0 like 0 dislike
3.1k views
子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3.1k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
* *** ** ** ** * ** * i=0,j=0,t;
** * * * ** * ** * ch,xh;
*** * ** **** **** a[100],c[100];
***** * * * ** * ** ** b[100],d[100];
*** ** * * * * *
* * ** * *** *** * * ** ((ch = getchar()) != 32) {

* * ***** * *** ** * * ** * **** ** ** ** = ch;
***** * *** * **** *** ** ***** ** **** **
* *** * ** * * **
**** ** *** *** *** * *
**** * ***** * * * * * * = getchar()) !='\n') {
** * * *** * * ***** * * ** *** * * ** *** = xh;
** * * * * ** *** ** * * ** * * ** *******
** **** ** * * ** * *
* * * * ** **** * *
*** *** **** * * * * * **** * {
***** ** * * *** * * *** ****** * * * ** **
*** * * * ********* *** ** ** *** * ** * * * ** {
** * *** * ** ***** ** **** *** ***** * **** * ** ** ******* *
*** * * * * * * * * ***** ** ** * ****
* * ***********
** * ** * * * * *
* ** * * * * * * * * ** ** * {
* * * *** ***** ** ** * * **** * ** *
**** ** *** ** * * ** ***** ** ** * ** * * * ** * {
*** ** ** * * * * * ** ***** **** ** * ******* ** ** * * * *** * **
* *** * ** *** * ** * * * * * * ** ** * * *
* * **** * ** * **   

    


** **** ** * * * ** * * *** {
* * ** *** * ** * * ** ***** * * ** ** * *** ** * *** ** * is \"%s\" in \"%s\"",d,c);
* * * *** ***** * * **
** ** ** * *** * * * *
***** ******* * * ** ** ** * {
***** ** *** * * ** ***** * *** * **** ** *** * **** are no \"%s\" in \"%s\"",d,c);
**** *** ** * **** * ****

    
* **** * *** *** * ** * *** ** * ** *** ***
* **** * * ** * * * **** * 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include * * ** *** * *

#include ****** ** **

#include *** **** * ****

#include ** * ***



int main(void){
** ** ** ** * * *** * ** ** *
** ****** ** ** i = 0;

  
* *** * * * *** * * * * * *******

  
** ** ** * * ** != '\0';i++)
** **** * * * ** * *** ** ** ** * = tolower(c[i]);
* * **** *** **** = '\0';
** *** * *** ** ** * * ******* *****
* ** ** ** * * *** != '\0';i++)
* ** *** ** ** * ******* * * *** * * = tolower(cc[i]);
* * **** * * * = '\0';
** * * **
** * * * ** **** ** != NULL)
*** *** ** * * ** **** * ** *** ** ** is *** * ***** ** in *** * *** * ** ** ***
* * * ***
** ** ** * * *** * ** * * * are no * *** *** in *** ****** * * * * ** ****
** * ** *** * *** *** ** ****
** * ** **
***** * *** * * ** **** ****  
* * * ** * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * ** *

#include ********** *

#include * * *** * *

#include ** * *** *



int main(int argc, char *argv[])

{
***** * ***** * * ** **** * *** *
***** * ***** i = 0;
****** *
* ******* * * * * * * * ** ***** **
** * * *
** * ** * * ** *** * != '\0';i++)
***** * ** ** **** ** **** * * * * * * = tolower(c[i]);
* ** ** * * ** **** *** * ** != '\0';i++)
* * **** ** * * * * * ** * *** * ** = tolower(cc[i]);
** *** * *
** * * ** * *** != NULL)
** ****** *** ** *** *** *** * **** **** ** ******* is * * ** ***** in **** ***** ** ** *** ** * *
* **** ***** **
* * ** * ***** **** * * *** * * ******** are no ** * * **** * in ** **** * *
** ** * ** ****** ** ** ** ** **

  
* * ** * * ********** **  
** * * * * * 0;

}
answered by (-216 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.59
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20299 - Available when: Unlimited - Due to: Unlimited
| 16 views
0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20297 - Available when: Unlimited - Due to: Unlimited
| 17 views
0 like 0 dislike
121 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 11.3k views
0 like 0 dislike
54 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13021 - Available when: Unlimited - Due to: Unlimited
| 6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users