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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
***** **** * * ** * *** * * * * *** * * * * ** * ** * *** * * *
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if (year%4 == 0)
{
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}
else
days = 365;
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** *** * ****** *** ** * * * ** * * * * ***
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* * **** * * * * * * * ** 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
** *** * * ** * * *
* * * main()
{
** * * ** * * * * i=0;
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
**** * * ** * * year, days;
*** * * * * * *** * ** ** ** ** ** * * input year:");
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* * * *** * * * (year % 4 != 0)
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* ** ** * * ** * ** * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * ** * * *** * year=0;
* * **** * * * * * *
*** * * * * * * * * ** * * * * ** * **
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****** * ** * * * *
* *** * ***** * * ***
}
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Hidden content!#include<stdio.h>
* * **** * **** *
** * *** ** *** ** * ** main()
{
** * * * ** ** i=0;
** * * * ** ** * * * * ** * * * * * * ** *
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Hidden content!#include ** * * * * * * *
main()
{
* ** * * * * ** year=0;
* * ** * ** * * * *** ** **** * &year);
* **** ** * ** * * * * * && year%100 !=0)
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* * * * * ** * * * *** * * * * ** *
}
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Hidden content!#include <stdio.h>
#include * * * * * **
int main()
{
* ** * * **** * * ** * * * * year;
** * * * * * * * * ** * *** * * * * * put your years:");
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*** * * * ** * * ** ** * ** * ** * * **
* ***** * * * * * * * * * * * ** * * **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * * * * * ** year=0;
** * * * ** * * * *
* * * * ** * * * ** * * * * * * ** * *** *
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** * * * * **
* ** ** * ** **
* ** ** **** *** * * *
}
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