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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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* ** ** * * * ***** * * * * ** **** ** * * * * * ** * * **** ** *
if (year%4 == 0)
{
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}
else
days = 365;
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** * ** ***** *** ******* * ** ** * * * * * * ** * *
return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
* * * ** ***** * ** * * *** * year=0;
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
** ** **** * * ** *** * * * * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* * ** * * * * * *
* ** ** *** * ** * * main()
{
* ** * * ** * ** ** ** i=0;
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
*** *** *** * * ** * * ** *** year, days;
*** * * * * * ** ** * * * * * ** *** * input year:");
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*** * * * * * * * ** ** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* *** ** * * * * ** ** year=0;
* *** * * * ** * * ** *
* * ** ** * * ** * * * ** ** * * * **
* ** * * * * * *
* * * * * * * *** * * **** * ** ** *
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*** ** *** * * ** * ** *
* *** * * * ***** *** **
* * ** * * *** ** * *
}
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Hidden content!#include<stdio.h>
**** * * * * *
**** * * ** * * * * * main()
{
* ** * * **** ** * ** * i=0;
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Hidden content!#include * * * *** * *
main()
{
** ** * ** * * * year=0;
* ** * * * * * * * * * &year);
*** * * * * * *** * **** ** * && year%100 !=0)
* ***** ** * * *** *** * * * * * year is leap * * * * *
* ** * * * * * *
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** * * ** * ** * * * ** * *** *** *
}
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Hidden content!#include <stdio.h>
#include ** * * **** * * **
int main()
{
** ** * * * * year;
* * * ** ** * * **** ** * * **** ** ** ** *** put your years:");
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* * * * * * * ** ** ** * * * * ** ***** 0;
* * * * * * * * * ** * * * * ** * * ** *
* ** ** ** * * * * ** * **** ** * * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* *** * * ** ** * * * ** * * year=0;
* * * * ** * * * ***
* * ** * * * *** * * * ****** ** * * * * *
* * * * * * ** * * ** *
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* * * * * * * * * *** * * * * * year is not leap year", year);
* * * ** * ** * * *
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***** ***** ** ** * ** *
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* * * * * * * * ** * *** ** *
* * * * * ** * * * * * *
}
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