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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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if (year%4 == 0)
{
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return 0;
}
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Hidden content!#include<stdio.h>
int main()
{
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
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}
* * * * *** * * * * * ** * 0;
}
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Hidden content!#include<stdio.h>
** ** * * * * * * ** * ***
* * * * * * * ** main()
{
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * ** * * * * * year, days;
* ** ** * * * * * ** * ** * *** * * ** ** * input year:");
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* * * * * * * *** *** * ** * 0;
}
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * ** * ** * **** ** year=0;
* * * * * * ** * * ** * ** * *
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}
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Hidden content!#include<stdio.h>
* * *** * * *
* ** * * * * * main()
{
* * *** * *** * i=0;
* * * ** ** ** ***** * * ** * ** * * * * *
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Hidden content!#include * * *** * ****
main()
{
* ** * * * * * *** year=0;
* ** * * **** * * * * &year);
* * * * ** * && year%100 !=0)
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* *** * * ** * ** * * * * *
}
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Hidden content!#include <stdio.h>
#include * * ** * *
int main()
{
* * * * ** * *** * * * year;
* * * * * * ** ** * * * * * ** * * put your years:");
* ** * ** ** *** * ** * ** * * * *** * * * * * * * ** *
* *** **** * *** *** * * ** *
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** * *** * *** ** ** * * * ** * * * if(year%100!=0)
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* * * ** * * * * * * * ** * * is leap year");
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* * ** *** * ** ** * ** ** * * * ** 0;
* * * * * * *** ** ** * * *
**** ** ** * ** * ** ** * * *
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * ** * ***** * year=0;
*** * * * * * * * *
* * **** ** ** ** ******** * ** ** * * * * ** * * *
** * * *** ** * **** * ***
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**** * * * * * * *
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** * * * * * ** ** ** * * * 0;
* * ** *** ** *****
* ** * *** ** * **
* * * * ** ** * * * **
}
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