[Exercise 7] ASCII Identification

Question

3.7k views

Please write a program that can identify a value's characteristic based on ASCII table. It must identify:

0-9 is a digit
A-Z is a capital character
a-z is a small character
Besides those conditions, it shows '%c is unknown'.

Kindly use the given template to finish the task. Be advised that your outputs must be exactly the same as the shown outputs below.

Example(Template)

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	char a;
	printf("Define:\n");
	scanf("%c",&a);
	
// Your condition starts from here
	
	return 0;
}

Input#1

Define:
6

Output#1

6 is a digit

Input#2

Define:
A

Output#2

A is a capital character

Input#3

Define:
f

Output#3

f is a small character

Input#4

Define:
/

Output#4

/ is unknown

Suggestion

It's time to use your favourite table: ASCII

[Exercise] Coding (C) - asked Oct 27, 2017 in Chapter 3: Branching, Looping and Functions by nat236919 (5.9k points)
ID: 29618 - Available when: Unlimited - Due to: Unlimited | 3.7k views

17 Answers

Page:

YT Chiu · Answer 1 · 2018-01-12 22:25:09

Hidden content!
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}

100/100 answered Jan 12, 2018 by YT Chiu (221 points)

Baigeldiev · Answer 2 · 2017-12-15 01:29:49

Hidden content!
#include ****      * ***** 
* *    *  * * * ***** * *  

/* run this program using the console pauser or add your own getch,  ******* ******* *  **** or input loop */

int main(int argc, char *argv[]) {
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}

50/100 answered Dec 15, 2017 by Baigeldiev (183 points)

Baigeldiev · Answer 3 · 2017-12-15 01:28:20

Hidden content!
#include <stdio.h>
#include  *  * *  ** * * 

/* run this program using the console pauser or add your own getch, ** ** **            or input loop */

int main(int argc, char *argv[]) {
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***** *    **   ***  **
**** *   *** *  ** *** ** *   *** 0;
}

answered Dec 15, 2017 by Baigeldiev (183 points)

The Judge · Answer 4 · 2017-12-14 11:46:02

Hidden content!
#include *  ** * ***    ****
 ****    ** *** *  * *    

/* run this program using the console pauser or add your own getch,  ***      **   * * * or input loop */

int main(int argc, char *argv[]) {
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}

100/100 answered Dec 14, 2017

Namuun_1029 · Answer 5 · 2017-12-13 15:36:09

prog.c:28:2: error: stray '#' in program
}#include <stdio.h>
  ^
prog.c:28:11: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
}#include <stdio.h>
           ^
In file included from prog.c:29:0:
/usr/include/stdlib.h:826:20: error: unknown type name 'wchar_t'
extern int mbtowc (wchar_t *__restrict __pwc,
                    ^~~~~~~
/usr/include/stdlib.h:830:31: error: unknown type name 'wchar_t'
extern int wctomb (char *__s, wchar_t __wchar) __THROW;
                               ^~~~~~~
/usr/include/stdlib.h:834:25: error: unknown type name 'wchar_t'
extern size_t mbstowcs (wchar_t *__restrict __pwcs,
                         ^~~~~~~
/usr/include/stdlib.h:838:10: error: unknown type name 'wchar_t'
    const wchar_t *__restrict __pwcs, size_t __n)
          ^~~~~~~
prog.c:33:5: error: redefinition of 'main'
int main(int argc, char *argv[]) {
     ^~~~
prog.c:5:5: note: previous definition of 'main' was here
int main(int argc, char *argv[]) {
     ^~~~

Bilegjargal · Answer 6 · 2017-12-13 15:15:27

Hidden content!
#include           ****
#include * *    *** ** ** **

int main(int argc, char *argv[]) {
*  * *   *  *** * **** ****   * a;
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*  * * ** * * ** *      **   *** *  *   *** * **  * *  ***    *   %c is unknown", a);

 ****  * *** **       **  *  **   ****** **  ** *   * * 
   ***  * * ** ** *     *  * **
*   **   * *   ** *   **** **     **** 0;
}

100/100 answered Dec 13, 2017 by Bilegjargal (220 points)
edited Dec 14, 2017 by Bilegjargal

lee,jiun-hong · Answer 7 · 2017-12-12 22:45:33

Hidden content!
#include<stdio.h>

int main(int argc, char *argv[]){
 * **  * *  **  **** ****  ** *  **  a;
*  *** **** **** **  *  ** *  *  ***       ** **** 
* **     * **** * *   * ****  *  * *** *** *    &a);

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*   * ***  *** *** ******  * **  **      *     * *******     * *      is a digit", a);
 *   ** ***  * *  ** *  * *   *
        ** ***    ** * ** ******  **   *  *      **  *  *** * {
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* *  *    ***      * *  **  *  * *    * ** *** * **     * {
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 * * ***   ***** ***       **
   **** *** *   *   *** * *  {
* ****    ****   *  ** * *   ***        ****  * **     **  ***   *  is unknown", a);
*  *******     **    **  *  
}

100/100 answered Dec 12, 2017 by lee,jiun-hong (273 points)

410630017 · Answer 8 · 2017-12-10 21:42:41

Hidden content!
  *  *** * * * * *
   *   ****  *** *  * *

*  * * * *  *       *    * * *  * or *      * ***    *   * *   ****    * *  or *** ** */

*** * ***   *   *   *** * {
*       ** *  *   c;
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* *   ** *** **  *   ** ****
**  **  **   ** 
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**  * ****       
*      *  *    if( c *   * * '0'  ** ***** ** c   *    '9' ) // we * * all the     * are in      ****  in the      * 
* ** *    **    ** ***  **   **   * *** **** * ***** * %c is a  *  **** *  c);

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* *     *    * *    * * * *  **    
* **  *****   c       ** ** *** * **  c *  'Z' ) // c is a  *  *  * 
***    *  *  *   ** *   *     ** 
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  *   * **        ** ** ** ** * 
* * *  *  ** *   == **
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*** * *      *      * ** **     * * 
  * *  *  ** * 
   *     *      ** *  0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)
reshown Dec 17, 2017 by nat236919

410630017 · Answer 9 · 2017-12-10 21:42:38

Hidden content!
****   *** * *    ***
  * ***  **** *******  

*   ** *   **   ** *  **   **** ***** or **  * *         ** *  *  * * or **   * */

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 * *** *  **     * c;
   * *   ***  *  ** *   **
 *** ***       **  **   *    * 
*        *  ***      * **
**       **  *  
 * ***    **   /*  ** **  **  * = is * ** *  *  * * == */
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* **      * *   
*  *    **   * ****  **  **    is %c **  *  * ** c);
     * * * 
*       * *  * if( c  **    '0'     *   ** c   * * '9' ) // we    all the **    are in ** * **  in the     *
     **  **  **   ***   ** * * ***     ******  %c is a     ***  * c);

  * *   * **   * 
** *  ** *  *  if( c  * ****  'a'  * ******** * c      'z' ) 
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  ** ***         ** * *   *   *  
* **   * **** *** * ** ****   
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*     *  *    ** **     *  ***  
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******    *  *    ** *  *       * 
** *** * *    *  ** == ***
     **  ** * 
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**** * *   **    ***    * * * *  
 ** ** ***    
 *  ***  ***  *  * *** 0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)

emilie · Answer 10 · 2017-11-01 15:12:05

Hidden content!
 * *     *   * *  * * *
     *  * * * *     * *

/* run this  **    * the  * *  *  * or add your own  *  *  * *** * ** ** ** * **  * or input loop */

int    *   ** * char  * *  {
*  ******  **** ** char a;
**   ***  *  * *** ** *  * * ** * *  *  ** * *
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* *    *  *  *  
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* *****  ***  *  *** * ** * *      * *   *  is a    *** *** ** a);
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** *** **  *** else *   **
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   * **  *  *   }
  * * **   else *     *** 
*** **  **   ** *  * * ***  *    ** ** **    is a ***   * **    * ** a);
* *    ** ****** }
 * ****   * **** else{
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 **  *    ***  }
// Your  ***  *    *  from here
    ***  * * ******  
*      **  **  * ** ** 0;
}

100/100 answered Nov 1, 2017 by emilie (290 points)
reshown Dec 17, 2017 by nat236919

[Exercise 7] ASCII Identification

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