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子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 2k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
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* * * * ** * ** **** * ch,xh;
* ** ** * *** * * * * a[100],c[100];
** * * **** ** * * b[100],d[100];
* * *** * **** *** *
* * ** * *** ** * * *** ((ch = getchar()) != 32) {

* * *** ** ** **** **** * ** ** * ** * * * ** * = ch;
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* ** * * ** ** * *****
** * *** * ** *** *
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** *** ***** ***
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*********** * ** ** *

    
** * * **** * ** ** **** * * *** ****
* * * ** **** * * * * 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include ** ** * ** *

#include **** * **

#include * *** ** ****

#include * * ** *



int main(void){
** * ** * ** * * ** * ******
** * **** i = 0;

  
******** * * ** * ** * ** * * * ** *

  
* * *** *** *** * ** * != '\0';i++)
**** * ***** * * **** ****** *** * * = tolower(c[i]);
** ********** ** * = '\0';
* * ** * * **** * ** * * ** *
* * * * * * * * != '\0';i++)
* ** *** * * * ** * * ** * = tolower(cc[i]);
* * * ** ** = '\0';
* * * *** *
* * * * ** ** * * **** != NULL)
* ** ** * * ******* *** ***** ** * * ** is * *** * * in * * ** ** ****** ** **
* * *** * *
*** * ** ** ** ** * ** * * * *** * are no ** * * **** in ** ** * * **** ***** *
* * * * * ** ******* **** * *
*** * * *
** * **** * ** ** *** * *** ****  
*** *** ******* 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include **** ** *

#include ** *** *

#include * * ***

#include * * ****



int main(int argc, char *argv[])

{
** * * * * * * *** ** * ** ****
** ** * ** * ** i = 0;
** ******* **
***** * * * * * ** **
** * ** * **
** * ** * * * * ** ** ** != '\0';i++)
** *** *** ** * * * **** * * ** ** * = tolower(c[i]);
*** ***** **** * ** **** != '\0';i++)
** * *** ** * **** ** * ***** *** = tolower(cc[i]);
** * * * * * ** *
* * **** **** * * * != NULL)
******* * * *** *** * * *** * * * * is ***** ** ** ** in ***** * * *** *** ***
* * **
* ** * *** ***** * * *** * ** **** are no * * ** * * * in * * ***** * ** * *
* * ****** * * *** **** * **

  
***** ****** * * * * * * *  
* * * * * **** * 0;

}
answered by (-216 points)
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