0 like 0 dislike
1.9k views

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000). After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13, the sequence is: 

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.
Input:
The input consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets. For each test case, there is one single line containing the number N.
Output:
For each test case, write sequentially in one line the number of digit 0, 1, …9 separated by a space.

Sample Input

2
3
13


Sample Output

0 1 1 1 0 0 0 0 0 0
1 6 2 2 1 1 1 1 1 1

Sample Input 2

1
5


Sample Output 2

0 1 1 1 1 1 0 0 0 0
[Normal] Coding (C++) - asked in Introduction to Computer Programming II (C++)
ID: 49740 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

2 Answers

0 like 0 dislike
Hidden content!
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int a[10],b[20];
    int k,n;
*** * ** * ** * * * **** **
    for(int i=0;i<k;i++)
    {
* ** ** ***** * ** *** **** * * *** ** **** * **
*** * ** ** ** *** * *** *** ***** **** ** ******
    }
    for(int i=0;i<k;i++)
    {
** ** ** * ** * ** * * * * * * * * **
* * ** ** * * *** ***** * * ** **** *** * *** ** * j = 0;j<=b[i];j++)
* *** * ** * * ****** **** ***** *
* ** ** * **** * * ******* ** ******** * * ***** *** * ***** k = j;
* * **** *** * * * * * *** *** ** *** * ** *** ** * *** * *****
* * * ** **** * * * * **** ** ***** *** * ** * *** **
* ******** * **** * * ** ** ** **** * * *** * **** ******* * * *** * ** ***** ** *** *** * ** num =k%10;
** ** ** **** ** * * * * * ****** *** * ** *** ** **** * *** ***** * *** ** * *** *** * ***** *
*** *** ** ****** * * * * * * * * * * * * * ** *** *** ***** * * * * *** * *** **
**** * ** ** ** * **** * * ** **** * *** **** *** **** * *
** ** * * **** * * * * * * * *** * * ** *****
* ** ** * * * ** ** * ** * ** * * ****
* * ** * ** * ** *** * **** * * * *** * **
* *** ***** * ***** *** **** ** * * * ** * * * *** * * ****
* * * *** *** * ****** ** ** * ** * * * * * * *
*** * ** ** * ***** ** ****** ***** j = 0;j<10;j++)
***** *** * ***** **** * ***** * ** ** *
* *** * * * ** * * ***** *** * * *** ******* * * *** * ** * ** *
* * * *** * ** ** * ** *** *** *** **** * *** ***** *** ****** ** * * * * ** ***** ***** ";
* * * * * * * * ** ** * * *** ** * * * * ** * ** ** ** * * * * ***** ** **
* * *** * **** *** ** * * **** ** ****** ** *** ** ** *** * * * ****
* * ** * * ** * * *** *** * * ** * ** * ** ***
    }

    return 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <iostream>

using namespace std;

int main()
{
    int counter[10],counter2[10],arr[1000],arr2[1000];
    int n1,n2,n3,i,j=0,rem,dec,k;
    for(i=0;i<10;i++)
    {
* ** * ** * * * * ** * ** * * * * ****** * * **
** **** ** * * ** * ****** * *** * * *** * *
*** ** ** * * *** ** **** * * * * ** * **
    }
    cin >> n1;
    if(n1>1)
    {
* * *** * * * ** ****** * *** * ** * * >> n2;
* * ** * * * * * **** * **** * * ** * * * >> n3;
      
**** ***** ** ** * * * * * * **** ** ** * * **** ** ** * *
        {
**** * * * ** ** *** * *** ** ** * ** *** ** * ***** * * **
* ** * * ** * ** *** * * * *** * * * ** * ** *** ** * * * ** * * * * *** **
**** ** **** ** ***** * *** * * ****** ** * * * *** ** *
* * * ** **** **** * **** * * * ** *** * ** * * * *** ** * * * * *** ** ** *** * *
* ** ** * **** * * * * ** ** ** * ***** * * *** ****** * ** * * * * *** * * ** ** **
*** ** * * * **** * * * * * * **** **** * * * ** * *** * * ***** * **** **** *
** * * ****** ** ***** ** * * * *** * * *** *** *** *** * * * * ** * **** **
*** ** * *** ** ** ** *** * **** * ** *** ***** * * ** ** * * ** *** * *** *** ** **
* * *** * * **** * * * *** * * * * * **** * * * **** **** * * * *** * ** * ** *** ****** **** *
* **** * * * ** * ** * * * * *** ** * *** *** * ***** * * **
        }
** * * ***** *** ** **** ** * ** ** * * *** * * ***
        {
**** ** ** ** * ** * * ** * *** * * * * * * * * ** * ******* * * * * *** * ***
* * *** *** * * * * * * * * *** * * * * ** ***** * ***** *
**** * * ** * ** *** ** * ** *** ** ** * * * * *** * *** ** ********* *** ** ** * * **
** * ** ** * * * * ** * ** * ** ***** **** *** * ** ** * *** ***** ** * * ** **** * * ** * ***
** ** * * * ** ** * ** * * **** *** ** **** **** ****** *
        }
** **** *** * ******* * * ** ** ****** * ** *** ****** *
        {
** ** ** * ***** *** **** **** ** * * * * *** * *** * *** * *** *
*** ** *** * ** * * ***** *** *** * * *** *** **** * *** ** * ** **
**** * ********* *** ** * * ***** * ** ** ****** ** * * * * * * * **** * ** ** *
* ** * *** * *** *** * ** * * ** * * ** *** * * * * * * * ** *** * * * * ***** *** * ** * * ******* **
** * * * * ** ** * **** ** ** * * ** * *** *** * * ******* * **
        }
* ***** * **** * *** **** ** * * * * * * ** * * *
        {
*** ** * * ** * ** ** ** * ** ** * ** * *** *** ** ***** ** * * *
** * * *** ****** ** * *** * *** * * * * * *** * * ** ** * * << counter[i];
*** * ** * * *** *** ** **** * * * ** ** * ** **** * **** **
**** * * **** * ** * * ** ** * * * ** *** * ***** *** << " " << counter[i];
**** *** ** ** * * * * * * ** * * *** **
** *** * * * ** * ** **** ** ** * **** **** * * * * * *
* *** ** * * ** * * * *** * * * * * ** * * ** * **** *
****** * * * ** * * * ** ** *** * *
* * *** * * ****** * ** **** * * * *** *** *** ***** *** * *** ** ** *
* * *** * * **** ** * ***** *** *** *** ********* * ** **** * *** * **** * << counter2[i];
* * ******* * ************** * * * *** * * ** ** * ** * * * ***
* * ** * *** ** *** * ** *** ***** * * ** ** *** * * * ** << " " << counter2[i];
        }
    }
    else
    {
* * *** ** * *** **** * * ** * ***** ********* * ** * ** * *

* ** ** ********* * *** ***** * ** * * ** * * * **
        {
** ** * *** * ** * * * ** ** * * * ** ***** * * ** *** * ** ***
* *** * * *** * * ** **** ** * * **** * * ** * ** * * *** **
*** ** **** * *** * ** * * * * * **** ** ** ***** * * * *
* **** ** *** * *** * *** * ** ** ** * * * ** ** *** ** **** * ** * **
*** * ** *** ***** * * * ****** **** ** *** ***** * * ** ** * * ** * ** * ** * * ** * * **
* * * * * * * * ** ** * * * * * ****** ** *** ** * ** * ** * * ** ***
*** * ** * * * ** * * ** ***** * ** * ** * ** ** * * ** *** ** * * ** * *** ** ****** * ** ** * *
* ** * *** * * * ** ** ** ** * * ** * ** ** ******* * * * * * ** * ** * ** * * * **
*** * ** ** *** ** * * * ** * * * ** ** *** ** * * * **** ** * * * * ** *** ** * * **** *
****** *** * ** * * * ***** ***** ** **** * ** ** *** *** ** ** ******
***** *** * ** * * ** * ** ** * * * * *** * ** *
** * * ** ***** * * * * ***** * * ** ***** * * * ** * *** *
        {
* *** **** ** * ***** *** *** **** *** ** *** * * *** ** * * *** * ****
** *** * * * ** * * * * * ** * ******* * ****** *** *
* * * * * * * * * *** * * * ** ** **** *** * * ** ** ** ** * * ** * * ****** * ** * **
* * ***** * * * *** * ***** *** ** ** * * ** * ***** *** * *** *** * *** *** * **** ** *** * **** * *******
* ** *** * ** * **** * *** * ** ** * * * *** ** **** * ** * *
* ** ** ****** * ***** ***** * * * * * ** * * *
      
* * ** *** * **** ** * * ***** ** * *** * ******** ****
* * **** ** * * ** * * * * ** ** **** * *
* * * * * ** * ** ** * *** ****** * * ** ** * * * *** ** ***
**** * * * ****** * ***** * * ****** *** ** * * ** *** * *** **** * ****** << counter2[i];
****** * ** * * ***** ** ** **** * * *** ** * ** ** *** * ***** ***
** * * **** * ** * ****** * ** * * * * * * * * **** * ** ** << " " << counter2[i];
        }
    }
}
answered by (-323 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Why??
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
1 answer
[Normal] Coding (C++) - asked May 17, 2018 in Introduction to Computer Programming II (C++)
ID: 52073 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users