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Question 10: Please write a program that can calculate tax 7% (0.07) of a product price, then outputs the tax and a total price including the tax.

Hint:

*Use %.2f for two decimal points*

*Printf a new line between the tax and a total price including tax*

Input1

80

Output1

5.60
85.60

 

Input 2

452

Output2

31.64
483.64

 

[Exam] asked in Final examination by (5.9k points)
ID: 41975 - Available when: Unlimited - Due to: 2018-01-17 16:30

edited by | 10k views

22 Answers

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Hidden content!
#include <stdio.h>
#include <stdlib.h>
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100/100 answered by (254 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (183 points)
0 0
prog.c: In function 'main':
prog.c:9:14: warning: unknown conversion type character '>' in format [-Wformat=]
     printf("%>2f", a*b);
              ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("%>2f", a*b);
            ^~~~~~
0 like 0 dislike
Hidden content!
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100/100 answered by (283 points)
0 0
prog.c: In function 'main':
prog.c:11:18: warning: format '%d' expects a matching 'int' argument [-Wformat=]
     printf("%.2f%d", a*b+a);
                  ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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0/100 answered by (192 points)
0 0
prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:12: warning: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^
prog.c:10:12: error: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^~~~~~~~~~~~~~~~~~
prog.c:10:5: error: expected expression at end of input
     printf("%2f\n%.2f,c,sum);
     ^~~~~~
prog.c:10:5: error: expected declaration or statement at end of input
0 0
prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:9:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (220 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     scanf("%d",a);
             ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("\n",b);
            ^~~~
0 0
prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.
0 0
prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.
0 like 0 dislike
Hidden content!
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100/100 answered by (221 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (183 points)
0 0
prog.c: In function 'main':
prog.c:7:14: warning: spurious trailing '%' in format [-Wformat=]
      printf("%\0.2f\n",a+a*0.07);
              ^
prog.c:7:15: warning: embedded '\0' in format [-Wformat-contains-nul]
      printf("%\0.2f\n",a+a*0.07);
               ^
prog.c:7:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\0.2f\n",a+a*0.07);
             ^~~~~~~~~~
0 like 0 dislike
Hidden content!
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answered by (183 points)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: unknown conversion type character 0xc in format [-Wformat=]
      printf("%\fn",a+a*0.07);
               ^
prog.c:8:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\fn",a+a*0.07);
             ^~~~~~
0 like 0 dislike
Hidden content!
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100/100 answered by (273 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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