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請設計一程式,從使用者輸入的數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** * *** * * ** n = 4, i, j, c;
* ** *** * ** *** * k = 0, f;

   int num[n];
* * ** * * *** *** * ** * * * &n);
*** * *** *** * * = 0;i <= n-1;i ++)
** * ***** * ** ** **** * *** ********* ** * * &num[i]);
* * * *** ********* ** = 0;i <= n-1;i ++)
* ** * * ** **** * ** * ** * = i+1;j <= n-1;j ++)
**** * * ** ** ** **** ** ** * ** * ** * ** * > num[j])
* * **** * ***** * *** * * ** * ***** * ** *** * ** ***** * ** * ****
** *** *** * ** **** **** * * ****** ** ** * * * * ***** *** ** *** = num[i];
** *** **** ****** * * * ** ***** * * * * * *** *** * * ** * * *** * **** * ** * = num[j];
* **** * * ** *** * * * * * ****** * ** *** * * * ** * * ** * **** * ** ** ** * * ** * * = c;
* *** * * *** * **** * *** ** ** * **** *** *** * * **** * *
* * * * * ** * * * *** != 0)
**** ** * * ** * *** *** *** = n/2;
** * ** * ** ***** f = (n+1)/2;
*** * * ** **** * = f-1;i <= f;i ++)
** * * * * *** * * ********* **** * ** **
*** * *** ** * ** ** ** ** * ** ** * * * * ** * ** ** **** = k + num[i];
*** * * * ** * * *** * * **** * * ***
** ** * ** ** ** *** ** = k/2;
** ***** ** **** * * ** * *** * ** k);


* * * *** * ** ** * * 0;

 }
answered by (-188 points)
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Hidden content!
#include<stdio.h>
*** ** * *** *****



int main()

{
* ** * ** * ** ** i,j,k,l;
***** * * * ** *
** * * ** * * * ** ** * ** ** * * ** * * **


* ** **** ***** *
** * * * ** ** ** ** n[i];
* * * ** * *** ** * **
* ** **** ** **** ** = 0;k < i;k++)
* ** ** * * * * *** *** * ** * * *** * n[k]);
* **** ** *** **** *** ** *
*** ** * * *** * * *** *
** * * * * * ** = 0;
*** * **** **** ** * * *
** * ** * ** ** ** **** = 0;k < i;k++)
* * ***** * ** **** * ** = l + n[k];

   
* ** * * ** * ** *** m;
* ** **** ** ***** *** * * = l / i;

   
*** * *** * ** * * * * ****** **** *** *
* * ** * * * * **
* * ** * * * ** * **
* * ** *** ** * *** * * 0;

}
answered by (-264 points)
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Hidden content!
#include<stdio.h>
* * * * * ** **



int main()

{
* *** * * * * * i,j,k,l;
** * *** * ** ** ** **
* * * * * * * ** **** * * * ** ***** *****


*** * *** * * ** ** **
** **** * ** **** n[i];
** * ** * *** * * **
* *** * * * ** * * * * = 0;k < i;k++)
* * ** ** * ** * * * *** * ** * *** *** * n[k]);
** * ** ** * ** * * *
*** ** * * ** *** * ** **
* *** * * ** * * * ** = 0;
**** **** * * **
* ** ** ** ** * ***** = 0;k < i;k++)
**** * * *** * **** = l + n[k];

   
* ** ***** ** *** ** * *** *** m;
******* ********* * ** = l / i;

   
*** * * * ** * ** ***** * * * **** ***
*** * *** **** ** ** *
*** ****** ** *** ** * **** * * *** *
* **** ** *** * * * *** * * ** 0;

}
answered by (-264 points)
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