[Exercise 7] ASCII Identification

Question

4.6k views

Please write a program that can identify a value's characteristic based on ASCII table. It must identify:

0-9 is a digit
A-Z is a capital character
a-z is a small character
Besides those conditions, it shows '%c is unknown'.

Kindly use the given template to finish the task. Be advised that your outputs must be exactly the same as the shown outputs below.

Example(Template)

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	char a;
	printf("Define:\n");
	scanf("%c",&a);
	
// Your condition starts from here
	
	return 0;
}

Input#1

Define:
6

Output#1

6 is a digit

Input#2

Define:
A

Output#2

A is a capital character

Input#3

Define:
f

Output#3

f is a small character

Input#4

Define:
/

Output#4

/ is unknown

Suggestion

It's time to use your favourite table: ASCII

[Exercise] Coding (C) - asked Oct 27, 2017 in Chapter 3: Branching, Looping and Functions by nat236919 (5.9k points)
ID: 29618 - Available when: Unlimited - Due to: Unlimited | 4.6k views

17 Answers

Page:

YT Chiu · Answer 1 · 2018-01-12 22:25:09

Hidden content!
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}

100/100 answered Jan 12, 2018 by YT Chiu (221 points)

Baigeldiev · Answer 2 · 2017-12-15 01:29:49

Hidden content!
#include   *  *  ********
  *      *     ***   *

/* run this program using the console pauser or add your own getch,  ****    **    *** ** or input loop */

int main(int argc, char *argv[]) {
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**  *** *  *   **** ****      *    
 ** ****  ***    * *  ** * *  
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****   *  * *    *  *** * *  * c * *    '0' *  ***    c <= '9' ) // we know all the digits are in some range in the ascii table
**** **  * *   *         ** *    *       * ****  ***  ***  *****   * * **   %c is a  ******** ** c);

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** **  ** ** *  ** ****** ** ** **
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}

50/100 answered Dec 15, 2017 by Baigeldiev (183 points)

Baigeldiev · Answer 3 · 2017-12-15 01:28:20

Hidden content!
#include <stdio.h>
#include  *    * **        

/* run this program using the console pauser or add your own getch,   *  *** * *   *    *   or input loop */

int main(int argc, char *argv[]) {
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* *  **   * * ** *** *     *
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*    *  **  * *   **** *  *
*    * * ** *  *  ** ** *
****** * ** *** ** *  ***** 0;
}

answered Dec 15, 2017 by Baigeldiev (183 points)

The Judge · Answer 4 · 2017-12-14 11:46:02

Hidden content!
#include *    * *    *   *
****   * *   ***     **  *

/* run this program using the console pauser or add your own getch,    *  *  * *  *  *   * * or input loop */

int main(int argc, char *argv[]) {
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    * * * * ** * *  ** **** **  ** * * * * * *  *    *  *** 
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*** * *   * ****    * *   
   *   ****  * *  * ***      * ** 0;
}

100/100 answered Dec 14, 2017

Namuun_1029 · Answer 5 · 2017-12-13 15:36:09

prog.c:28:2: error: stray '#' in program
}#include <stdio.h>
  ^
prog.c:28:11: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
}#include <stdio.h>
           ^
In file included from prog.c:29:0:
/usr/include/stdlib.h:826:20: error: unknown type name 'wchar_t'
extern int mbtowc (wchar_t *__restrict __pwc,
                    ^~~~~~~
/usr/include/stdlib.h:830:31: error: unknown type name 'wchar_t'
extern int wctomb (char *__s, wchar_t __wchar) __THROW;
                               ^~~~~~~
/usr/include/stdlib.h:834:25: error: unknown type name 'wchar_t'
extern size_t mbstowcs (wchar_t *__restrict __pwcs,
                         ^~~~~~~
/usr/include/stdlib.h:838:10: error: unknown type name 'wchar_t'
    const wchar_t *__restrict __pwcs, size_t __n)
          ^~~~~~~
prog.c:33:5: error: redefinition of 'main'
int main(int argc, char *argv[]) {
     ^~~~
prog.c:5:5: note: previous definition of 'main' was here
int main(int argc, char *argv[]) {
     ^~~~

Bilegjargal · Answer 6 · 2017-12-13 15:15:27

Hidden content!
#include  * ** ****  **
#include  * *    ***  **  

int main(int argc, char *argv[]) {
*     *** **    ***   *****   * a;
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* *   *** * * ** ** ** ****
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*     ** * * * **    **** *** **  *   **** *    *
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*  *** ****  *  ****  *  *** **     ** *  *      *  *** **  %c is unknown", a);

 * *** *    **  **  * *   * *  **        ***   *
*     ****  * *  ** ** *      
*    * * *** *** *  ***** 0;
}

100/100 answered Dec 13, 2017 by Bilegjargal (220 points)
edited Dec 14, 2017 by Bilegjargal

lee,jiun-hong · Answer 7 · 2017-12-12 22:45:33

Hidden content!
#include<stdio.h>

int main(int argc, char *argv[]){
* **  ***  **  ** * ** *     **  ** *** a;
 ****    *  **  ** * * **  ****** *** ***  **   
  *** *** ** *  *    * *** **     *    ** *    * * &a);

 * *** **** *  ** **  *   ****   **** ****  * * *  *    * {
  **  ** ** *  ***  * * **** *  *    * *  *   *    ***** *  * ** is a digit", a);
  *** *  **  **** *  *   **  ** 
    ****** ** * ****** *  *** **  * * * *    * ***  ** *   * * * *  {
  **     ** **       * **   *****  *  ** ***   *  * *  ** ***  is a capital character", a);
** **** * ** ****     *  **   
*  **  *    ** ** **** * * **  *  *** *** * ********  * ***  {
 *   * * **  ** *   * * **  *** * * ** **** ** ** * ***  *  **     ** is a small character", a);
  ***** **   *** ***  * ** * 
  *      * ***** ***  *  * * {
** * ** *     *    ******* * *  *** * ***  ******** * * * **  * **   is unknown", a);
 * * ** **** **  *  * ***   
}

100/100 answered Dec 12, 2017 by lee,jiun-hong (273 points)

410630017 · Answer 8 · 2017-12-10 21:42:41

Hidden content!
*   **   **  ******* *
 *    ******   ** *

 *  ** *  *  *   ***  * *     **  or     *** *      *        *     *  or **  * *  */

**  ** * * *        **   {
* ****  * * **** ** c;
 *  *   * * *  * **  
**  *    *   *  ***  * *
******     * *  * * *  ***
  *    *    
** **** *** *  /*   * ****   ** * = is *  **  *      **** == */
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**    **   * *    
*   **  *  *** if( c  **** *   '0'  ****  *   *  c * ** *** '9' ) // we * *  all the     * are in **  ** in the **    * 
   * **  ** * ***   *  * * **    ** *** *   **  %c is a **  *  **  ** c);

**   *    ***** * 
* **    *** if( c  *  *** 'a'  ** * **  c     *  'z' ) 
          * **  *   *    ******  *    *   *   **** * %c is a    *   ******  c );

*** *   ****  **   ** **  
 **  *   *  * *  * *     ** **  
 ***    **** ** *  c  ***       * ** ** ***  c    **  'Z' ) // c is a  ***    *  
***** ** * *  *  *  *** ** ** *  
*   *      **   * *    ** *    * * * *** * *   %c is a    *      *   c );
* ***     * *   *** ** ** *  
* ***  * **  **  == **  
 *    *     * 
*               ***     *  **  *  ****  ** * *    * * ****** ** %c is   ****       *

**   ** **  **    ** * *       * 
  * ** * * ** 
*    * *  ***      0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)
reshown Dec 17, 2017 by nat236919

410630017 · Answer 9 · 2017-12-10 21:42:38

Hidden content!
* ***  *** * * ** * *   
** *     *  *** **  **  *

 **   * *   **   **  *   *  *   *  or  ** * ** *  * * * * *   **    *   **  *** or     */

 **  **   * * **   *   *  {
***    *** *    * c;
*        **** *   * *  ** 
****  *   *** *  * *   *
*  *  *  * ***  * *  **** **
****** *** *    *** 
*** ** * **   /* * *  **   *** = is ** ** *  *  == */
** *   **  *** c =  *   *
 * *  *   * *** * 
* * * **  ***   *   * **     *  * **     is %c ****** *  c);
** **  *    **** 
   *   * * *   if( c  **  * '0'  **** ***** ** c   *  * '9' ) // we   all the *** are in ***  * * in the  ***    * 
**   *     **   ** * ** *   *  *  *  ** * *   *** %c is a  **   **   c);

**    * ** *  * 
** * * * *     if( c * ***  'a'  * *  *    * c *  **  'z' ) 
**    **** * **** *  *     *     *  * * *   * %c is a    ***  * *** c );

*     * *     *   * *** * *     *  
 *** *** *   ***  **** 
** *     * * *   c  * * * *  *  *   **  c ** * 'Z' ) // c is a ***  *    
 ******* **  *  *  * **** 
***** * ** ***  * * ** *     *  *  *   **  *  * * * %c is a    ******  *   c );
 * *        *** * *    *     
    *** * ***** * == ***
*   *** ****** 
   ** * **   *** *    * *    *** * **    ** ****  *** %c is   ******   *  

*     * *** *   *    * *  * * 
      *   ** * 
 ***   **   **  *  * 0;
}

100/100 answered Dec 10, 2017 by 410630017 (153 points)

emilie · Answer 10 · 2017-11-01 15:12:05

Hidden content!
****** ****    * *  * * 
*  * *  *    * **  * ***

/* run this  *   * **   the *** *   **  or add your own  ***  *** **   *  ***    or input loop */

int ** * * * char *   {
**** * * * * **   char a;
*   **     ** ** *** * **   * ***   * *  
 ******  ***   * *  *  ****   * ** ** **** *  * **** ***
     *** * *  *  * 
 *  * ***** *** ** *  ** *
   **** *      **  * ** **  * *  *** * *   is a *    **   * a);
 *****    *   ** }
**   * *   **   else   *  * *  
 ******* * * *    **   **    *    * *   * *   **  is a      *** **   * a);
* **      * * }
    ** *  else  ********
* **** *   **     *  * * *  *   **    * is a  ** *** **   * *** a);
**  *   ****  }
*     *     **  else{
  **   **  ** * **  *   * * ** *  * * ** * is **   *  *    
 ** *     ***  }
// Your **  * *   * from here
  *     * * 
***** *        ** 0;
}

100/100 answered Nov 1, 2017 by emilie (290 points)
reshown Dec 17, 2017 by nat236919

[Exercise 7] ASCII Identification

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