1 like 0 dislike
3.8k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 3.8k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* * * * ** num,i,j;
** * ** *** * *** * ****** * * *** **
* * * * ** ** * (j=1; j<=num/2+1; j++)
* ** * * * *** * * * *** *
* *** * ** *** * * * ** * * ****** (i=0; i<num/2+1-j; i++)
* ****** *** * ***** ** ** * * *** * * ** ** * ");
** * * * * *** **** ** (i=0; i<(j-1)*2+1; i++)
* **** * ** * ** ** * **** * **** *** * * * * ****
** *** ** ***** ** ***** * ** ** * * *
***** ***** **** *
* *** ** * ** * *** * (j=num-(num/2+1); j>0; j--)
* *** *** * *
** ******* ** * * ** * * * * * (i=0; i<num/2+1-j; i++)
** *** * * * * ** ** * ** ** * * * * ** * * ******* * *** *** ");
** * * ** ******* * *** * *** ** (i=0; i<(j-1)*2+1; i++)
* * **** *** ** ** * **** ** * * * **** ***** *** * * * * ****
** ** * * * * * * ** * * ** ****** ****** *** *** * *
* * ** * * ** ** * ***

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* * * **



int main()

{
* ****** * ** n, j, k;


** * * ***** *** * ******* ** , &n);
* ***** * * * ******** = 1; j <= n / 2 + 1;j ++)
********* * ** ***
* ******** * * * * ** * * *** * * * * ** = 0;k < n / 2 + 1 - j;k ++)
* * * * ** ** * ** * ** *** * ******* ** * ****** * ");
* * **** * * *** *** * * ** * *** **** < (j-1) * 2 + 1;k ++)
* * ** * ** * ** * ** *** ** * * * * * **** *** ** * **
*** * * * * * *** * * *** **** ** * * * **
** ***** * * ***
* ***** * *** = n - (n / 2 + 1); j >= 0;j --)
* * * * * **
* * * * * * * * *** * **** ** = 0;k < n / 2 + 1 - j;k ++)
* ** * * * * * ******** * * **** *** * * * * * * * ");
*** * ** ** ** ** * ***** * ** ** **** ** < (j-1) * 2 + 1;k ++)
* * ** * * * * * * *** ******** ** **** ** *** ** ** *
* ** *** * * * ** ** ** * * ** * ** ** * *
**** **** * *** * *
* * * **** *** 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.190
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.4k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.8k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users