1 like 0 dislike
6.1k views
請設計一個程式,利用迴圈輸出文字菱形。

p.s. 輸入皆為奇數

範例輸入1:

5

範例輸出1:

  *

 ***

*****

 ***

  *
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15388 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 6.1k views
0 2
Called for Help
0 0
#include <stdio.h>
#include <stdlib.h>

int main()

{
    int a,n,m,k;
    scanf("%d",&a);
    for(n=1;n<=a;n=n+2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    for(n=a-2;n>0;n=n-2)
    {
        for(k=(a-n)/2;k>0;k--)
        {
            printf(" ");
        }
        for(m=1;m<=n;m=m+1)
        {
            printf("*");
        }
        printf("\n");
    }
    return 0;
}

42 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
**** * * * * num,i,j;
*** * *** * *** *** ****** ** **
* *** * * * *** (j=1; j<=num/2+1; j++)
* *** * * ***** ** * * * *
* ** ** * * * * *** **** *** * * (i=0; i<num/2+1-j; i++)
* ********** * ** * * * ** * * ** ** * *** *** * * ");
* *** *** *** * * * * * * ** (i=0; i<(j-1)*2+1; i++)
* **** ** *** * * ******* ** *** * * * * *** * * *** ****** *
*** *** ********* ** ** ** * *** ** ** * * * *
* * ** *** * ** **
*** ***** ** *** (j=num-(num/2+1); j>0; j--)
** * * *** *** * * * **
*** * ** ** * * * * **** ** (i=0; i<num/2+1-j; i++)
*** * * * ** * * ****** *** ** ** * *** * *** ** *** **** * ");
** ******* ** * * *** * * * * (i=0; i<(j-1)*2+1; i++)
*** ** *** ** * * * * * **** * ** ** * * ** * **
*** ** ** * * * * **** *** * ****** * ** * * *
* **** ** * * * * * * * * *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* * * * ****** * * *



int main()

{
* * * *** * ***** * n, j, k;


* ** ** * * * *** , &n);
** * * * * * ** ** * = 1; j <= n / 2 + 1;j ++)
* * * ** * ** ***
* * * * * * * * * ** * *** * *** = 0;k < n / 2 + 1 - j;k ++)
* * * *** ** ******** * ** * * **** * ** ** * ");
* ** * * ** ***** * * * *** **** * *** * *** ** < (j-1) * 2 + 1;k ++)
* ** * * * * * ***** ** *** **** ** ****** * * * **
** * * ** ** **** *** * **** *** * ** * ** ***** * **
* * * * ****
* ** * *** * = n - (n / 2 + 1); j >= 0;j --)
* ** * ** * * ** *
** *** ** * **** * ** * * ** * **** * ** **** * * = 0;k < n / 2 + 1 - j;k ++)
** ** ************ ** ** * ** ** ** ******** ** ");
*** ****** * ****** ** * **** ** ** * ** * * < (j-1) * 2 + 1;k ++)
** ** * * * *** ******* * * * * ** * **
** *** ** ** **** ** **** *** * **** * *** **
* * ** ** **
** * *** * ******** 0;

}
answered by (-114 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 5.9k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.9k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users