0 like 0 dislike
3.5k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * *** *

main()

{
** ** * ** **** i,a,b,c;
*** * *** **** ** **** ** * **** *** ** *
* *** * * ** ** * ****** **

{
**** * ** ** ***** ** * * ***

{
* ***** * * * * * * ");

}
* * * * * *** ** *

{
** * ** * ** * * ******

{
* * * ** ** ** ** ** ** ** **

}

}
* * * *** ** ** * ** * *



}


* *** ** *** ** * * * ** * * * * ****
* ** * ** * *** * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
** ***** * * * ***** ** &num);
* * * *** ** * * i = 1;i <= num;i=i+2)

   {
** * * * *** * * ** * *** * ** *** * *** * ** ");
** *** * **** ***** * * ** * * * ** ** * ** * * * \n");
** * *** * ** ** ** ** ** * ** k =1;k<=num-(i/2);k++)
*** ** * *** *** *** ** * * ** **
** * ** *** * * **** ***** * * *** * * * ** * * ** ** * ** *** ** ");
** ** *** ** * **** ** * * ** **** * *
**** * * * * * ***** *** * * * * * * ***** * **** * ** *** *
* * * * * ** **** *** *** *** ** * * j = 1;j <= i;j++)
* ** * * * * * ** * * **** **** ** * **
*** * **** * * * *** * * * * *** *** * * ** * * * * * ****** * * * * * *  
* * ***** *** * * * * **** **** **** * * *** * * * * ** ** * * *** * * * ** * ** * *** *** * ** ** *** * ** *** * *** * *** * ** * ** ** **** ** * * **** **** ** ** * * * * * *** *
**** ****** * * **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* *** * ** * * *** a, b, i;
* * *** ** ***** * * * * * *** ** ** ** * ** *
** * * **** * *** ** * **** * *** **
** *** * * * * * *
*** *** * * * * * ** ** * ** ***** ** * **** * * * * *** *
* * * ****** *** * ****** *** * * * ** ** * * ** ");
**** ** ** ****** ** ** ********* * * * * ** * *** * **** * **
****** * * ** ****** * * * * * ****** * * ** * ** * * * *
* ** ** ** ** *** ** * * * * ** *** ** * **** * *** * *** ** * * * * *
** * ** * ** **** *
** ** * ** *** *** * * *** ** * ** ** *
** ** * *** * ** * ** ** * 0;
* ** * * *** **
*** *** ** ** *** * **
*** * **** * * * *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
** * * ** **** *
* ** * ***** *** ** *



int * *

{
* a, j, k;
** ****** ** ** * ** *
*** = 1;j * ** a / 2 + 1;j ++)

{
** * ** *** * ** = 0;k * * * a / 2 - j +1;k ++)
* * *** ******** * ** * * ** * **
*** * * * * ** * = 0;k * * * 2 + 1 ;k ++)
** ****** ** *** * ***** * * * *** * * *
* **** * *** * ******* * * ** **

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * ** *

#include * * * *** *



int main()

{
** * * * **** x,y,z;
* ** ** *** * ** ** **** * *** ** * *
* ** * * ** * * * * * = 1;x <= (z+1)/2;x ++)
* ** **** * * * **
* * * * **** ** ***** ** * **** * ** = 1;y <= (z+1)/2 - x;y ++)
* * **** ** *** ** ** ** ** * *** **** ** * ** * * **** * ");
*** ** ** **** * * ** **** * ** * ** ** = 1;y <= (x*2)-1 ;y ++)
** * * *** ******* ******* *** * * ***** * * ** * ******* *
* * * *** ***** *** * *** ********* * * * * ** *
** * * ** ** * *


* * * ** * * * ** * 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * * * *** *** *

#include * *** ** *



int main()

{

int a, j, k;
* * *** * * * * *
* ** ** ** / 2+1; j++)

{
* * ** *** * * * **** ** ** ** * a/2 -j +1;k++)
* * *** **** * ** * * * * * * **** * * *
*** *** * ** ** ** * *** * * * ** ** * *
* ** * *** * ** ***** * * * **** ****

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
** **** *** * * *** **** * *** * ** *** ** ** ** **** * *** * ***** **** ** * ** * ** ** ** *
* ** *** * *** * ***** * * ** * ** ** ****** **** ** * * **** ** * ** ** ** * * * * ** * ** * * * *** ****** *** *** **
** * * ** ** ** ** ** ** **** * ***** *** *** * ** * ** ** * **** * * * * **** **** *** ** * * * ** * * * ** ** ** **** * ");
** * ** **** * * * * **** *** ***** * * ** *** ** ** * * ** **** * * **** **** ** ** ** * **** ** * ** ***** **** * * **** ****** **** *
* ******** ** ** * ***** ** ** * ** * *** * * ** ** ** ** ******** ** * * * * *** *** * ** * **** * **** * * ***** * ** *
** * * * * * * * * * *** *** ** * ** * ** * * **** **** ** * ** ** * ** * *** ***** * * * ** ************* ** * * * * *** **** * **
**** * *** * ** ****** * ********* * * ***** * * *** **** * * * * * * * * * ** * * *** * * * ** * ** **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * * **

#include *** ** *



int main()

{
**** ** ** * * ** * * * * * num, n, p;
** * ** * * ** ** * ** *** * ** * * &num);
***** ** *** * * * *** (n = 0; (2 * n) + 1 <= num; n++)
**** ** * * * ** *
* * ** * *** ** **** **** **** *** **** ** * * ** (p = 0; p <= (num / 2) - n - 1; p++)
* ** ***** ** *** * * **** * * ** * ** *** ** * * ** * ** *** ** ");
** *** * * ** * * * * **** * ** (p = 0; p <= (n*2); p++)
** ******* * **** * **** * * ***** * ** ** ** **** * * *** * * ** * ** ** *** *
* **** *** * * * *** **** *** * ** **** **** ***
*** * ** ** ** * * * *


* ** * * * * *** * ** * 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * * ** **



int main()

{
* * * ** ***** * * a, b, c;
** * *** * * ** **** * * * ** ** ** * ***
** ******** **** ** * ** ** * * * c <= a; c+=2)
* ** * ***** ** * *
** ** **** * *** * * * ****** * ** b <= (a-c)/2; b++)
* * *** **** * *** * ** ** ** * ***** ** ");
** ****** * * ** ****** * ** * b <= c; b++)
***** * * ** **** * **** * ***** * * * * * ******
* * * *** * *** *** * * ** ** *** * * * *
* **** * ** ** ** *
*** ** ** * * *** * * ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* ** ** **** ** * **** a ;
***** ** * ** i , j ;

    
* ** ** * **** * *** ** ** **** ** &a);


** * ** * * ** * **** *

    {
***** * *** ***** ** * *
* **** * * ******** * * * ***** * *** *
** * ** ** ** * * * * ** ** *
*** **** * * ***** * *** * ** *** ** *** * * ");  
*** *** * ** * *** * * ** ** ** *
** * ** ** * ** ** **** * ** ***** * ** * * * ** * ***** * * * ** **** * * *** ** * ** * ** ** * * **
*** ** ** ** ** * * * ** * **
* **** * ** * ***** ** ** ** * ** **** * ********* * * ** ** ** * ** *** *** * ** * ** * ** * * * **** * * * * ** ** **** *** * * ******** *** ** * ***** ***** * * * ** ** ** * * *** *** * **** * ** ** * **** ******* ** * * *
*** *** * * ** * *** * * * **** * *** *


* * * ** **** ** * * ** *** **
* **** * *** * * ** * * * * *** **** * **** * * * *

    }

   

    
* * *** * ** **** * ** ** **
*** * * * * * ******* * * *** 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.154
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 4.4k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 3.1k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 4.1k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users