0 like 0 dislike
17k views

Write a program that asks the user to type an integer N and find out all the factors of N and display it on screen.

寫一個程式 輸入一個整數N,找出N的所有因數

Example input 1

10

Example output 1

1 2 5 10

Example input 2

24

Example output 2

1 2 3 4 6 8 12 24

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 17k views

72 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int N,a=1;
*** * * * * ** ** *** *** **** ** ** * *
* **** * * *** * *** ** **
    {
** * * * * * ** ** ***** ** * * **** * ** ** ******
* * * * ** * * * * *** * *** * ** *****
****** * * * ** * *** * * * ** * * ** * *** * ",a);
* * **** * *** *** * *** ******* ** **** * * ***** * * * ******* ** ** **
** ** ** *** *** * *** *** *** ** * ******* * * **** * * ** *** **
* *** ***** * * ** **** * * * * **** **** *** **** * ** * **** ** * ***** * ** * * * * *** ");
**** ** * * ** * * **** ***** ****** *** *** *** **** * *
* ** *** * * *** * **** * * ** ** * *** *
** ** * ** *** ** ** * ***** * * **** * * **** **** ** * ** ** **


    }
    return 0;

}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main() {
    int a,i,j,first=0;
* ** *** ** ** ** ** * **** *** ******* * * &a);
** ***** ***** *** **** * **** * * * {
** *** *** ** * * ** *** * ** * ** *** * * * * * * * * ** {
** * * * * *** ** ** ***** * * * ** * * ** ** * ** * (first!=0) {
** ** ** ** * * * ** * * * *** * * * **** ** * ** *** * ***** ** * * * ******** * ** ");
* * * ** * ** * * * * **** * * ** ** *** ** * ******* *
* * * * ** *** * * * *** * * **** ** **** * ****** * * * ***** i);
** * * ** *** * * * ** ** ** *** * **** * *** * *** * * ** *
* ** * ** **** ** * * * * ** ** * *
    }
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
** * *** *

int main()
{
** **** ** * * * * * * a,b;

* ****** *** *** * * * ***** ***** * * * * * *
**** **** ******** * * * b=1; b<=a; b ++)
** * **** * *** *** **
****** ** * * * *** ** * *** ** **** * *** *** ==0) printf("%d ",b);
**** ** ** *** **** **** *
** *** ** ******* * ****** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main ()
{
* ****** ** * *** * * * * n,i;
** *** **** ******* ** * * * *** * *
* * ** *** * ** ** ** ** * * **** ;i++)
**** * * ** **** **** * * **** * * **** * * *** (n%i==0)
* ******* * *** **** * ***** ** * * * *** *** ** ",i);
**** **** * * *** * * 0;
}
answered by (-196 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** *** ** ** * * * *** i,n;
** * ****** * * * ** * * * * *** * * ** *
** *** * * * ** * *** * *
** ** * ** *** ******* ** **** **** ***** *
*** ** * * **** **** ** ** * * * * * ** ***** * ** *** ",i);
}
answered by (-323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(){

* ** * * *** ** * * * ** ** * a,i,c=0;

** * ** ** **** * * * *** * ** **
** ****** *** ***** *** * ** * *** **** ***** *
* *** * ** ** * **** ** **** * * ***** ** ** **
***** * *** **** * ** * * ** **** * ** * **** * *** * * ** *** * *
* ** *** *** * * ** **** * ** * **** * *** * **** ****** * *** * ** ** *
*** * ** ******* *** * ** *** * *** * * * ***** * * **** * ******* ***
** ** * ** **** * * ** ***** * * * *** * * ** ** * ***** *** * * *** * ** printf(" %d",i);}


     }





return 0;
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>

int main(){

** * * * * ** * * * * * ** a,i;

***** **** *** *** * * **** * ****** * * ** * * ** ** **
* ********** **** * ** ** * ***
* *** **** *** * * * **** ***** * *** * * ** * ** * ** ** ***
**** ** * ***** * ** * ** ** *





return 0;
}
answered by (-301 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** * ****** *

int main(){

** ***** * ** * ** * ** ** ** ** a,i;

* ** ** * **** ** * * *** * * ** *** ** * * * ** **
* ** ***** ** *** * * *** **** ***** **
***** ******** ** * *** * *** **** * * * ** ** * *** ** **** ",i);
** * ** * *** ***** *





return 0;
}
answered by (-301 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * **
#include <math.h>

int main ()
{
int i,n,j;
* * ** * ** * ** * ******
***** ***** ***
{
* * ** * ** ** *
{
if(i*j==n){

* * * * * * * * * ** *** * ** * * ** * * ** *** * *** * ***** ***** ** *** * ** * *** *** * ** * ** * * {
* *** * * * ***** ** * ** * ** ****** *** * *** ** **** ********* ** * * ** * * **** ****** **** * ",i);
* * ** ** ** * *** ***** *** **** * * ** *** * ** * ** ** * **** *** * * * *** ** ** * * * * **** ** **


** ** ***** * ** * ** * * * *** * *** * *


}
}
}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main ()
{
int i,n,j;
* * **** * * *
* ** *** *
{
** **** * ***
{
if(i*j==n){

* *** * ** * ***** * * ** * ***** *** ** * * ******* * * ***** ****** * ***** *** ***** * *** **** ***** {
** * **** ** *** ** ** * * ***** ***** *** * * ** **** * * * *** *** * ** * * ** * * ******* *
*** ** ***** ** ********** * * ** * ****** * * ****** *** ****** * * * ** **** *** ** *** * * * * * *


* * * * * ** * *** *** ** ** * * * ** ** *


}
}
}
answered by (-336 points)
0 1
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 24.9k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 22.5k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 17k views
12,783 questions
183,442 answers
172,219 comments
4,824 users