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Question 10: Please write a program that can calculate tax 7% (0.07) of a product price, then outputs the tax and a total price including the tax.

Hint:

*Use %.2f for two decimal points*

*Printf a new line between the tax and a total price including tax*

Input1

80

Output1

5.60
85.60

 

Input 2

452

Output2

31.64
483.64

 

[考試] 最新提問 分類:Final examination | 用戶: (5.9k 分)
ID: 41975 - 從幾時開始: 無限制 - 到幾時結束: 2018-01-17 16:30

修改於 用戶: | 6.3k 瀏覽

22 個回答

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內容已隱藏
#include <stdio.h>
#include <stdlib.h>
int main(){
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100/100 最新回答 用戶: (254 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(){
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}
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最新回答 用戶: (183 分)
0 0
prog.c: In function 'main':
prog.c:9:14: warning: unknown conversion type character '>' in format [-Wformat=]
     printf("%>2f", a*b);
              ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("%>2f", a*b);
            ^~~~~~
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內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(){ * * *** *** * * *** **** ** ** *
*** * ** * ** * * * * a;
* ** * ** * **** *** *** b=0.07;
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* * * * ** * ******* ** * * ** ** * (a*b)+a);
* ** ** * ** *

** ** ** *** *** * *** 0;
}
100/100 最新回答 用戶: (283 分)
0 0
prog.c: In function 'main':
prog.c:11:18: warning: format '%d' expects a matching 'int' argument [-Wformat=]
     printf("%.2f%d", a*b+a);
                  ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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內容已隱藏
#include ** * * * **
int main()
{
*** **** * * * * * ** * n;
* **** ** * * ****** * ** * sum,c;
* * ** * ** * * ** * * **** ** * * ****
* ** ** ** * * = n*(0.07);
** ** * *** * * * = n + c;
**** * * ** * *** *** ****** * * * * ***** ** *
  
0/100 最新回答 用戶: (192 分)
0 0
prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:12: warning: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^
prog.c:10:12: error: missing terminating " character
     printf("%2f\n%.2f,c,sum);
            ^~~~~~~~~~~~~~~~~~
prog.c:10:5: error: expected expression at end of input
     printf("%2f\n%.2f,c,sum);
     ^~~~~~
prog.c:10:5: error: expected declaration or statement at end of input
0 0
prog.c: In function 'main':
prog.c:7:17: error: 'n' undeclared (first use in this function)
     scanf("%d",&n);
                 ^
prog.c:7:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:9:5: error: expected declaration or statement at end of input
     printf("%.2f\n%.2f",c,sum);
     ^~~~~~
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內容已隱藏
#include <stdio.h>
#include <stdlib.h>

int main(){
* ****** * *** * * * a;
** * ****** * ** ** *** * *** b=0.07;
* ** *** ** ** **
** * ******* * * ** *** * * ** ** * * &a);
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* ** ** * *** * * * **
** * * * **** * **** ** ** ** ** * * * **
* * *** ** ** ** * * 0;
}
100/100 最新回答 用戶: (153 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include ** * * * * *
#include *** * * * ** *

int main(int argc, char *argv[])
{

* ** ** ** ** * a;
** * *** * *** **** b=0.07;
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** * * ** ** * * * *** ****** *** ** *** (a*b)+a);
*** ****** ** ** * ** ** * **** * * * *
* * ** *** * ********* 0;

}
最新回答 用戶: (220 分)
修改於 用戶:
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
     scanf("%d",a);
             ^
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("\n",b);
            ^~~~
0 0
prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.
0 0
prog.c:1:19: fatal error: cstdlib: No such file or directory
 #include <cstdlib>
                   ^
compilation terminated.
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內容已隱藏
#include <stdio.h>
#include * * **

int main(int argc, char *argv[]) {
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* * ***** ** *** *** p,tax,total;
*** * ** ** * * * * * ** ** ** &p);
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* * ** * * *** *** * *** * ** *** * ** *
***** ** * * *** ***
    * * ***** ** **
* * * *** ****** **** 0;
}
100/100 最新回答 用戶: (221 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
* ** ****** * ** *

int main () {
* **** ***
* * * * * a; ******** ******* *
** ** * * * * * * * * * * * * %0.2f\n", a*0.07);
* ** * * * *** * * * * * * *** *** * * ***
* * ** ************ *** * * 0;
}
最新回答 用戶: (183 分)
0 0
prog.c: In function 'main':
prog.c:7:14: warning: spurious trailing '%' in format [-Wformat=]
      printf("%\0.2f\n",a+a*0.07);
              ^
prog.c:7:15: warning: embedded '\0' in format [-Wformat-contains-nul]
      printf("%\0.2f\n",a+a*0.07);
               ^
prog.c:7:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\0.2f\n",a+a*0.07);
             ^~~~~~~~~~
0 喜歡 0 不喜歡
內容已隱藏
*** * ** ** * **
#include **** * **

int main () {
* * * * ****
** ******** ** * * a; * ** * ** ** * *
* *** * *** ** * ** ****** *** ** * *** %f\n", a*0.07);
*** * * ** * * * * * **** *** * ** ** * * *
* * * *** * * * * 0;
}
最新回答 用戶: (183 分)
0 0
prog.c: In function 'main':
prog.c:8:15: warning: unknown conversion type character 0xc in format [-Wformat=]
      printf("%\fn",a+a*0.07);
               ^
prog.c:8:13: warning: too many arguments for format [-Wformat-extra-args]
      printf("%\fn",a+a*0.07);
             ^~~~~~
0 喜歡 0 不喜歡
內容已隱藏
#include * ** *** * *
#include * * ** *

int main(int argc, char *argv[])
{

** * a;
 
* **** **** * *** * * **
* ** * **** * ** **** * * ***
*** * ** * **** ** ****** ***
** * * * **** * * * ** ** * * * * * * * * * * * * ****** * * ** ** ***
* * ** *** * * * ***** ** ** * * * *  
****** *** 0;
}
100/100 最新回答 用戶: (273 分)
修改於 用戶:
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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