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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
*** * * * * * ** * **** * ** * * * * * ***** * * *
* * * * * ** * *** * ***** * ** * * ** ** * ** *
if (year%4 == 0)
{
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}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
* * ** * * * * * year=0;
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
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}
** *** * * ** **** * * ** * * 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* * ** * * ** * * *
** * ** * * * main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * ** * ** * *** year, days;
* * * ** * * * ** * * ** * ** ** ** input year:");
** * * *** * ** ** * ** * * * ** * * &year);
* * * *** ** ** (year % 4 != 0)
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* **** *** ** **** * * * * * * ** ** * * *** ** * * ** * * * * = 366;
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* * * * * * * * **
* * ** * *** * ** * * * * * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** *** * * *** *** ** ** year=0;
** ** * ** * ** *** * * *
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* * * * ** * * * * * *
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* * ** * * * ** * *
}
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Hidden content!#include<stdio.h>
** ***** ** * * * * ** *
* ***** * * * main()
{
* * ** *** ** i=0;
** * * * * * ** ** ** * * * * * * *
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Hidden content!#include * * *** ** *
main()
{
* * * * * ** * * year=0;
* * ** ** * ** ** *** *** * * * &year);
* ** ** * * * ** ** * * ** * && year%100 !=0)
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* **** * ** * * * * **** *
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* * * * * ** * ** * *** * ** * *
}
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Hidden content!#include <stdio.h>
#include * * * * * *
int main()
{
** *** ** * * * * year;
* * * ** * ** * ** * *** * ** * **** * ** * put your years:");
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** * * ** * * * * * *
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* ** ** * * * * * * * * ** **** if(year%100!=0)
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* * * * * * * * ** * **** * * *
** * * * * * * ** * * * * * **
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * ***** * * * * * * year=0;
**** *** **** * **** * * *
** ** ** ** * *** * * ** * ** * * * * * * *
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** * * ** *** * * **
* * ** ** * * * * ** *
* **** ** ** ** * * *
}
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