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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 2.2k views

23 Answers

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Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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** ** ***** * * ch,xh;
** ** ** ** ** ** ** * a[100],c[100];
** * * * ** ** * b[100],d[100];
**** * * * * * *
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* ** *** ** ***** *
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** *** * * * ** **

    
* * ***** ** * * * *** * * * ** * *
** ** *** * ** ** *** * 0;

}
answered by (122 points)
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Hidden content!
#include * * ******

#include ** * ***

#include * ** * * * *** *

#include ** * * ** **



int main(void){
*** * ** * ***** * * **** *** ** **
* * * * *** i = 0;

  
* ** * * * *** * * * ** * *

  
* * * * * **** ** ** != '\0';i++)
* ** ***** * ** * ** * *** ** * * = tolower(c[i]);
* ** * * *** * ** * = '\0';
* *** * * * ** ** ** ****** * ** * *
***** * **** ******** ** ** != '\0';i++)
* * ** * ** * * ** * ***** ** ****** *** = tolower(cc[i]);
* ** ** *** ***** ** = '\0';
** ** *
** * * * * ** * ****** != NULL)
* ** ** * *** * ** ** * *** ** ** * is *** *** * ** * in * * *** ** * * *** **
* ** ** * *
*** ***** * **** * ** ***** *** * *** * * are no * * * * ** in * * *** * *** ** * *
* * ** ** * * ** *** * * * **
*** ** *
** * * * ** * ** * ** *  
* ** ***** * *** * * 0;

}
answered by (-216 points)
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Hidden content!
#include * *** * *

#include * * ****

#include * * * * *

#include * ** * ******



int main(int argc, char *argv[])

{
**** * * * **** ** ** * *** * *
* * ** ** ** i = 0;
* **** ****** **
* **** **** * *** * * * * * * *
** *** *
***** *** ** ** * * != '\0';i++)
*** ** * ** * **** ** **** * * ** ** = tolower(c[i]);
* * ** * ** * ** * * != '\0';i++)
* * *** **** ** * * **** * * = tolower(cc[i]);
* ** *
**** ** * ** *** != NULL)
** *** * *** * ***** ** ** * ** * ** is * ** ** ******** in * * * * * * * **
* * * *** * *
* * ** * * *** * * **** * * * ** * are no * * * *** in ** ** *** * ** **
* * ** * ** * ** * * * *

  
* * * * ***** * * * * *  
**** ** * * * 0;

}
answered by (-216 points)
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