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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
* ** ** * ** * **** * * * * * * * * * **
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if (year%4 == 0)
{
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}
else
days = 365;
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
* * * * * * * ** ** * * ** year=0;
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}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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else
* *** * ** * * * *** * *** * * * * ** ** * * year is not leap year",i);
}
*** * * * ** * * ** * * * * *** 0;
}
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楊傑宇
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Hidden content!#include<stdio.h>
* * * ** * * **
** * * * * * * ** * main()
{
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answered
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * ** * * * * * * ** year, days;
* * * ** * * ** * *** *** ** * ** * input year:");
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* * * ** *** * * * * * *** 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** * * ** ** * * * * * year=0;
* * * * * * ** *** * *** * **
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}
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Hidden content!#include<stdio.h>
* * ** * ** * *** ***
* ** **** *** * main()
{
* ** * * * *** * * * ***** i=0;
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Hidden content!#include ** * * *
main()
{
* * * ** * ** ** * * year=0;
* * * * * ** * ** * *** * ** * &year);
* * *** *** * * * *** ** * && year%100 !=0)
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* * * * * ** * * * * * * *** * **
}
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Hidden content!#include <stdio.h>
#include * * * *
int main()
{
* * * * * * * * ** * * * year;
* ** * * * * * ** * * * *** **** put your years:");
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* * * ** * ** * ** * * * ** 0;
** * ** *** *** * * * ** *** * **
* * * **** ** **** * * ** *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * ** * * * * * * year=0;
** *** * * * *** * * *
* * **** ** * * ** * * * ** ** ** *** * * * *
* * * ** * * *
* * ** * * * *
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** *** *** * * * ** * *
** * * * * * * * * * *
** * * * * * ** * * * *
}
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