0 like 0 dislike
5.5k views
請設計一個程式,利用迴圈輸出文字金字塔。

p.s. 輸入皆為奇數,且不大於20

範例輸入1:

5

範例輸出1:

  *

 ***

*****

輸入範例2:

7

輸出範例2:

   *

  ***

 *****

*******
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 13501 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 0
Called for Help
0 0
Called for Help

45 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * * * *

main()

{
* * ** ** i,a,b,c;
* ******** ** ** * ** *** * ** ** * ***
*** *** ** *** * ***** *** **

{
***** * * ********* * * * ** **

{
* * * ** * ** ** * *** ** ");

}
* ** * * * * **

{
** * ** * *** * * * *** *

{
** ** * *** * ** * * ** * *** *

}

}
* ** * * ** ** ** ***** ** * **



}


** *** *** * * * ** *** ** ***** *
** * * ** *** * ***** 0;







}
answered by (-190 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{

   int num;
* * * * **** * * ** * *** **** *** &num);
* * ** * *** * * i = 1;i <= num;i=i+2)

   {
* ****** *** * * * **** ** *** * **** * *** *** ");
** ** * *** *** **** * ** * ** **** * \n");
** *** ** *** * * * *** * *** * *** * * **** k =1;k<=num-(i/2);k++)
* * * * **** ***** **** * * ** ***** ***** *
* * ** * * ***** * * ** *** * * ** * *** * * **** * * * * * ");
** * * * ***** **** * ** ** * ** **
** ****** * * * ****** *** **** * * ***** *** * ** *** **** **** * ***
* ******* * ** * ** * ** *** *** ****** * * j = 1;j <= i;j++)
** ** ** * * **** * ** * ****
** ** **** * ** *********** * **** * ** * * ** * ** * ***** * *** ** *  
* * ***** **** * *** * *** ** ** * * * *** * ** * * * * ** * ********** * * * ********* * ** ** * * * *** * ** * * ** * *** * * ** * * ** * * *** *** ** ** * ***
***** * * * *** **

   return 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* * * *** ** * * ** a, b, i;
* ** * * * *** **** *** * * * * * ** ***** * ***
** * * * ***** * * ** * * ** * **
***** * *** ** * * ** *
*** * **** ** * * ** **** ** * * * * * * * ***
* * * * ** * *** ** * ****** * * *** * * * * * ");
** * * * ** * * *** * * * ** * ** * * * ** * **** * ***
***** * * ** *** ** * * *** ****** * * *** **** * * * * **
* * * * * * * * * * ** * ** ****** * * * ** ****
* *** * * ** * ** * **
** ***** **** * * *** * * *** ** * *
* * ** * * *** * * ** * 0;
* * * * * * * *** *
* * * ** ** * ***** ***
** ** *** **** ****** ***

    

    

    

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
* * ** * * * **
* * ** *** *



int *

{
* a, j, k;
* *** * *** * * * * * * * * *
*** = 1;j * * a / 2 + 1;j ++)

{
* ** ** * * * ** * = 0;k * * a / 2 - j +1;k ++)
* * *** * * *** ** **** ** * *
* ** * *** * * ** ** ** ** = 0;k ** * * * 2 + 1 ;k ++)
**** ** * * * *** ** * *
*** * * * ** *** * * **** * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include * *** * ****

#include ** ** * *



int main()

{
******** **** ** x,y,z;
* * ** ** * * * ****** * ***** ** ** *
** * ** *** * = 1;x <= (z+1)/2;x ++)
**** * * * **
* ** * * ***** * * * ** ** = 1;y <= (z+1)/2 - x;y ++)
* * ** ** * * * * * * * *** * ** * **** ** * ");
* * *** * ** ** ** *** * *** **** * * * = 1;y <= (x*2)-1 ;y ++)
* *** ** ** *** **** ** ** **** **** *** * * *** * ** ** *
*** * * ** * * * * * * * * * *** * *** * * * **
* ** * ** *


* * *** * ** **** ** 0;

}
answered by (-188 points)
0 like 0 dislike
Hidden content!
#include ** * *** ***

#include ** * *** **



int main()

{

int a, j, k;
* ** * ** * * *
**** ** / 2+1; j++)

{
****** * ** **** * **** ** ** ** ** a/2 -j +1;k++)
** * * * ** * ** * **** * * * * *
** * ** ** * ** ** ** * * * * ****
*** * ** * * ** *** ** * * * * * *

}

}
answered by (56 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

int a,j,k;

scanf("%d",&a);

for(j=1;j<=a/2+1;j++)
* * ** **** ** * ** * * * ** * ** * **** **** * * * *** ** ** ** *** * * **** * ** * * ***** * *
* * * ** * ** ** **** * **** * * ** ** *** * * * * ** ** * * *** ***** * * ** ******* * *** * * * *** * ******** * * * * * ** * *
*** ******* * * ** **** ** ** * ** ** * *** *** ** * *** * * * **** **** **** *** **** * * ***** *** * * ** * * ** ");
* *** ** * ********** ** * * * **** *** **** * *** * **** * ** * * * ** * *** ** ******** * * ** *** * * * ** * ** * ** *** *** **
* *** * ** ** * ** * ** * ** * ** * * *** **** * *** ** * *** *** * ** * * * *** ** * ** ** ** *** ** ** **** *** * * **** ** * ** *
* * ****** * ** *** ***** * ******* ** * *** *** **** * * * ** * * **** * * ** * * **** * * *** **** * **** **** *** ** **
**** * **** ***** * * *** * * ***** *** * * * * ****** ** ** ** *** ** * ** ***** * ** ***** * * ******** * * * ***** * * * *

system("pause");

return 0;

}
answered by (-284 points)
0 like 0 dislike
Hidden content!
#include * ** * * **

#include ** ********



int main()

{
**** * *** *** *** * ** num, n, p;
* ** *** **** * ** ** * ******* * &num);
* * * * * ** ** * * (n = 0; (2 * n) + 1 <= num; n++)
**** ** ** * ** * * ***
* * * * ** ** * * * * * *** * *** * * * * * (p = 0; p <= (num / 2) - n - 1; p++)
* * * * * * * *** * ** *** * * * * ** *** ** ******** ** * ** ** * * ** ");
** * * * * ** ********* ***** ** ** **** ** (p = 0; p <= (n*2); p++)
* * ** ** **** ** ***** * ** * * ** * **** ** * ** * * ** ****
****** * **** * ** * * ** * * **** ** * * * * * *** **
** **** ** * ** *******


* * ******* * ***** ** 0;

}
answered by (-214 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * * **** * *



int main()

{
* ** *** ** ** ** * * * a, b, c;
* * * ***** * ** ** * ** *****
* * ** ** * ***** ** c <= a; c+=2)
** * * * ** * **
* *** * * ** * *** * * * * ** ** b <= (a-c)/2; b++)
* **** ** ** ***** * * * * **** * ** * *** * * ");
** ** *** ***** ** *** * *** * ** * b <= c; b++)
* ** ***** ** * * ** ** ** ** * ***** * ** * *
** * * ** * ** * * ** *****
****** ** *** * *
* * * **** *** * ** ** 0;

}
answered by (-202 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>





int main()

{
* * * * ** * ** * a ;
** * ** *** * * * ** i , j ;

    
* *** ******* *** * ** * ***** * * * &a);


* * * * ** * *** ** ******* *

    {
* * * * ** * * ** ****** * * ** *
** *** **** *** ** ****** * ** ** * *** **** * * * * **
***** ** ** *** *** * * * *
* * * * * ** * ** ***** ** **** * ** * * * ");  
** * * ** **** *** *** ** * * * *
* ** * ** *** * * **** * * * * * * *** ***** * * * * ** *** ** ****** **** * *** ** * * * * *** ** * * * * ** *
* ** * * * * *** * ** ** *
** * * * *** ** ** * * ***** * * * *** ** * * * ** * ****** * ***** * *** ** * * ******* ** * ** * * * * * ** * * * * ** **** * * ** ** * ** * ********* * * * *** * ********** ** ** *** * ** ** * ** * * ** ******* ***
* ** * *** ******** * * * *** * * ** *


******* * **** ** *
* ** ** * *** *** ** * * * ** **** * * * ** * * ** *

    }

   

    
** * ** * ** *** ******* * *** ** * * * *
* * * *** * ** ** *** ** * 0 ;

}
answered by (-186 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.68.150.38
©2016-2025

Related questions

0 like 0 dislike
23 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13528 - Available when: Unlimited - Due to: Unlimited
| 3.2k views
0 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 作業 by Shun-Po (18k points)
ID: 13427 - Available when: Unlimited - Due to: Unlimited
| 7.2k views
0 like 0 dislike
40 answers
[Exercise] Coding (C) - asked Sep 29, 2016 in 作業 by Shun-Po (18k points)
ID: 11795 - Available when: Unlimited - Due to: Unlimited
| 4.8k views
0 like 0 dislike
60 answers
[Exercise] Coding (C) - asked Oct 13, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13428 - Available when: Unlimited - Due to: Unlimited
| 6.4k views
0 like 0 dislike
31 answers
[Exercise] Essay (Open question) - asked Nov 3, 2016 in 作業 by Shun-Po (18k points)
ID: 16958 - Available when: Unlimited - Due to: Unlimited
| 4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users