0 like 0 dislike
13.6k views
請設計一個程式,讓使用者輸入兩個正整數a以及b(a <= b),從小到大輸出a到b之間的所有質數。

範例輸入:

1 10

範例輸出:

2 3 5 7
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13617 - Available when: Unlimited - Due to: Unlimited
| 13.6k views
0 0
Called for Help
0 0
Called for Help
0 0
Called for Help

91 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * * * * * ** x=0,y=0,j,k;
* ** *** * * ***** ** * * * * **** ** ** *
**** * ** * ** *** * * = x;j <= y;j++)
* *** ** * * **
* * ** ** * * * ** **** ***** **** k<j ; k++)
* * * ** *** * * **** ** * *
* * ** * * * * ** * * *** * * ** * * * * * *** % k == 0)
*** * ** ***** * * *** * **** * *** *** * ********
* * ** * ** * * ** ** * *
** *** *** * * ** * ** * * * * *** == j)
* **** ** * *** ** * ** ** * * ** * * **** * ",j);
*** ** **** * *** *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
** * ** *** * *
* * **** * * ***



int main ** **

{
*** * ***


** ** * *** * * ** *** *
* * ** ** * ** **


* * ** *** * * *

{
* *** * *** ****

{


***** % d == * ***



}




* == d * ** * *** * *** * * * * * *** *** *** ** **



}




** 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
* ** * ** ****



int main()



{
** * * ** a, b, j, k;
* * * *** * ** * ** * * ** *
* ** *** * = a ; j * * b; j ++)
* *** * * **
* ****** * = 2;k * j;k ++)
* * **
* * * ** ** * * * j % k ==0)
* * ** * ***** **
* *** **** *
* * ** * == j)
** ** * *** ** ** *
*




** ** * * * ** * * 0;
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>



int main()

{
** *** ** * * * * a, b, j, k;
* * ** **** * *** * * *** ** ** &a, &b);


***** *** *** * * = a; j <= b; j++)
****** * *** ** ** ** *
** * ** ** ** * ** * ** * * ** **** *** = 2; k < j; k++)
** * * ******** * ** ** * * ** ***** * **
*** * * ** * **** * * ** *** *** * ** ** ** ** ** * * % k == 0)
* **** * ** * * * * ** * *** * * ** **** *** * * * ** **** * * * ** ** ** * * * *
** ** ** * * * ** * ***** **
** * ***** * ** * * ***** ** * ** * == j)
* *** *** ****** * ** * * * * * *** ** ** * * * **** * * ***
** ** **** * * * * * ** *** * *** * ** * * * * * ** * * ** * ** ** *** ** ** *** * * * * * ", j);
**** ** ** * **** ** * * * * ** * * ** * ******* * *

    }



return 0;

}
answered by (-105 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main() {

    
* *** * * *** *** *** a=0;

    int b=0;

    int i,j;

    
** *** * ** * * * * *** * ** * * *** **
** ** * * ** ** * * * * * * *** ** *** * *


* ** * **** * ** ** ** * *
** *** ** * *** * * * ** ***** *** **** *
* *** ** * * ** * ** * *** * * * **** ******* **** *
* *** ** * * * * * * * ** ** * **** ** ** ** ** * *** * ** * * ** * *** i%j == 0 ){
* * * **** ** * *** ** * * * * ** ** * * * *** * ** ** **** * * ** * * ** *
*** ** * ** ** * **** ** ** ** * * * ** * ** *** * ** ** ***
*** * **** ** * * * ** *** * * * *
** * * * ** ** * ** **** * * ** * * * ** * ** ** **
* *** **** ***** ** ** * ** *** * * ** ** * * * * *** * ******* * ****** **** ",j);
** * *** * ** * ****** ** * ** *** * * * ** **

    }
* ** ** * * ** *** * 0;

}
answered by (-126 points)
0 like 0 dislike
Hidden content!
**** * * * **



int main()



{
* * *** * *** a, b, j, k;
* * * **** **** * ** * * * *** ** * * ** ** * *
* * ** * = a ; j * ** * b; j ++)
* * * * ***
* * ** ***** = 2;k ** * j;k ++)
** ** * **
* ** ********* * *** j % k ==0)
* *** ** * ****
* ** * ** *
* * ** == j)
* ** * *** * * * * j);
** * ***




** * * * ***** **** 0;

}
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main() {

    
*** ** * * * * a=0;
** * *** ** **** * * b=0;

    int i,j;

    
** * **** * * * ** * ** * **** ** * * ** **
* * * **** *** * * * * ****** ** *** * *


* *** ** * ** * ** * *** * * **
* * * ** * *** ** **** ****** *** *
** * ** *** *** ** * * * * ** ** * * * * *** * *
* ****** ** * * ***** * * ** * * * * *** ** *** * * *** * * * i%j == 0 ){
*** ** ** * * * **** * *** *** *** * * * ***** ** ** ***** *** * ** * *** **
* *** * ****** ** ** * ***** * ** * *** *** *** * **
** * * *** * * * ** * *
*** * * * * * ** * * * * ****** *** ***** * * *
* ** ******* **** * * * * ** **** * ** ** *** * ** * *** ** *** * * * * * * ",j);
** ** * ** ** ** * ** * **** * ** ***

    }

    


* ***** *** ******* *** * * * ** 0;
answered by (-126 points)
0 like 0 dislike
Hidden content!
* ** *** *** * *



int main()



{
** *** * a, b, j, k;
* ** *** * * * ** **** * * **** **
** * ** * = a ; j * ** b; j ++)
**** * *****
* ***** *** *** * = 2;k ** j;k ++)
* * *
** *** ** * *** j % k ==0)
* * * * ** ** * * *
** **** * * *
* * ** ** == j)
** ** *** ** ** * *** * j);
** * *




***** * **** **** 0;

}
answered by (-24 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** * *** * * ** ** ** num1= 0,num2=0 ,k ,wh = 0 ;
*** * *** * * *** * * * * * * * **** * *
** * * ***** ** **** * * ****** * ** ** **
* * * ** * *** * (num1 <= num2)
** *** ** * *
** ** **** **** * * * ****** * ** (k=2 ; k<num1 ; k++)
* * **** * * * *** * * ****** ** * * ***
* ******** ** * * * * * * *** * ** ***** * ** *** ** ** ** ** (num1%k == 0)
* **** *** * * * * ** ** * * * ** * * * * ** * ** * * * *


** * * * * * ** * * * * ** ***** ** * ** * * * *


* ** ** * ** ** *** *** * *** * *** (wh == 0 && num1 > 1)
* * *** * * *** * * *** * * * ** * ** * ********* ** * ",num1);


** ** * * * * * * ****** ** *** * * ** ** **


***** * * * * * ** * * * ** * * ** * ** * **** ;
**** ** * **
* *** * * * ** * * ** 0 ;



}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ***** * **

int main()

{
* ** * * **** n , j ,k = 0;
** *** * * * * * ***** * **


* ***** ***** * (j = 2;j < n; j ++)
*** * **** *
* *** ** * * *** * * * % j == 0)
* **** ** * ** ** * **
* * ** * ** * ***** **** ** *** * * * * * = 1;
** ** **** * * * * ** * * * ** *** ****** *** *** **** * ",j);


** ** ** *** *** ** * * *
***** **** * *
***** * * (k == 0 * * *** *** n > 1)
* ** *** *** * **** * * * ** * a prime");


** *** ** 0;

}
answered by (43 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.5
©2016-2026

Related questions

0 like 0 dislike
64 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13763 - Available when: Unlimited - Due to: Unlimited
| 9.3k views
0 like 0 dislike
61 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13736 - Available when: Unlimited - Due to: Unlimited
| 9.6k views
0 like 0 dislike
117 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13581 - Available when: Unlimited - Due to: Unlimited
| 15.2k views
1 like 0 dislike
48 answers
[Exercise] Essay (Open question) - asked Nov 2, 2016 in 作業 by Shun-Po (18k points)
ID: 16865 - Available when: Unlimited - Due to: Unlimited
| 9.2k views
0 like 0 dislike
76 answers
[Exercise] Coding (C) - asked Oct 19, 2016 in 作業 by Shun-Po (18k points)
ID: 14120 - Available when: Unlimited - Due to: Unlimited
| 12.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users