[Exercise 16] Arrays: Bubble-sort

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Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited | 5.8k views

46 Answers

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Hidden content!
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100/100 answered by (281 points)
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0 0
Case 0: Wrong output
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Case 2: Wrong output
Case 3: Wrong output
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(){
    int number[5]; 
    int size = 5, temporary,i,j; 
    
    for(i=0;i<size;i++){ 
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}
100/100 answered by (290 points)
edited by
0 0
prog.c: In function 'main':
prog.c:11:24: error: 'i' undeclared (first use in this function)
     for(int j=0;j<size;i++){
                        ^
prog.c:11:24: note: each undeclared identifier is reported only once for each function it appears in
prog.c:13:45: error: expected ')' before '{' token
                     if(number[i]>number[i+1]{
                                             ^
prog.c:18:13: error: expected expression before '}' token
             }
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:12:24: error: 'i' undeclared (first use in this function)
     for(int j=0;j<size;i++){
                        ^
prog.c:12:24: note: each undeclared identifier is reported only once for each function it appears in
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(){
  * **   * *  * *** *  *  number[5];
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  return 0;
}
100/100 answered by (271 points)
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commented by (4.3k points)
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Hidden content!
#include <stdio.h>

int main(){
 * *  **** ***   ***  *** **  *   number[5]; // Do not change
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 ***  *** *** *  ***   *  * i=0;i<size;i++){ // Do not change
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}
100/100 answered by (192 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main(){
*  **  * *** *   ** **  ** number[5]; // Do not change
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}
100/100 answered by (254 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
commented by (4.3k points)
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Hidden content!
#include <stdio.h>

int main(){
    int number[5]; // Do not change
    int size = 5, temporary; // Do not change
    
    for(int i=0;i<size;i++){ // Do not change
          ** ***      ****    *   *   ****   * // Do not change
    } // Do not change

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}
80/100 answered by (227 points)
0 0
prog.c: In function 'main':
prog.c:15:47: error: 'temp' undeclared (first use in this function)
                                               temp = number[i];
                                               ^~~~
prog.c:15:47: note: each undeclared identifier is reported only once for each function it appears in
commented by (4.3k points)
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Hidden content!
#include <stdio.h>

int main(){
*** *   *    *         *    *** number[5]; // Do not change
    ***** **  **  ** ** ***  size = 5, temporary; // Do not change
* ***** *  *  * **   *** * * *    i=0;i<size;i++){ // Do not change
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  return 0;
}
100/100 answered
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
commented by (4.3k points)
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Hidden content!
#include <stdio.h>

int main(){
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*      * *  *** *  * * *  **   ** size = 5, temporary; // Do not change
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 ******* *****  *   ** ****  *****  **
  return 0;
}
100/100 answered by (183 points)
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
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Hidden content!
for(int  ***  * *     
 ** *   * *  **  * * *  **  * for(int **    *      * *
  **** **   *     * * *    *        *** * ***   ******  *     ***
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**  ***    **  ** **  *  ***  *      **  *** *  * *   **** 
* * *      ** }
50/100 answered by (244 points)
0 0
prog.c:1:1: error: expected identifier or '(' before 'for'
 for(int i=0;i<size;i++){
 ^~~
prog.c:1:14: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
 for(int i=0;i<size;i++){
              ^
prog.c:1:21: error: expected '=', ',', ';', 'asm' or '__attribute__' before '++' token
 for(int i=0;i<size;i++){
                     ^~
prog.c:11:2: error: expected identifier or '(' before 'for'
  for(int i=size-1;i>=0;i--){
  ^~~
prog.c:11:20: error: expected '=', ',', ';', 'asm' or '__attribute__' before '>=' token
  for(int i=size-1;i>=0;i--){
                    ^~
prog.c:11:25: error: expected '=', ',', ';', 'asm' or '__attribute__' before '--' token
  for(int i=size-1;i>=0;i--){
                         ^~
commented by (4.3k points)
0 0
It's missing a header which is #include
commented by (5.9k points)
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Hidden content!
#include *   *  ***** **

int main(){
 **  ** * * **   int number[5]; // Do not change
** * *   int size = 5, temporary; // Do not change
         *  
    for(int   ***  *** **     * // Do not change
** **       *** *    * * *   *  ** ** **    * *** // Do not change
* *    ** **** } // Do not change

 ** **   // Your conditions start from here

* * *   * **** j = 0; j < size; j++){
**  *    *  ***    **   ** *   * *** *   ***   ***  i = 0; i < size-1; i++){
** * *     * * * * * ***      ******* ***  *  ** ***  *  * *  *     ** *   * ***  >  *      *
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******     *** * *  ***** 
 * * * *  * *  return 0;
}
100/100 answered by (221 points)
0 0
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Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
commented by (4.3k points)
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