0 like 0 dislike
13.6k views
請設計一個程式,讓使用者輸入兩個正整數a以及b(a <= b),從小到大輸出a到b之間的所有質數。

範例輸入:

1 10

範例輸出:

2 3 5 7
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13617 - Available when: Unlimited - Due to: Unlimited
| 13.6k views
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help

91 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** *** * * x=0,y=0,j,k;
** * * ** **** ** **** *** * ** *** **
** ** * ** * **** * = x;j <= y;j++)
* ** * * * ** **** *
* * * * *** ** ** ** ** * ** **** ** k<j ; k++)
* * * * * **** * ** *** *
* *** * ** ** * * ** * *** * * * ***** % k == 0)
** *** ** * * * ** * * ** * *** * * **
**** * * * * *** * * * * * * ***
* ** * *** * * **** * *** ** * * == j)
** * * * ** **** **** *** ** ** * ** ",j);
* *** * * ** **

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
* * ** ** ***
* * ** ** **



int main *

{
***


** ** * ** ** ** * *
* * ** * **** * * * *


**** ** *** *

{
** ** *** ***

{


** % d == * **



}




* * == d * ***** ** * ** * * *** * * ** * **** *



}




* *** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
** * *** * * *** **



int main()



{
* ***** * * a, b, j, k;
** * ** ****** * * ** *** * * * * * *
** * * ** *** * = a ; j * ** * b; j ++)
* * * ** *
* ***** ** ** ** = 2;k * j;k ++)
* *** ** *
***** * * **** j % k ==0)
**** * * * *
* *** *
***** ** * == j)
*** * ******* ***** *** *
* **




* ** * * ** * 0;
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
* * ** *** ** * ** * *** ** a, b, j, k;
** * * * **** ** ** * ** * * * * * * * &a, &b);


*** * * *** * ** ***** *** * = a; j <= b; j++)
* * * **** * * * *
**** ** * * * * * *** ** * ** ** * ** * = 2; k < j; k++)
*** ** ** * *** ** * ****** * *** * ** * ** **
* *** ** * * * ** * * ** ** * * ** **** ** * ***** ** ***** % k == 0)
** * * * * * * ** * ** * * ** *** * * *** * ** *** * * ***** ** ** * *** ** * *** ** * ** ** **
* **** * *** ** ** ** *** * * * * **
* ** ** ** * ** *** * **** * *** ** * * ** == j)
* * * * * ** * * * * * **** *** * *** **** * ** * *
***** * * ** *** ** *** ******* * **** *** * ** ** * *** * *** * * *** **** ** * * ** * ** * * * ** ", j);
* *** * ** * ** ** * * ****** ** *** ** * * * ** ** **********

    }



return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main() {

    
* *** *** ** * * ** *** a=0;

    int b=0;

    int i,j;

    
* * * * ** ** *** *** ** * *
*** ** * * **** ** * ** ***** * * * * **** * * ** *


*** ** *** ** ** * * **** ** ** * ** *
**** * ***** *** * * ** * * *** * **
**** * ** ***** **** *** * ** *** ** * * * * *
** * * * * * ** * *** * * * ** ** ** ****** * ** * i%j == 0 ){
** *** ** ** * ** ** * ***** * * * ** *** * * ** * ** * *** ** ** * ** *** * *** * *
****** ** ** * *** * * * *** *** ** * * ** ***** * *
* * * ** ** ** ** * ** *** * ** * *
** * ** * * *** *** * ** * *** ***** ** * * **
* *** ** * * * * * ** * * * * * ** ** ** **** ** *** ** * ** ** * ",j);
* *** * ****** * ****** ** ** * * *** *

    }
*** * **** ** ** ** ** ** ** 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
** ** * * * *** **



int main()



{
*** * * ** * * a, b, j, k;
* **** * * * * * * * * * ***** * *** ** ** **
* ** ***** * = a ; j *** * b; j ++)
* ** *****
* ** *** * * = 2;k **** j;k ++)
****** * **
* * * * *** * j % k ==0)
* **** * * *** ****
*** * * *
* ** * ** == j)
* ***** *** * * ** * j);
* ** **




* *** **** *** * * * * 0;

}
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main() {

    
**** * *** ** **** *** a=0;
** * * *** *** ** * b=0;

    int i,j;

    
***** ** **** *** * * * * * ** * ** * * *
* * ** * * * * *** ** ** * * **** * ****


* ***** ** * * ** * * * **
** * *** * * * *** ***** **** ***
* *** *** ** * * **** ** * **** **** *** * **** * **
**** ** ***** ** ** ** ** ***** **** * ** ** * * * *** ** * ** *** * * i%j == 0 ){
* ***** * * *** * ** *** * * *** * *** * **** * * ** * * ** ** *** * ** * *****
** *** * * * ****** ** * * * *** * * * * **** **** **** ** * ** **
* ** * * ** * ** * *** * ** * * * * *
** ** ** * *** ** * *** * * ** * ** ******** ** * **
* * * ** * * * * ** * **** * * * **** * * **** * ** * * * ",j);
* * * ** * ** * * ** ******* * ** *******

    }

    


***** *** * *** ***** * * 0;
answered by (-126 points)
0 like 0 dislike
Hidden content!
* * * * * *** *



int main()



{
* * ** a, b, j, k;
* ** * * **** * * * *** * ** *** ** *** * *
** ** * ** * ** = a ; j b; j ++)
** **** **
** *** * * ** * = 2;k ** * * j;k ++)
* * *** ***
* * ** ** ** j % k ==0)
* * **** ** ** * *
** * * * ***
** * ** ** == j)
* * * *** * ** ** j);
***** **




* **** ** * ** * * ** *** * 0;

}
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** * * * ** ***** * ** ** num1= 0,num2=0 ,k ,wh = 0 ;
*** ** * ****** * * *** ** * * *** * *
* *** * ** ** * *** * * *
** * * * (num1 <= num2)
* * ** **** * *
* * * * * ****** * * * *** * * * * (k=2 ; k<num1 ; k++)
** * * * * **** * * ***** * **
* * * * * * * ** * * * * * **** * * * * ** ** (num1%k == 0)
*** *** *** * ** **** * * ***** * * *** * * ** * ***** * * * * **** ********


* *** * ********** **** ********* * * * ** * **


* * ** ** ** * * * * * ** **** * **** (wh == 0 && num1 > 1)
**** *** **** ** *** ** * * ** ** *** **** * ** ** ",num1);


* * ** * * ** * * ** *** *** *** * * *****


* *** *** * * **** * * *** ** * ** *** * ;
* ** *** **** **
* * ** * * * *** *** *** 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * * *** **

int main()

{
* *** *** ** * n , j ,k = 0;
* *** ********* * ***** * * *


* ** * *** (j = 2;j < n; j ++)
*** ** *** *
* * ** * *** * * *** * ** * * * * % j == 0)
****** ** ** * * * *
*** * * ** * * ** ** ** * * * ******* ** *** = 1;
* * * ** * * * ** * * ***** ** *** * *** ",j);


**** ** * * * * *** **
* * ** *
* ***** ** * * (k == 0 *** * ** * n > 1)
** * * ** * ** * * * * *** *** a prime");


*** * ** ** 0;

}
answered by (43 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.4
©2016-2026

Related questions

0 like 0 dislike
64 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13763 - Available when: Unlimited - Due to: Unlimited
| 9.3k views
0 like 0 dislike
61 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13736 - Available when: Unlimited - Due to: Unlimited
| 9.6k views
0 like 0 dislike
117 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13581 - Available when: Unlimited - Due to: Unlimited
| 15.2k views
1 like 0 dislike
48 answers
[Exercise] Essay (Open question) - asked Nov 2, 2016 in 作業 by Shun-Po (18k points)
ID: 16865 - Available when: Unlimited - Due to: Unlimited
| 9.2k views
0 like 0 dislike
76 answers
[Exercise] Coding (C) - asked Oct 19, 2016 in 作業 by Shun-Po (18k points)
ID: 14120 - Available when: Unlimited - Due to: Unlimited
| 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users