0 like 0 dislike
5.6k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 5.6k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * *** *

main()

{
* * ***** * i,a,b,c;
* ** * ****** * * * ** *
** * * ** ** * * * **** ****

{
* ** * **** *** * * * ** *

{
* ***** *** * ** * *** * ");

}
* * * ** ** ** * * *

{
* ** * ** * ** * ** *

{
* * ** * * * ***** ** * * ** *

}

}
** * * * * ** * ** ** ** * ** *



}


* * * * ** * ** * * * ** *** **
* * * ** ***** *** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * * *** * **** *** * * * *** * &num);
** **** **** * * ** i = 1;i <= num;i=i+2)

   {
* * ** * * ** ** * ** * * ** * *** *** ");
* ** ** *** * * * ** * * * * ** * ***** *** \n");
** * ** *** **** ** * * ***** * * * k =1;k<=num-(i/2);k++)
* ** ***** ******* ****** * ****** * ** * * ****
* * * ** * * * * * * * ** * *** * ******* ** ** ***** *** * ");
*** * * * ** **** * ** * *** ******* ** *
* * * * * ** *** *** ** * ** * * ** *** ** *** * **** *** *
* * ** ** *** * ** **** *** * ** ** *** j = 1;j <= i;j++)
******* *** * * ** ** * **** ** ***** **
* * * *** * ** *** * **** * * * * *** ** ** ******* *** * * ** ***  
***** * *** * * **** * * **** **** ***** * * * *** *** ** * * * ** * * *** ** * * ** * * ** ******** ** *** * * * * ***** ** ** * * ** * ** *** * * * * * ** *
* *** * * * ****

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* ** * ** * ******* a, b, i;
* ** * * * ** * **** * * *** * ********
* ** ****** * **** **** **** **** * **
*** * * ** * ** **** *
*** *** * * **** * * **** *** * * * *** * * **** * *** *
* ** * ** * * * ** * ** * ** *** ***** * * ** ");
* ** ****** ***** ** * ** * ** * * *** * * * *** *
* * * ** * * * * ** *** * * * **** * ** ** **** * *** ** ** ** *
***** * *** ** * ** * * * **** * ***** ** ****** **** * *
* *** * * ***** *** * ***
* *** * ****** * * * * *** * * *
** * * ** ** *** * * 0;
*** * * ** *******
* * *** *** * **** *
** *** * * * *** **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** * * * *** * * *
* ** ** * * ** * ***



int * *

{
* a, j, k;
**** * * ** * * * *
** = 1;j *** a / 2 + 1;j ++)

{
** **** * ** ***** *** *** = 0;k *** a / 2 - j +1;k ++)
** ******* ** * *** *** *** * * ** * ***** **
* ** * ** ** * * ** * ** ***** = 0;k * * * * 2 + 1 ;k ++)
*** ** * ** * * *** * * ** * * *
* ******* * * *** * * ** * ** * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * * * * *

#include *** *** ** * *



int main()

{
* **** ** * *** x,y,z;
* ** * * * * ******* * * * * * * * * **
* * * * * * * * ** ** = 1;x <= (z+1)/2;x ++)
** *** * * ****
** *** * *** **** * ** ****** **** ** = 1;y <= (z+1)/2 - x;y ++)
* ** * ** ** ** * ** ** * **** ** **** ** * * * * ** ");
* ** * ** * * * * ** * * * ** = 1;y <= (x*2)-1 ;y ++)
** * * ***** ** *** * *** * * ** ** ** ******** * * *
** ***** ****** ** * ** * * ** * * * ** * ** * *
** **** * * **


*** ** ** ***** * ** * * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * * ***

#include * * *** * *



int main()

{

int a, j, k;
** * * * **** ***
* ** / 2+1; j++)

{
***** * * * ** **** * *** ** a/2 -j +1;k++)
****** * * * ******** * * * * ** * * **
* * * *** **** ** ** * * ***
* *** ** ***** **** *** ** *** *** ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * ** * *** *** *** * *** **** ** * * * * ******** *** * ** * ** **** * * * * *** ** * * **** * *** ** * * ****
* * * ** * ***** * ** *** * ** ** ** ** ** * ** *** ** * * * ** * ** ****** * * ** ** *** * *** * ** * * * ** * **
* * * * * ** * * ** ** ******* **** ** ** **** *** * *** *** ***** * * ** *** *** *** ** * * *** * * ");
* * * ************ ** ***** * *** * * * *** * * ** * * * ****** ** * * **** * * * * ** * ** * ** **** ** * *** **** *
* *** * *** *** ******* * * * * * ** *** **** * ** ** *** * *** * * * ** **** ** * * ** ** * * ** ** ******** * *** * ***** ** ********
* *** * * * * * *** ** * ** ** *** * * *** * *** ** * ** * * * * ** *** **** * * *** * * * * ****** * ** *
* * ** * *** * * ** *** * * * * ** * *** * **** ** ** * **** * *** * *** ***** **** * **** ** * ** *** *** * * **** ** ** **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * *** * ***

#include * *** *** * **



int main()

{
* * **** * * ** * num, n, p;
* ** ** **** * * * ** * * ** * &num);
*** ** * ** ** * ** * * (n = 0; (2 * n) + 1 <= num; n++)
** * ** ** *** * * * ** *
* ** **** * * ** * * *** * **** ** * * * (p = 0; p <= (num / 2) - n - 1; p++)
* *** ******** *** * *** * ** ** * * ** * * * * *** *** *** ** ");
* *** * * * ** * * *** * * **** * ** (p = 0; p <= (n*2); p++)
* ** * **** * ** * *********** * * ** ** * * * * *** ** ** * *
** *** * * * * ** ** * ** ** *** * * *** * * ** * *
* ****** ** ** *


***** * ** * **** * * * * *** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** * ***** ** **



int main()

{
** ** *** * * ** * * ** a, b, c;
** ** * *** *** *** * ** * ** * * **** ***** ****
** * ** ** * ***** ** c <= a; c+=2)
* *** * ** * * ******
**** **** ** * ** * ** * **** b <= (a-c)/2; b++)
** ** * * ** * * * * ***** * * * * * * ");
* * * * **** ** ***** * *** * b <= c; b++)
** ** * * ** *** ** **** ** *** ** ** *** * * ** ** * * ** *
* *** ** * * * *** **** *** * ** * *
** * * ** * * ** * *
* ** * ******* ** * * * ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * ** * ** * * * *** a ;
** ** * ** ** ** ** *** i , j ;

    
* * * *** ** ** ***** ** * * ** ***** &a);


* * *** * ** * ** * *****

    {
** *** * * ****** ** ** *** * ****
* * * * ***** * * ** ** * * ** * * **** * ***
* ** ********* ** ** * *** * *
** * **** * * ** * ****** ** **** * ** ");  
* * ***** * ***** * * * * *
** * * * * * *** * * ********* * ** *** * * * * * * * * * * **** ** ** ** ** * * *** * ** *** * **** ** * ** ** *
* *** * * *** * ******** * * ** * **
** * * *** ** ** ******* ***** *** * * *** * * **** * * **** *** * * * * * * ** ** ** * * * * ** * * * *** ** *** * ** ***** * * * * ** * ******* * ** ** ***** ** *** * *** * ** * * ** * ***** * * ***** * ** * ****** ***** * ***
************** * * ** * * ******


* **** * * ** ** *** *** * ** ***
** * **** ** ***** * * * ** * ** ** * ** * *** * ** *

    }

   

    
* *** ***** * * * * ** * *** * ***
**** *** ** ******* * *** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.82
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.3k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 4.9k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 6.5k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users