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請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** * * * n = 4, i, j, c;
**** ** ** * ** * k = 0, f;

   int num[n];
* * * ***** * ** *** * ****** * &n);
* * **** ** *** = 0;i <= n-1;i ++)
** * ** * *** *** * ** * *** *** * * ** *** * * &num[i]);
* * ***** ** * *** * ** = 0;i <= n-1;i ++)
*** ** ** ** **** * **** ** * ** ** *** = i+1;j <= n-1;j ++)
* * * * *** ** * *** * ** ***** ** * * * ***** * > num[j])
* *** ** * *** **** ** * *** ** *** * * ** *** ***** ** * ** **
** * * *** *** * * ** * ** * *** ** ** * * * * * **** * ***** ** * * ** * *** = num[i];
* * * ** *** * ** * ** * * * ** *** ** * **** * * * ***** * * **** ** **** * * ** ** * ** = num[j];
** ** * ** * *********** * ** * ** * * ***** * * ****** *** ** * * *** ***** ** = c;
* * ** * ** ** * * * ** * ** *** *** ** ** ** ** * ** ** *
*** * ** ** ***** **** *** != 0)
*** *** * * ** * ***** *** * * *** * * *** ** * = n/2;
** * * ** * ** **** * * f = (n+1)/2;
** ** *** * * * **** * = f-1;i <= f;i ++)
*** * ** *** * * ** ********** * ** *
* * * * *** * * * **** *** * ** * ** * **** * * = k + num[i];
*** * * ***** ****** * * ** * * *
* * ** ** ** * * * = k/2;
*** ** * * **** ** ** * * * * * * * ** k);


* ** * ** **** * * * * 0;

 }
answered by (-188 points)
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Hidden content!
#include<stdio.h>
**** * ** *** ****



int main()

{
*** * *** ** * * ** i,j,k,l;
* * * ** * * **
** ** ** ** * *** ****** * ** * * * * * *


** ** ** ** * ***** * * * *
*** ********* ** ** * n[i];
* *** * ** ** * * ** *** *
* * **** * ** ** * * = 0;k < i;k++)
*** ** * ** * * ** * * * ** *** n[k]);
** * ** * **** * * * **
* ** ********* * ***** *
** ************ * *** * * ** = 0;
** * * ** * * * ** **
* *** * ****** * * * * = 0;k < i;k++)
** **** ** ** *** * = l + n[k];

   
* * ** *** ** * * ** * m;
* * * ** *** * ** = l / i;

   
* * * *** ** ** ** *** * ********* ** **
* * * *** ****** *** ****
*** * * **** * * *** *
** ** * * * * ** * ** * *** 0;

}
answered by (-264 points)
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Hidden content!
#include<stdio.h>
* **** * **** * * *



int main()

{
**** ** * * **** *** * i,j,k,l;
* * ** *** * **** * * * *
******* * ** ** ** ** * * * * * * **** * *


* *** * * ** * * * **** *
*** ** ** * ** n[i];
** * ***** ** * ** ***
* *** * * ******* * = 0;k < i;k++)
** **** ** *** **** * * * * * n[k]);
** ** ***** * **
* * ** ***** ***
**** ********* * * **** = 0;
** * ******* *** * * **
** ***** **** ** ** ** * * ** = 0;k < i;k++)
** * * * ** = l + n[k];

   
*** ** *** ***** m;
* *** * ** * * ** **** = l / i;

   
* * ***** * **** ** ** ** *** * * **
** * ** ** ****
* **** * ** * * ** * * ** ** ** ** * * ** * * *
* *** * ** * **** * * 0;

}
answered by (-264 points)
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