {
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scanf ( ** * ****** ** *
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* **** ** ( * ** * * * ** ** ** ,x);

printf ( * ** * ****
* * ***** * * * *** * *
** ** *** 0;

}
answered by (-304 points)
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Hidden content!
* ** *** * ** *
** ** * * * * **
** * * ** ** * **

int main ( * *
** ***
*** ******* c ;
* ****** *** ** * ***

scanf ( * * **** ** * **
* ** (c !='\n') ** * * *



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******

x=x+1;
*

else if ( *** ** (c)){
* ******* ****** **** *** * * * * * * ** * **

}

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*** ** **
** * * *

scanf ( ** **** ** * * * * *
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* * * * * ( ** * * * ** * * ****** * ,x);

printf ( * ** * ** **** *
** ** ** *** * ** * ** ***
* *** ** 0;

}
answered by (-304 points)
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Hidden content!
* **** * * **
* *** * * * **
*** ** * **

int main()



{
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* * ** * ** * ****** a=0, b=0, d=0;
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**** ** * *** * if(isalpha(c))
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** * ** * *** * ("pause");
* ** ** * ** *** * 0;

}
answered by (-110 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

#include<ctype.h>

int main()

{

    int a=0,b=0,i=-1;
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** * ** * * * **** 0;

}
answered by (-188 points)
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Hidden content!
** * **** * * * * *
* * * * ** *** **
* * * * * *** **

int main (  )
** * *
** c ;
**** ** * * *** *


** * ** (c !='\n')  {
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}

else ** *
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*** ** ( * * * * * ,x);

printf ( * ***** *** * * * *
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* ** * 0;

}
answered by (-304 points)
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