0 like 0 dislike
3.5k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** *** ** * ***

main()

{
**** * * * ** *** i,a,b,c;
* *** * *** * * * ** ** * * * * * ** * ***
** ***** * * * * * * * **

{
**** * ** * *** ** *** ******* * *

{
*** **** * * ** ** * ");

}
*** *** ** ** * *

{
* * * * *** **** *** *

{
***** * ** *** ***** ****** **

}

}
* ** ** * ** ** * * * ** * **



}


* * * * ** * ** *** * ** * *
** * ** ** * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* ** * **** * * * * * ** ** &num);
***** *** * ** ** ******** i = 1;i <= num;i=i+2)

   {
* * * * * * ** ** *** * * **** **** * ");
* * * * * ** **** * ** * * *** * ** \n");
* ** * *** * * ** ** * ** * ** * ** * * **** * k =1;k<=num-(i/2);k++)
*** *** * ** ** *** ** *** * * ** *
* * * ** * * ** * * * ******* * * ** * * * ** ***** *** ");
* * ** * ** * * * ** ** * ****
** * * *** * **** * * ** ***** *** ****** * ** **** ** ** **** ** *
* * **** ** ****** * * * ***** **** * j = 1;j <= i;j++)
** ** **** ** *** *** * ** *** ** ** **
***** * * *** ** * **** ** ** * * * * *** ** ** * * * ** ** * *** * * * *  
* *** * * ** ** * ** **** * ** * *** ** * *** **** * *** *** * ** * * * ** ** * *** *** ** ** **** * ** * * *** * ** *** * * * **** *** ** * ** ** *** * ** * ** *
* **** * *** *** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* * * ** ** ** a, b, i;
* ***** * * ** ** * ** * ** ** ** ** ** * * ** **
* * ** * ** * ** ** * ** *** * * ** * *
** ** ** ***** * *
* ** * *** * * * * * * * * *** * * ** *** ** ***
*** *** * ** ** * * **** *** *** * * ****** ** ** ** ");
****** * ** ** **** * * * * * * * *** * * ** ** ** ***
* ** * *** ***** * * *** ** * ** *** * ** ******* * ** * * ****
*** * ***** *** * ** * ** * ** * * * * *** * ** * **
* * * * * * * *** **
***** * * * **** * *****
** * * ** *** * * * 0;
** * ** ** *** **** *
* ** * ** *** *
*** * * * ** ******** **

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
*** * * *** ** *
* * * * ** * * *



int * *

{
** a, j, k;
** ***** ** *** * * * * **
*** = 1;j ** a / 2 + 1;j ++)

{
*** * *** * *** *** * = 0;k * * a / 2 - j +1;k ++)
****** * *** * * ***** * * * *
* ** ** **** *** ** * ** = 0;k ** * *** * 2 + 1 ;k ++)
** * ** * * ** *** ***** *** * ** * ** *
******* * ** ** *** ** ** * * ** * * *** ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include ** **** * * * *

#include * **** * *



int main()

{
* * *** *** ** * * ** x,y,z;
** * ***** * * ** ** ** ** * *** *
***** ** ** * = 1;x <= (z+1)/2;x ++)
* **** * * * *
** * ** ** * ** * ** ** * * * = 1;y <= (z+1)/2 - x;y ++)
* * ** * ** ** * * * ******* * * ** ** *** ***** ** ");
* * * ** ** * ** ** ** ** * ****** * = 1;y <= (x*2)-1 ;y ++)
*** ** * * ** * ** * * ** * * *** * * **** * ** * *****
* * ***** *** * * * * * ** * ** * *******
** * * * *******


** ** ** * * * * ****** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * *** *

#include * * *** **



int main()

{

int a, j, k;
* ** ** * ** * **** **** *
* ****** * *** * / 2+1; j++)

{
* ** *** ** **** *** ** * a/2 -j +1;k++)
** *** *** ***** ** *** * * * ** *
* * * * * * ***** ** ** ** * * ***
* * * ** ** * * *** *** * *** * * *** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
** **** * ** ** * *** * ** * * * *** * *** * * *** ** * * * * * * ** * ** * * ** ** * ** ** ***
***** ** * ** * * **** * ** *** * * ** ***** * ** * ******** ** *** * *** * * ** ***** * * * * * *** * * * ** * * ** ** * ***
** * ** * ** * * * **** ****** ** * * * ** ***** ** ** *** * ** ***** * * *** * ** ** * * * * ***** * *** * * ");
* * * *** * ** ****** ** ** *** * * * * ** * ******* ******* ** *** ** * ** ** * **** * * * * ** **** **** * * ****** * **
*** * * ****** * * **** ** ****** **** **** * **** *** **** * * ****** **** * ** * ** * *** * ** ****** ** ** ** **** * **** *******
* * * ** ** ************* ** **** ** **** * * *** ****** **** ** * **** **** * * * * ** ** ** * **** ***** * ** *** * *** ** **
* * ** ** ** * ** **** *** * * * ** * * * **** * *** *** * * * * ***** ***** * * ** ** ** ** * *** * ** * ** **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include ***** *** * *

#include ****** *** *



int main()

{
* * ** *** * * * * *** num, n, p;
** * * *** ** * * ** * ** ***** * &num);
*** **** * * * **** (n = 0; (2 * n) + 1 <= num; n++)
* * **** ** * **** *
**** ** ** ** *** * *********** *** *** ** *** **** (p = 0; p <= (num / 2) - n - 1; p++)
* ************** *** * *** ** **** *** * *** * *** *** ** *** ** * ***** ");
* **** *** ** *** ** * **** ** * *** * (p = 0; p <= (n*2); p++)
* **** *** * * *** * * * * * * * * * *** * ** ***** * *** *** * ** * *** * *
* * *** * ** * *** ** *** * * * * ** * * **** * *** **
* *** ** ** *** ** ** * *


* * *** * * * * ** * * * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ** * *** * ****



int main()

{
** *** * ** *** * ** ** a, b, c;
* * * * *** * ** * * ******** * * * **
* * *** ***** *** * ** *** * * c <= a; c+=2)
* * * ** ** * * ** *
* ******* * * * ** * * * ** * * b <= (a-c)/2; b++)
*** * *** *** * * * ** * ** * * * *** * * ");
******** * ** * *** *** * ** * * * b <= c; b++)
*** * * ** * ** * * ** **** * ** * ** **** * *** **
**** ** * ** * **** * ** *** * * **
**** * ** * * ****** * ** * * *
* ** * * * * *** ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * ** * * * ** **** a ;
* ** ***** ** * * *** i , j ;

    
* * * * ** * ****** * * * ** ** * * &a);


*** * * ***** ** ***** ** *** *

    {
* ** * *** * * * *** *** *
*** *** *** *** *** * * * ** **** * * ** * *
** ** * ** ** *** ** * **
* ****** * *** * * * * * **** ** *** ** *** ** * *** * * * ");  
** *** ** * * ** * * * * *
** * ** * *** ** * ** * * ** ** **** * * * ** **** * * * * * ** *** * ** ** * *** * *** * *** *
* * ** * * ***** ** ***** * **
* ** * ** ***** ** **** * * * **** *** * ** * * * * * *** * ** *** * *** ** * **** *** * * *** ** *** ** * ** * ** * ** * ** * ** **** * * ** ** ** * * ***** *** *** *** *** * ******* * * ** * * * * * *
** * * * * * **** * * *** * ****


**** *** ** ** *** * *
* **** **** * * **** **** ** * ** * ** * * * ***

    }

   

    
** ****** **** ** * ** ** ** *** ** ** ***
* * * * *** * * *** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.131
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 3.1k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users