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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
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18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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Oct 27, 2016
by
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* **** * ** * * i=0,
* * * * ** * ** ** *** * * * ** ** ** * *
* ** * *** ** * * ** * *** * * * *** *****
** * * * ** * ** * * * *** *** * * * * ** * *
** * *** * ** * * ** * * * * = i*5/100;
** * * ** **** ** * * * * * * * * * ***** ** * * * * * * *
*** ** * * * *** * = ((i-520000)*12/100)+(520000*5/100);
* * * ** * ** ** *** * * * * * * ** * * ** *** * * * ***
* *** * * * ** *** * * * * * = * * * * ** * * * * * * ** ** ****** *
* * **** * * ** *** * ** * ** * * ** * * ** * * ** * ** * *
** * * * * *** * * = ***** * * * * * * * ** ** * * * * ****
** ** ** * * * * * * * * * * * ** * * * * *
** * * ** * ********** ** = * **** ** * ** *** *** **** *** * * * * * * ** * ** **
** ** ** * ** * * ** * ** ** if(i>=10000001)
** * *** * ****** * * * * * = * * * * ** * ** * *** * * * ** ** * * * * ** * * * **
* ** * * *** * * * * * * * ** * **
** * * * * ** * *** ** * * *** ** ** * *
* * *** * * **** * *** * * ** * 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include <stdio.h>
int main()
{
int money;
* * * * ** * * * ** * * * ** *** * **** * input your money:");
*** * * * ** * ** * * * ** * * * ** * *
*** ** * ** ** * * ** *** ** * * **
* **** ** * ** * * ***** * * * * ** * ** ** ** *** ** * *
* * * * ** * * *
** ** * * * * * * **** * * ** * if(money<=1170000)
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** ** *** * * ** *
* * * * * * * * ** * * if (money<=2350000)
* ** * *** * * * ** * * * * *** * * * * * ** * * *** **** ** *** ** * *
* * * * ****** *** * * if (smoney<=4400000)
*** ** * * * * * ****** * * * *** * * ** * * * * * * * * * ** * * *
** * * * *
* ** * * * * * ** * * ** * * * if (money<=10000000)
* * * ****** * *** * ** *** * ** ** * * * ** ** * * **** * ** **** *******
* ** ** * ** * ** **
* * * * ** * * * * ** if (money>10000000)
** ** **** *** * * ** * ** **** * * * * ** * ** ** * * ** * * * * ** * *
* * ** *** * ** ** ** ** ** * * * *** ***
* * *** * ** * * * ** * ** 0;
}
answered
Oct 27, 2016
by
cityhunter0412
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * ** * ** * * n = 0 , tax = 0 ;
*** * * * ** * * * * ** * ** ** * *
* * * * **** * ** * **
* ** * ** ** * * * * * * * * n <= 520000 )
** ** * * ** * * *
* * ** * ** * * * ** * * * * * ** *** * ** * ** = n * 0.05;
** ** * ** * * ** ** * ** * *** * * * * * * * ** ** * ***** ** **** * * ***
** * * * * **** * * * * *** *** * ** *** *** *** * * ** * * * * ***
* * * * * ** * *** * * ** * ** *** * * ** ** ** * 0;
** ** ** ** * * * * **
* * ** ** ** * * * n <= 1170000 )
* * * * *** * ** **** **
* * ** * *** ** ** * * * * * *** ** ** * ** * * * = 520000*0.05+ (n-520000)*0.12;
*** * *** * * * * * * *** ** * * * * * ** * ** *** ** ** * *** * *
*** * ****** * * ** * ** * ** * * * * ** ** * * ** * * * * *
* ** * * * * * ***** * * *** * ** * * * * * * 0;
*** **** * ** * * * * * * * *
* * *** ** * * * ** * n <=2350000 )
** **** * ** * * ** *
* ** ** * ** * * *** *** * * * * * ** * * ** ** * ** = 520000*0.05+ (1170000-520000)*0.12+ (n-1170000-520000)*0.2;
* * ** * ** *** * * * * * * * ** ** * * * ** * * * * * * *
** * * * * * * * * * ** * ** * ** * **** * * * * * **
* * * * ** * *** ** * * ** * * * * * 0;
* ** ** * * ** * * * * * * *
* * * * ** * * n <= 4400000 )
* * ** * ** * ** * * **
* * * * ** * * ** * *** * * ** * * ** * * ** = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (n-2350000-1170000-520000)*0.3;
* * **** ** * * * * * ** * ** * * ** *** ** * * * * * * * *
* *** * * * * * *** * * * * * * * * *** * * * ** ** * * * * * *
* * * * * * * * * * * * * ** * * ** * * * * * 0;
** *** * * ** * ** *** * * * * *
**** * ** ** * * * * **** * * n <= 10000000 )
** **** * * ** * ** ** * * *
* * * * ** ** * ** * * * ** *** **** **** * ** *** ** = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + (n-4400000-2350000-1170000-520000)*0.4;
*** * **** *** * ** ** * * * *** ***** ** * ** * ** * * * ** * * ** *
* * * * * * * **** * * * ** * * * ** *** * * * ** ** * *
* * * * * * * *** * * * **** * ** * ****** * 0;
* ** * * * **** ***** ** * ***
* **** * * * *** * * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + ** * ** * ** * * ** * * * + * ** ** * * * *** * ** ** ** ** * *
* *** * * * * ** * *** ** * *** * * * * ** ** ***
** * ** ** * * * * * * * * * * * * *
* * * ** * * * * * * 0;
}
answered
Oct 27, 2016
by
Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* *** * * * * * ** * x=0,i=0;
** ** * * * * * ***
* **** * ** ** ** *** * ** * * ** *** ** ** ** ** *
* *** * ** * * * * *
* * * * * ** * *** * ** ** * * * (x<=520000)
*** * * * ** *
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* ** * * ** ** * * * * if(520001<=x<=1170000)
* * *** * * ** * ** *
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** **** ** * * * * *** if(1170001<=x<=2350000)
* * * *** * *** * ** **
* * *** ***** * * * * * * * * *** * *
*** * * * * * ** * * * if(2350001<=x<=4400000)
* * * * * * * ** *** **
* * * * * ** * * ** ** * * * **
* * * * * * * * *
* * ** ** ** * * ***** * ** ** * * if(4400001<=x<=10000000)
* * * *** * * * *
* * * * * * *** ** * * * *
* * * * *** * * * *
** * * * * * ** * ** ** ** ** if(10000001<=x)
* ** * ** * * * * * *
* ** **** * ***** *** * ** ** * ** * *
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*** * * * * **
* * * *** * * ** * * ** ** * *
* ** *** * ** * * 0;
* ** * ** * ** ** * * ***
}
answered
Oct 27, 2016
by
410523005
(
122
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Hidden content!#include * ** * ** * *
#include * **** *****
int main()
{
** *** * *** ** * * ** *** num;
* * * **** * * *** *** * * * * * ** &num);
** * * * ** ** **
** ** ** * *** >= 10000001)
* * * ** ** ** * * * ** *
**** * * ** * * * * *** = * ** * * * * ** * * 0.45;
*** * ** * ** * * ** ** *
* ** * * *** ** * if (num >= 4400001)
* * ** *
* ** ** *** * * * * * * ** * * = * * * ** ** * 0.4;
* **** * * ***** * * ** ****
* ** * ** ** * * * * if (num >= 2350001)
* ** ******* * * *
*** * *** ** * * * * * * *** ** = * * * ** *** * *0.3;
** * * *** * ** *
* * * * * ** * *** * if (num >= 1170001)
* * * * **** *** * * * *
* * * * * * * * ** * = * * * * * * *0.2;
* * ** *
* *** * ** ** ** ** if (num >= 520001)
* * * * ** * ** * *
* * * *** * * * ** * * * * = * ** ** * * * *0.12;
* * * ** * ** **
** ** * * ** if(num >= 0)
** * * * * * *** *
* * *** *** ** ** ** * = num *0.05;
* ** * * * * *
* ** * * * **** * * * * * * * * *
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*** * * * * *** * *** * * ** ** * * *** ** num);
*** ** * ** * * * ** * * * * * * ** *** * * *
* *** * ** * ** ** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include * * ** * * **
#include * * * ** * ** *
int main()
{
* * * * * * * ** * ** num;
** * * ** * * *** ** * * *** * * * **** * &num);
* * * *** * **
*** * * * * * ** * * * * * >= 10000001)
** *** * * * ** *
* ** * * * * ** *** * * * * ** * * *** = * * *** * * ** *** * * 0.45;
** * ** ** * ** * *
* ** * * * ** * if (num >= 4400001)
* * * * ** * * *
*** * * ** ** ** * * ** * ** * ** = * * * * * * * 0.4;
** ** ** ** * **** *
* * **** ** * *** if (num >= 2350001)
** * **** * * * * **
* * * * ** * * * * * * * * * *** = ** * * ** * *0.3;
** * ** * ** * * * * *
** * * ** * * * * * if (num >= 1170001)
** * ** * * **** *
* * *** ** * * * ** **** * ** * = * *** * * * * ** * *0.2;
** * ** *** * *
* * * * * * if (num >= 520001)
* * * * * ** * *
****** ** ** * *** * ** * ** * * = ** * * * * ** * * * *0.12;
* * * * * ** ***
** * * *** * * * if(num >= 0)
* ** ** * *** *
* * * *** * * * * = num *0.05;
* * ***
** *** * * * **** ** * * * *** * ** * *** ***
** * * * *** **** * **
* ** ** *** * ** * * * * * **** * * ** * * num);
** * * * * ** * * **** * * ** * *** *
* * * * ** * ** * **** 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include * * ** * **
#include ** * * ** * *
int main()
{
* ** * * * * **** **** num;
* * * * ** * * * ** * &num);
** * ** * ***
* * * * * * * * * * * * >= 10000001)
** ** * * ** * **
* * * ** ** * * * = * ** * * * * * 0.45;
* * * * ** * * **
*** * * * *** if (num >= 4400001)
** * * * * * * * ** ***
* ** * * *** * * ** * * * = * * * * * *** * 0.4;
** * ** *****
** *** ** * *** ** * * * if (num >= 2350001)
* * ** * *
* ** * ** * ** * * * * * * = * * * * ** **** * *0.3;
**** ** ** *
* ** ** ** * * * if (num >= 1170001)
* * ** * * *** **
* ** * ** * ** ** * * * ** * = * * ** * * * ** *0.2;
* * * * * *** *
** * * * * * * ** * if (num >= 520001)
* ** ** ** *
** * * ** * * ** * * = * *** *** * ** *0.12;
* * * * * *** ** *
* ** * * ** ** * ** * if(num >= 0)
*** * * ** * **
** * * * * * * * * * * = * *** * * ** *0.05;
* ** * *** * ** *
** **** * * * * * * * * * * ** *
** **** * ** ** *
** * * **** * * * * *** * * * ** * ** num);
** **** *** * **** **** *** * ** * * *
** * * ** ** * * * * 0;
}
answered
Oct 27, 2016
by
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Hidden content!#include * * ** *
#include *** * * * *
int main()
{
* ** *** * *** * * * * num;
** * * *** * * ** * * ** * ** &num);
* * * * *** ***
* * ** * * ** * * * * >= 10000001)
* * ** * * * * * *
* * * ** * * * *** ** = * * * * * * * * * 0.45;
* **** ** * * ** *
* * * * * ** if (num >= 4400001)
** ** * * * *
**** * * * ** * * * * * * * * *** = * ***** * * * 0.4;
* * ** ** * ** *
* ** * * ** * * * * ** if (num >= 2350001)
* * **** * * * *
**** * * * ** * * ** **** * * * * ** * = ** *** * * ** * ** *0.3;
** * * * * ** *
** ** * * * * * ** if (num >= 1170001)
* ** * ** * * *
** * * * * * *** * *** * ** ** * = * ** ** * * *0.2;
* * *** * * * * *
* * * * ** ** *** * * * if (num >= 520001)
* ** * * ** ******* **
** ** * * * * * ***** ** * * = ** ** *** * ** * *0.12;
* *** ** *** * * ** ** *
** *** * * * * if(num >= 0)
* ** * ** ** * * *
** ** * ** ** *** * = * * * *0.05;
** * ** *
* ***** * * * * * * *** ** * ** *
* * *** ** * ** * * * * *
* ** * * * * ** ** * * * * ** * ** num);
*** * * ** * * * * * ** * ** * *** * *
** * *** **** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include ** * * * * **
#include * ** * ** * *
int main()
{
* * * * * * num;
* * ** * * ** * ** * * * * *** * &num);
* * **** ** *** ***
* ** * * ** * ** >= 10000001)
* * * * ** * * *
** ** * * * *** * * * = ***** * ** * ** * 0.45;
* * * *
*** * ** * *** *** if (num >= 4400001)
* * * *** ***** *
* * * * *** * * ** * ** *** = ** ** * ** * 0.4;
**** * * * *
** * * * * * * *** * if (num >= 2350001)
* ** * ** *** * * ** *
* * * * ** * * * ** * * = * * * ** *** **** * *0.3;
* * * * ** *** ***
** * * * * * ** * if (num >= 1170001)
* * *** * *** ** * * *
* * * * * *** * * ** * * *** * ** *** = * * ** * * ** ** *0.2;
* * ** ***** ** * * ** ***
* * * * ** ** * if (num >= 520001)
* * ** ** * * * *
* * * ** * * ** * * ** = * * ** ** * *0.12;
* * * ** ** ****
* *** ** * * ** * ** * * * if(num >= 0)
* * *** ** * ** *
** * * * * ** ** ** * * * = **** * ** * *0.05;
* * * * *
** * * * * * * * ** * * *
* * * ** * *** * ** ***
* *** ** * ** * ** * * * * * ** ** num);
* ***** * ** * * **** * ** * * **
* ** * * *** * 0;
}
answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * *** * ** * ** * * * * i=0,
* * * * * ** ** * * * ** * * * *** * * * *
* * * * * *** ** * * * * * * * ** ** * * ** ***
**** ** * * ** ** * * ** **** ** * * * * * *
* ** * ** * ** * * ** = i*5/100;
* * ***** * *** * * *** ** * ** * * ** **** * * * ** *
** * ** * * ** * * * * * *** ** = ((i-520000)*12/100)+(520000*5/100);
* * * ** * * * ** * * * ** ** * * **** * * * * * * * * *
*** **** * * ** *** * * = * * * * * * * ** * *
* * * *** * * ** * * *** * * * **** * ** * *** *** * * * * * **
** * ** * * * *** * * * * = * * * * ** * * ** * * * * *** *
* * * ** ** * ** * * *** * * *** * ** * * * *** ** * * *
** * ** *** *** ** * * * ** = * * * * * * * * * ** * * * * * ** ** ** ** * * *
*** ***** * *** *** * * * ** * * if(i>=10000001)
* *** * ** ** ** * ** *** * *** = * ** * ** ** * ** * ** * * * * * * * * * * * * ** *
* *** * * * *** ** * * ** * *** ** * **** * * *** *** *
* * ** ** * ** ** ** * * * * * * * * *** * *
* * * * *** * ** ** * * * *** 0;
}
answered
Oct 27, 2016
by
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AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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AD 20161027 期中考 9
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15445 -
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[Exercise]
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AD 20161027 期中考 7
[Exercise]
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Oct 27, 2016
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