0 like 0 dislike
1.6k views

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000). After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13, the sequence is: 

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.
Input:
The input consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets. For each test case, there is one single line containing the number N.
Output:
For each test case, write sequentially in one line the number of digit 0, 1, …9 separated by a space.

Sample Input

2
3
13


Sample Output

0 1 1 1 0 0 0 0 0 0
1 6 2 2 1 1 1 1 1 1

Sample Input 2

1
5


Sample Output 2

0 1 1 1 1 1 0 0 0 0
[Normal] Coding (C++) - asked in Introduction to Computer Programming II (C++)
ID: 49740 - Available when: Unlimited - Due to: Unlimited
| 1.6k views

2 Answers

0 like 0 dislike
Hidden content!
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int a[10],b[20];
    int k,n;
* * * * * * * * ** * * * * * **** *
    for(int i=0;i<k;i++)
    {
* *** * ** ** * ** ***** **** *** ** * ** * * * *
* ** * ** * * * * * *** *** ** * * ** ****
    }
    for(int i=0;i<k;i++)
    {
** ** ** * ** * * * ** *** ** ** * * ** *
* * *** *** * * *** ** **** * * ** * * ** j = 0;j<=b[i];j++)
* * * * ** ** ** * * * ** ** * ** * * *** **
* *** ******* ***** ** *** * *** **** * * ** * * * **** * * * * k = j;
* ** * * * **** * ** * * **** ** *** * * *** ** *** ** * * *******
****** **** *** ** * * ***** * **** * ** ** * **** **** ** *** *
* * *** ** * **** ****** *** * ** * * *** ** ***** * **** **** *** * ** ******* ** * *** num =k%10;
***** *** * ** * * **** * * ** * * * *** **** * ** * * * ****** * * **** * * *
**** * * * ** * ** * *** ***** * * * ** * * * *** * **** ** * * *** ***
** ** ** * ** * ** * *** *** * ******* **** ** * * * * ********
* * ***** * * * * * * ** * ** * ** ** **
**** *** ****** *** * ***** * ** * ****** * * *** ** ***
*** ***** ** * ** * ** *** * ***** * ***** *
** * * * * ***** * *** ****** * * * ** ** *** *** *** ** * * *
* ** ** * ** **** * *** *** ***** **
** **** * *** ** * *** ** * * ** ***** * * ** j = 0;j<10;j++)
* * * * **** *** *** * ** ** ** **** ****** *** *
***** * ****** *** * * ** * *** * ** ** **** ***** ** * ***** *
* * **** * * ** * ** * ** ** * ** *** * ****** ** * *** * ** *** * * ******* * ** * * ** * ";
* ** *** * * * * * ** * *** **** *** * **** * *** * * * ** * ** * ** * **
* ** * *** ** ***** * * * ** * * * * ** * *** * ** ** * *
*** * ** ** ** ***** * ** ** * ** *** **
    }

    return 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <iostream>

using namespace std;

int main()
{
    int counter[10],counter2[10],arr[1000],arr2[1000];
    int n1,n2,n3,i,j=0,rem,dec,k;
    for(i=0;i<10;i++)
    {
* **** ** * * *** **** * ** * ** ***** *
* ** ** ** * *** * **** * ** * * ** ** **** ** *
****** ** * ***** ***** ***** ** * ** * * * ** ** * *
    }
    cin >> n1;
    if(n1>1)
    {
* ** **** * * * * *** * ***** * * * * >> n2;
* * ** * *** * **** * *** **** ** ** * ** * ** ** >> n3;
      
* * * ** * * * * * ** ** * * * * *** *
        {
*** *** ** **** * ** * ** ** **** * * ** ** * * ** * * * ** ** * * **
* * ** ** * * **** ** * * * * * * ***** *** ***** * **** ** * * * **
* * * *** * ** ***** ** * * ** * * * ** *** **** **** * *
* * **** ** * **** * * **** * * ** ** * * ***** * *** * ** ** * ****** *** ** *** * * ***** *
* **** * * ** ** ** *** ** * * *** **** * * ** * ** *** * **** ** * * * ****** ** ** ** ** * ****
* *** * * *** **** ***** ** ** * ** * ** ** * *** **** * * * * *** ** * * * * * * *** * ****** *
**** ** *** *** * * *** * ** ** * * ** * * * * ******* ** * * * * * **** **** *
* ** * * * ** * * ****** * ** * ** * ** ** * ***** *** ** * * * *** * * * ** *
* * ***** ********* ** * ** * ** ** ** ** * *** * * *** * * ** * * ** ** * * * **
* ** *** ** * * * *** * *** ** ** * ** * * * * *** * *
        }
** * ****** ** ** **** * **** * * ** ** * * ** **
        {
*** * * * * * ***** **** * ** ** * * * *** *** * * **** *** * ***** * * * ** *
* * * ** ** ** * **** *** ** * * ** * * ** ** ** ** **
* *** *** ** * * * * ** ** * * **** * * ** * ** * * * * * * * *** * ** **** * ** **** * *
** **** * * *** * ** * * * * * * * * **** ** * * * * *** *** * * ** ** **** ** ***** ** * **** ** **
** ***** * * * ** * ** *** * * * *** * * * *** * * **** * * * ** *
        }
* * ** *** * * ***** *** *** * ** * ** * * * ***** ** **
        {
** * * * * * * **** * ** * ******* *** **** * ** *** ** * * * * *
** * *** *** ** ****** ** * * * ** ** * * * * ** * * * ****** ******
**** ** *** *** **** ** *** **** * ***** *** ** **** ** * * * ** ****** * ** ** *** ** * *
** ** ** * ** ** * *** ***** * * ** *** ********* ** *** *** * ** * * * ** * *** * ** ***** * **** ***
* * ** * *** ** ** ********* ** ****** * * * * * ****** **
        }
* * * * *** * * ** ** * ******* ** * * * ** ** * ***
        {
* ** * * * *** * * * *** ********* **** * ** ** ** **** *
*** ** ** * *** * ** ****** * ** * * * ********* * * ** * ****** << counter[i];
**** * * * *** * ***** ***** *** * * * * * * * ** **
* * ** * **** * ** *** * * ********* * * **** * ***** * ** * << " " << counter[i];
* * **** ** * * ****** * ***** * *******
** * * * * * * ** ** ** ** *** ***** ** ** *
** * * * ** ** * ***** *** * *** * * ** **** * **
*** * * * * * *** * *** * **** ** ** * *
* ****** **** * ** * ** ** ** *********** * ***** * ** ** ** * *** * ** *
**** * * * **** * *** * ** ** * * * * ****** *** ** * *** * * * * *** * << counter2[i];
** * * * **** ** * **** *** * *** * ** *** ** * * ** ** ** * * * **** * ****
** * * ** *** * * *** ******* ** ** ***** ** ** * * * ** ** << " " << counter2[i];
        }
    }
    else
    {
*** *** * * ** *** * **** * *** * * * * ** * * * *** ****** *** ***

**** * ** ** ****** *** * ** * * * **** **
        {
* ** ** * ** *** * *** ***** * * *** * ****** ** * *** * ** * *
** * **** * ** ** * * * **** * *** * * ***** ** * ** ** * ** * **
* ** * * * *** *** **** **** * ** * ** *** *** * *** ** ** **
* * * * **** ** * ******* * **** * * ** * *** ** ***** ***** * * * *** ******* * *
* ** ** ** * ** ** ** ** * * ** * * ** * **** * * ******* ****** ***** * * *
* * * * * * * * * * ***** ** ** * * **** ** * ******** * * * *** * ***** **** * * * * ** * * *
* **** ** * * *** ** ****** * * ** * * * * * *** ***** * ** * * **** * * * ** * ** * *
** * * * ** *** * *** *** * * * * * **** *** * ** ** * ** * ***** * * **** *** * ** * * * **
**** * * * * *** ** ***** * **** *** **** * ** * **** *** * * * **** *** * * * ** * ***** ** * *
** ** * * ** *** * * * ** *** **** *** ******* * ** ** * *** *
** *** * * **** * * * ***** * * ** ** * ** ***
* **** * * * * * ** * *** * **** **** *** ** *
        {
** ****** * ** * * * * * ** * * * ** **** ** * ** ** * * **** *** * ** * ****
** * ** * **** * ** *** * ******* *** ** * * *** ** * *** **** *
* * ** *** * * * * * * ** ** *** * *** * ** * ** **** ** ** * * * * *** ** ** ** ***** * * **
* * ** * * **** ** * ** * * ** ** *** * ** *** * **** * * * * * * ** *** * ** * * *** * * *** ** * ** * * ** ** ****** *
* * * *** *** * ** ***** ** * * ****** * * *** **** *
** ***** * *** * * * ** ** * * * ******
      
* * ** ** ** * * * *** * ***** *** ** ****** ** *** ***
* ** * **** ** * * * * *** * * ** **** *
** ***** * *** * * ** * ** * *** * ******** ** ****** * *
*** **** * * ** * ** * ** * *** * ******* * ** * * * * ** * << counter2[i];
* *** *** * * **** ** * * ** * * * ***** ** * ** ** *** ** *
*** * ** *** ** * ** ** * ** ** **** *** *** *** * ** * ** * * << " " << counter2[i];
        }
    }
}
answered by (-323 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Why??
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.177
©2016-2025

Related questions

0 like 0 dislike
1 answer
[Normal] Coding (C++) - asked May 17, 2018 in Introduction to Computer Programming II (C++)
ID: 52073 - Available when: Unlimited - Due to: Unlimited
| 1.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users