0 like 0 dislike
3.3k views
子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3.3k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
* * *** * ** ** * *** * i=0,j=0,t;
* ** ** ** ***** * **** ch,xh;
* *** * * * * * * * a[100],c[100];
****** * **** *** *** b[100],d[100];
**** * * * ** ** * **
** * * ** ** * *** * * ((ch = getchar()) != 32) {

**** * *** *** ** ****** ***** *** * * *** * = ch;
** * * ********* * **** ** * * * * ** * ***
**** **** **** * ***** **
**** **** * * * * ** **
* * * *** ** * * * = getchar()) !='\n') {
******* **** **** * ** ** ** ** **** * * *** ** *** = xh;
* **** * ** ** * ** *** ** *** ** *
** **** * * * * *
*** ** ***** * ** * * *
*** ** *** * * ******* * * ** {
* ***** * ** ********* * ** *** * * ***** ** * **** **
** ** *** *** * * *** ** * ** ****** *** ** * * {
** * * ** *** * * *** *** * * * **** ***** * ** ***** * ***
** * *** ** ** * **** * ** * * * * ***
* ** **** * * * *
** ****** ** ** * ** *
** ** * ** * *** * ** ***** {
** *** * * *** ***** * * ** ** ** * ** * **** *** *
***** * * ** ***** * * *** *** ** * * ** * **** * {
* ** * ** * * ** ** *** *** ** ******* ** * ** ** *
* * * ** ** ** * *** * * * *** ** * * **
* **** * *** * ** *   

    


* * * * **** * * * ** * * ****** * ** {
** * **** *** * ***** ** ** * **** * *** * **** ** * is \"%s\" in \"%s\"",d,c);
* ** ** * ** ** ******
*** *** ** ** * ** *** * *
** * * ** * * {
* ** * ** ** ** * * *** ******* ** * * ** * * * * ** * * ** * are no \"%s\" in \"%s\"",d,c);
****** ** *** *** * **

    
*** ** * * *** ** *** * ** ** **********
*** * * ** * ** *** * * 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include *** * *** * *

#include ** * ****

#include *** * ** ** ** **

#include *** ***** *



int main(void){
*** ** * * ** *** ** * **** ** * ** **
** * ** * i = 0;

  
* ** * ** * ** * * *** * ***

  
** ** * **** ** *** != '\0';i++)
*** * ** * ** **** * *** ***** * * = tolower(c[i]);
* * *** ******* ** * = '\0';
* * * *** * *** * * ** * *
* ** * * * * * * * * * * != '\0';i++)
* ** * ** * ** ** = tolower(cc[i]);
***** ** *** *** = '\0';
* **** ***
** * ** ***** * * * != NULL)
*** ** ** ** ** * *** *** * * * * * * is ** **** ** in * ** *** * * ** *
** * **** *
* ** ** * ** * * * ** * ** * * *** are no ** ** * * ** ** in * *** * *** **
* * * * * ** *** ** * **
*** * ** *
******* * ** ** ** * *** * *  
*** * * * * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * *** * * **

#include * *** * **

#include **** * * *

#include *****



int main(int argc, char *argv[])

{
****** *** **** ** *** ******* * * **
* *** ** * ** i = 0;
** *
* ** * * **** * ** *** *
* * * * *
*** ** ** * ******* *** ** != '\0';i++)
*** ** ***** ** ** **** * * = tolower(c[i]);
** * * ** * ** * * * != '\0';i++)
***** * * * * * ******* * ** * * ** * ** = tolower(cc[i]);
****** **
** * * * *** ** ** * != NULL)
*** * ** * ** * ** ** * * * * * is ** * * * *** in * ** ** * *** * *
* ** ***** ***
* * * ** * * ******** * ** * are no **** * * **** * in * * ** **** *** ******* *
***** * ** * ** ** ***** * *

  
*** * ** **** * * * * * *  
**** * ** ** ** 0;

}
answered by (-216 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.123.184
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20299 - Available when: Unlimited - Due to: Unlimited
| 16 views
0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20297 - Available when: Unlimited - Due to: Unlimited
| 17 views
0 like 0 dislike
121 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 12.1k views
0 like 0 dislike
54 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13021 - Available when: Unlimited - Due to: Unlimited
| 6.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users