1 like 0 dislike
4.2k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 4.2k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* ** * **** num,i,j;
** ** * * ** * *** **** * ** * ** **** *
** *** **** * * * (j=1; j<=num/2+1; j++)
*** * * * **** * * * *
** * * ******* * ** ** *** (i=0; i<num/2+1-j; i++)
** ** * * ** *** * ** **** ** * ** * ***** * *** * ");
** ** * * * * * **** * *** * ** * (i=0; i<(j-1)*2+1; i++)
* * * * * * *** *** ***** ** * ***** **** * ** * * * ** **
* * ** * * ** * * * **** ** * *** * * * * * * **
* ** ***** * * * ** ***
***** * ***** * * (j=num-(num/2+1); j>0; j--)
*** *** *** * * *** * **
*** ** ***** * ** * **** * * ** (i=0; i<num/2+1-j; i++)
**** * * ***** * ** *** *** *** * *** * * ** * * ** * ");
* * ** *** ** ***** * * **** (i=0; i<(j-1)*2+1; i++)
* * * * ** *** * *** * ** * * * ** ** * * ** * ** * * **
* *** * * ** ** ** **** ***** ** * *** * * ** **
** * * *** ** ** ** *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* ** ** * * *



int main()

{
**** * ** * ** * * * ** * ** n, j, k;


* ** * ** ** ** * ** , &n);
* ** ********** *** = 1; j <= n / 2 + 1;j ++)
****** **** ** **
**** * * * * * * *** ** ** * *** * * ** ** ** = 0;k < n / 2 + 1 - j;k ++)
**** * * ** * ****** * * *** ******* **** * * **** * ");
** * ** *** * * *** **** * ** * * ** * * * < (j-1) * 2 + 1;k ++)
** ** *** ***** ** *** * * * **** ******* ** * * ** ** *
** * ** * * ****** * * *** * * * *** ** ** ** ** * ** ** *** **
**** * * * ** *
* * ** ** ******* *** = n - (n / 2 + 1); j >= 0;j --)
* * *** * ** * * *
* * * *** **** ** ** *** ** * * * ** ** = 0;k < n / 2 + 1 - j;k ++)
* * * * * * *** * ***** ** * * * ** * ****** ");
* *** * * * **** *** * * ** * < (j-1) * 2 + 1;k ++)
* * * ** * ** *** * **** ** ** ***** * * *** * ** *****
***** * * ****** ** ** ** **** ** ** ** * * *** * * *
**** ** * * ****
** *** ** * * 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.192
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.8k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users