1 like 0 dislike
5.3k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 5.3k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
** * ** **** *** num,i,j;
* *** ** * * **** ** ** ** * **
** **** ** ** * (j=1; j<=num/2+1; j++)
* ***** **** ** * ***** *** *
****** ***** ***** * *** * * * (i=0; i<num/2+1-j; i++)
* ** *** *** *** ** * **** * ** * * * ** **** ***** * * **** ");
* ** ** * * *** * ** * *** * * ** *** * (i=0; i<(j-1)*2+1; i++)
*** * * ** **** *** ** * *** * **** ** ** *** * ** ** * *
** * ** *** * *** * *** * * ** * * * ** ** **
* ** ** *** * ***
** *** * * * *** (j=num-(num/2+1); j>0; j--)
* ** ** *** * ** ****** **** *
* * * *** ** ****** ** * (i=0; i<num/2+1-j; i++)
** ** ** ** ****** ** * ***** * **** * * * ***** ");
****** * ** * * * * * **** (i=0; i<(j-1)*2+1; i++)
* ** * * * * *** *** ** ***** * *** ***** * * **** * *** * * * ** *
* * **** * **** ***** ** * * * * ** ** * *
* *** * ** * * * * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
***** *** ****



int main()

{
* * * * * *** * * * n, j, k;


*** * *** ** * *** * * **** , &n);
** * ** ** ** = 1; j <= n / 2 + 1;j ++)
* *** * ** *****
* *** ***** **** ****** * * ** * * **** = 0;k < n / 2 + 1 - j;k ++)
***** ** ** * ** * ****** * * * ** * * ** ** ** * * * ** ");
** * **** * * ** ** *** * * **** * ** * * ** < (j-1) * 2 + 1;k ++)
* *** * * * ****** * ** ** * * * ***** * * * ** **** *** *** ***** *
** * ** ***** **** ** * * * * * *** * ***** *** * * **
*** * * *** **
** ** ***** **** ** = n - (n / 2 + 1); j >= 0;j --)
** * * ******
* * *** *** * * ** ******* * * *** **** = 0;k < n / 2 + 1 - j;k ++)
* * * *** * * ** *** ** ******* * * * * * ** ");
** * ** ** ** **** * **** ** * ** ** *** *** < (j-1) * 2 + 1;k ++)
** * * * * * * ** * ** * **** * * ** * * ** ***** ** ****
* ** ** * * **** * * * ** * * ** ***** ** * * * * * *
* *** ****** *** * *
** * *** **** 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.81
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.9k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.5k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users