0 like 0 dislike
3k views
子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
**** ******** ** ***** i=0,j=0,t;
**** *** **** * *** * ** ch,xh;
* *** * * * ** *** a[100],c[100];
** ** ********* * ** ** b[100],d[100];
* * *** ** ** * *****
* ** ** * ** * * * ** * ** ((ch = getchar()) != 32) {

***** ** * * ** ** ** ** * **** ** * * ** **** ** = ch;
* ** *** * ** * * ** * * * ******* ** * * * ***
* ** ****** * * * ***
*** * * ** ** ********
** * ** * * ** ***** = getchar()) !='\n') {
* * *** * ***** * ** * *** * * * **** * * = xh;
**** ***** **** * * ***** ** ** *** **
* ** *** * **
** * * **** **** *
*** * ** * * *** * **** * {
** **** * ** * * ***** * ** * * ** ** * ** ** *
* * ** * * * * ****** * * * **** * * **** **** * * * {
* **** ** ***** * ** * * * ** ***** *** * *** * * ** * ** * ** ********** *
****** * * *** * ** * * ** * ** *** *
******** ** ** * ******
**** ** * ***** * **
** * * ** *** ** ** *** *** * * {
** ** **** * ****** * * * ** ** ** **
* * * * * * * * ******* ** * * * *** *** ** {
** * ***** * * * * * * * *** **** ** * ** ** ** * *** *
** ** * *** * * * *** ** **** *** ***** * *
* ** ** * **** * *   

    


* ** *** * ** * ** ****** * * * {
**** ** * *** * **** * ** ******* ** * * * ***** ** is \"%s\" in \"%s\"",d,c);
***** * * *** * **
** * * ** * * * *** ** **
**** * * * * * * ** {
*** * *** * * *** * * **** * ** ** * * * *** ** are no \"%s\" in \"%s\"",d,c);
* ** ** *** * * *

    
* ** *** ****** * * * * * ** *
* * * ***** ** ** * * * 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include ** * ** ** * **

#include * ** * ** *

#include * * * **

#include * ** ** ** ** * *



int main(void){
* ** * ** * ** * ** *** * *
*** ** *** * i = 0;

  
***** ** ** ** ** * ** ** * ***** **

  
* *** ** * ** * * ** != '\0';i++)
* ** * *** ** *** ** ** ** * **** ** = tolower(c[i]);
* * **** ** * * * * = '\0';
* * * * * *** ** ***** * *** *
* * * * *** * **** ** *** * != '\0';i++)
*** *** * *** *** * ** * * ** * = tolower(cc[i]);
**** *** * * **** = '\0';
* * ** **
* * ******* ***** != NULL)
* * ***** * * * * ******* * * is * * ** * * in *** * ***** ** **
* * * ** * *
** ** * *** ***** ** ** ** * * * * are no ** ** ****** * in ***** * ***** **** ***
* ** ** **** * ***** *** * *** **
*** * * *
*** * *** **** * *** ** *** ** * **  
** **** ***** * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ** * * *** **

#include * * * * *

#include ** * * *

#include ** * **** * * *



int main(int argc, char *argv[])

{
* **** * ***** *** *** * * *** ** * * **
** * ** * **** i = 0;
** * ** * *
*** * **** *** * * *** **
**** * **
********* ********** ** * != '\0';i++)
* *** * ***** * *** *** ** *** = tolower(c[i]);
**** ** ** * * *** ** ** ***** != '\0';i++)
* * * *** **** ** ** ***** * ***** *** ** = tolower(cc[i]);
** *** ******* *
* * * *** * != NULL)
*** *** * * * ** * * * *** * ** *** * is * **** * * * in ** * * ** **** ** * * *
* * ***** *** *
***** ** * * *** ** *** ** **** * * ** are no ** *** *** * * in ****** * * * *** * **
** * **** * **** * **** **

  
** **** * * ** * ** *** * *  
** ** *** * *** 0;

}
answered by (-216 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.12
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20299 - Available when: Unlimited - Due to: Unlimited
| 16 views
0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20297 - Available when: Unlimited - Due to: Unlimited
| 17 views
0 like 0 dislike
121 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 11.1k views
0 like 0 dislike
54 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13021 - Available when: Unlimited - Due to: Unlimited
| 5.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users