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請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * * * n = 4, i, j, c;
* ** ******* ** ** k = 0, f;

   int num[n];
** * ** * **** ** * * * * * *** &n);
* * * ** ***** *** *** = 0;i <= n-1;i ++)
**** * ** ** ** * * ** * * ** * **** ******* * &num[i]);
** * **** *** * ** = 0;i <= n-1;i ++)
*** * ** * ** *** *** ** * **** * * * * = i+1;j <= n-1;j ++)
* * * * **** * * * *** * * * * * * ** ** > num[j])
*** ** *** * *** ** ** ** ** * ** * ** * ******* * ** **** ** ***
* * * * **** * ** * * * ********** ** ** ** * *** * * * ** * * ** ** ** = num[i];
*** ** * * * * * * *** ** *** ** **** ** * * * ** ** * * *** * * = num[j];
**** *** * * *** * ** ** * * * * *** ** **** ** * * **** *** *** * ** ** ** * * ** = c;
* *** * * *** ** * **** **** **** *** * *** * * ** ** ** * *** * * * ***
*** ** * ** * * * * *** ** ** != 0)
***** * ** * * ** *** **** * * ** = n/2;
* * * * * *** ** ** * * f = (n+1)/2;
***** *** ***** * * ***** = f-1;i <= f;i ++)
* ** * ** ** ** ** * ** ** *
*** *** * * ** * * **** *** ** ** * * * ** * ***** * ** * = k + num[i];
** * *** * ** * **** * *** * * **** **
** *** * **** * ** = k/2;
* * *** ** * * ** **** **** * *** ** k);


* * * *** * ** 0;

 }
answered by (-188 points)
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Hidden content!
#include<stdio.h>
** ** * *** ***



int main()

{
* * * ** ** **** i,j,k,l;
*** * * * * * ** * *
* ** ** * * **** * ***** ** ** * *


*** * * ** * ** * * *
* ** *** * *** ** n[i];
* ** * * * **** * ** *
* ******* *** *** *** **** * * = 0;k < i;k++)
* * * **** * ** * **** * * * ** ** * * * ** * n[k]);
* * * * ** * * *
** * * *** ** * *
** ** * **** ** * * ** * = 0;
* * * **** * ** ******* * *
**** ******* ** * **** * * = 0;k < i;k++)
* * * ** **** * ***** * *** = l + n[k];

   
** * * * **** * * * m;
* ***** ** ** * ** ** *** = l / i;

   
****** *** ** * ** * *** ** **** **
** *** * * *** * **
* ** *** * * *
* **** ** **** * *** 0;

}
answered by (-264 points)
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Hidden content!
#include<stdio.h>
* * ***** **



int main()

{
*** ** * * *** * * * i,j,k,l;
* * * * ** * ** * *
** ****** *** * * *** * ** ** * * *** *


* ** * * * *** **** *
** * ****** * ** ** * n[i];
* * * * * * * * ** * **
**** * *** ***** * ** = 0;k < i;k++)
* * * ** **** ** * *** * * ** ** * *** * n[k]);
** *********** ** *
* *** * *** ** *** *
* ** * * *** * *** * * * * = 0;
*** * * **** *** * ***
** **** ** * *** *** * ** = 0;k < i;k++)
*** ** * * * * ** = l + n[k];

   
** * * *** *** * * * ** m;
* * * * * * * * = l / i;

   
** *** * * ** **** ** ** * *** ******* *
* * * *** * * * * ** *
** *** * * *** ***** * * * **** * * **
*** ** * * ** *** **** * 0;

}
answered by (-264 points)
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