0 like 0 dislike
5.2k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 5.2k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * *

main()

{
* * *** * *** * * i,a,b,c;
* *** ******* *** ** * * * * * * * *
* ** * * ** ** * * *** ***

{
* * ** * ** ** * * * ** ** ** * *

{
* ** * ** * ** ***** * ** ");

}
* **** *** ******* *

{
* ** *** *** * ** * *

{
* * * * * ** * * ***** **** * *

}

}
* **** ** * ******* * * *



}


* ****** * *** * * ** * **
** ** * ** * * 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* ** ** **** **** * * ** **** &num);
** * ** * * i = 1;i <= num;i=i+2)

   {
* ** ** * * * ** * ** ** * * * *** * * ** * ");
**** ** * * * * * ** * *** * ** * ******* * \n");
*** * ** ****** ** * * * * * * * *** k =1;k<=num-(i/2);k++)
****** * ******* *** *** *** * * * **
* * ****** * *** * * * * ********** ** ** ** * ** ** ** *** * ** ");
** *** * * * ** * * ***** *
* * ** ** *** ** **** ***** **** * *** * **** ** ** * *
**** * ** * ** * * ** * * * ** * ******* * j = 1;j <= i;j++)
* ********** * * *** * * ** *** *
* *** * ** ** ** * ******* * **** **** * * * * ** ***** * **** ** **  
** ** *** *** ** * * ** **** *** ** ** ** ** * * * **** ** * * * * * **** * * * ** * ** **** **** *** ** * * * **** * ****** * *** *** **** * * * ***** * * * * ***
* *** *** *** * * * *

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* *** ** * * ** * a, b, i;
* * * * ** ** * ** * * * ** ** * *
** ** * ******* * ** * *** *** *
** * * * * * ** * *
*** * ** * * ** *** * ** ** * * **** * *** ** ** ** ** * * * *
** * *** **** * **** * *** * * * **** ** * * * ");
* * * *** *** * ** **** ** **** * ***** * * * ** **
** * ** * ** ******* ** ** ******* * * ** *** *** * ***** ** *
* * **** * * *** * ** ** ** * * ** ** * * * **
* * ** * ** * * *
*** * * *** ** ** * ** * *** ** * ***
** *** ** * *** * *** ** *** * **** 0;
* ** ** **** * ****
** * **** *** * * * *
* * **** * *** *

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* * * ** *
* **** ***** *



int **

{
* a, j, k;
** * * * *** * *
* * = 1;j * * * a / 2 + 1;j ++)

{
** * *** * ** *** * * * * = 0;k * * ** a / 2 - j +1;k ++)
* * **** ** ** * * * * * * *
* ** * * ** * ** ***** * = 0;k * * * * 2 + 1 ;k ++)
* * **** * ** * ** **** ** * **** *** *
* * * * * * *** * ** ** ** *** * ** *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include *** * *

#include * ** * * **



int main()

{
* *** * ** ** * * x,y,z;
* * * * ** * *** * ** *
* *** * * * ** *** * = 1;x <= (z+1)/2;x ++)
*** ** * **** * ** * *
** * * * * *** * *** *** * * ** * ** = 1;y <= (z+1)/2 - x;y ++)
* ** * * ** * * *** * * ** **** ** *** *** ");
** ****** * ***** * * ** ** *** * * = 1;y <= (x*2)-1 ;y ++)
** * *** *** * * * * * ** ******** * ** *** **** * * * * **
* * ******* *** *** *** * ** *** ** **
* * * **** * ** *


* ** * ** * ** ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include * * * * **

#include **** * ***** *



int main()

{

int a, j, k;
* *** ** **** * ***** * *
**** *** **** / 2+1; j++)

{
* * * ****** ** * * ** * ** * a/2 -j +1;k++)
* * * * * *** ** * * *** ** ** *
** * * * *** ***** * ** ** *** ** *
* * * ** *** *** ***** ** * *** * * ***

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
***** *** * * *** ** **** * ** * * ** * ** * * * * ** *** * * ********** **** ** * *** **** ***** * * *
*** * ** *** ****** ** ** *** ** * * * * * * *** * * * * ** * ** * * * ** * **** * ** ** * *** * * ** * ** **** **
********** *** *** ** ** * * * ** * * ** *** **** * *** * * **** ** ** * ****** ** * * ** ** ** ** ** ** * **** ");
** ** * ** ** *** * **** *** **** * * ** * ** * * * * **** *** ********* * ** * **** *** ***** * ******* **** ************ * * **
* **** ** *** * ** *** **** * * * * * * * ** ** * * ** ** ** * *** * ** * ** * * ** * *** *** ***** * *** * * *** *** *** *** **
* * * ** * *** **** ** ** * **** *** **** ** * *** **** * * *** ******** * *** ** ** * **** ** **** * * *
***** ** * * *** * * ** * * ** * * ** ** * * ****** **** ** *** ** * ** *** * * ** * ** ** **** * **

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include *** *

#include * * * * ** *



int main()

{
* * * * * * * * * * **** num, n, p;
*** ****** ** **** ** ** * * *** * ** *** &num);
*** * * * ** ***** * * (n = 0; (2 * n) + 1 <= num; n++)
*** ** * * *** * * **
* ** ** *** **** * ** ** * * * *** * ** * (p = 0; p <= (num / 2) - n - 1; p++)
* *** ** * ** * * * * ** * * * **** * ****** ** ** * * ** * ** * * * ");
** * ** * * ** * ** * ** * (p = 0; p <= (n*2); p++)
** *** *** * *** * * * ** ** ** ** * **** * **** ****** *** **** ** * ** * * * * **
******** * ** ** * ** ** ***** ** ***** * **** *
** * ** * * ** * *


* ****** * ** * ** *** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** *



int main()

{
*** * * * * * ** *** a, b, c;
** *** ** ** **** *** * * * * ** **
* ** ** * *** ** *** ** c <= a; c+=2)
*** * ***** **** *****
** * * **** * * ** * * ** b <= (a-c)/2; b++)
* * **** * ** ** * *** ** **** ** * **** *** ");
** *** ******* * ** ** * * * ** b <= c; b++)
* ******* * * ** **** ** *** ** ** * * * ** * *** **
** * * * *** ** * **** *** **** ** ** ** ***** **
**** * * * **
** ** ** * ***** *** ** * 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * ** *** * *** a ;
** *** ** * * * * i , j ;

    
** *** ******* * ** * ** * ** * ** * &a);


* ** * * ** ** * * ** ****** *

    {
*** ** *** *** ***** *** *
*** ** * * ** * * ** * * ** *** ****** * * ** *
* * ** ** * ** * * * ** * * ** ****
* ** * **** * ** *** **** *** * ** **** ** ");  
* ** ** ** *** ***** *** * * **** *
******** * ** * ** ** ** * ** ** *** ** ** ** * * *** *** * *** *** ** * *** **** * ** * ****** * * * ***** * * ** * * * ** **
** ** **** * ** *** * ***
** * *** * **** ** * * ** * ****** *** ** ****** * * * ** * ** * *** * * ** * *** ** * * ******* ** * * ** *** *** ** * ** * * * ** * ** * ** *** ** ***** * ** ***** * ****** * * * ***** ****** ** ** ** ***
*** * * * ** *** ** * ** * ** *** **


* ** **** * * * ****** *** *
** *** * ** * * ** * * * * **** * ******* * * *** ******

    }

   

    
**** * ** * * ****** *** * ** **
* ** ** *** * * **** *** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.81
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.1k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users