0 like 0 dislike
3.1k views
子字串

請設計一個程式,使用者會輸入兩個字串,兩個字串間用一個空格隔開,每個字串的內容只會包含大小寫的英文字母,請判斷第二個字串是否出現在第一個字串內。請將大小寫視為同一個字。

輸入範例1:

friEND end

輸出範例1:

There is "end" in "friEND"

輸入範例2:

friEND friends

輸出範例2:

There are no "friends" in "friEND"
asked in 2016-1 程式設計(一)AD by (18k points) | 3.1k views

23 Answers

0 like 0 dislike
Hidden content!
#include<stdlib.h>

#include<stdio.h>

#include<string.h>

#include<ctype.h>



int main()



{
* ** * * ***** * * *** i=0,j=0,t;
*** ****** * ** *** ch,xh;
* ** *** * ** * ** ** a[100],c[100];
*** ******** ** * ** * * b[100],d[100];
*** * * ** **
** ** * * ***** ((ch = getchar()) != 32) {

* * ***** * ** ******* ******** ****** = ch;
** ** ** * * ****** * *** **** * * * * * * *
** * ** * ***
*** * ** *** * * * ** *
* * * * ** * **** = getchar()) !='\n') {
** **** ** ** ******** * **** * *** * ** ** = xh;
** ** ** * * ** ** ** * * * * * * *******
***** * * ** * ** *
* * *** * ** ****** *
* * * *** * ** * **** ** * * * {
** ** *** **** * * * ** *** * ** * * * * * ** *
***** * * **** * * * ** **** * ** *** {
* * *** ***** ** * *** * * ** * * * * * * * ** * * ** * * *** * ** *
* **** *** ** * ** * * *** ** ** *** ** * *
***** ** * **** *
* * **** * * **** * ***
* ***** * * ****** * * * ** * {
*** * * ** ** **** ** * ** ** * ** ** * * * * ***
*** * ** *** * * *** ** * ****** * ** ** ****** {
* * ** ** * * ** * ** **** *** ** * ** ** * * * **** * ** ** **** * **
* * * * *** ** * ***** *** *** * * *** **
*** * * *** ** ** * *   

    


** * *** * * * ** ** * * * ******* {
*** ** ** * *** * * **** ** * * *** * ** * * * ** is \"%s\" in \"%s\"",d,c);
***** * * **
* ** **** ** *
** ** * *** * * **** **** {
* * ** * * * *** **** * *** * *** *** ** ** *** ** ** are no \"%s\" in \"%s\"",d,c);
**** * ** ** **

    
* ** * ** * * ** ****** *
*** *** **** * * *** ***** 0;

}
answered by (122 points)
0 like 0 dislike
Hidden content!
#include * ***** ** **

#include ** * * **** *

#include * * * ** **

#include **** ** * * * ** *



int main(void){
* * *** * * * * * ** * **** *
* * * * * i = 0;

  
****** * ** ** *** ***

  
*** *** **** ** ** * * != '\0';i++)
*** * ** * ** * ***** ** ** * **** = tolower(c[i]);
****** ** * ** ** = '\0';
** ** * * * * ** * ***** *
** * ** * ** ** **** * ** != '\0';i++)
* * *** *** ** ** * ** * * * *** ** = tolower(cc[i]);
* * **** ***** * = '\0';
** *** ** *
** * * * ** ** *** * != NULL)
** ** * * * *** * * ** *** * * * ** *** * **** is * ** * * ** in ** ** *** ***** * * * ***
* * * * * * *
* ** * * * *** ** ** * *** ** * are no * * *** ** * * in ** **** *** *
** * *** * * ** * * ***
** ** *
***** * * ** *** * *** * * *  
* * * * * *** * * 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ** ** ** *** * *

#include * *** * *

#include * * * *

#include ** * * * *



int main(int argc, char *argv[])

{
* * * **** ** * ** ** ** **
* **** ** * i = 0;
** * *
*** * * * * * * **** * * * ** *
*** * * ** **
* * ** * * ****** ** ** != '\0';i++)
* ** ****** * * * * * * = tolower(c[i]);
* ***** * **** ** * * * * * != '\0';i++)
** **** ** *** ** * * ** *** * *** ** = tolower(cc[i]);
* * ** ******
** * ** *** ***** * * * != NULL)
* * ** ***** ** * * * * ** ** ** is *** *** *** * *** * in ***** **** * *** ***** ******
* ** **** ****** *
***** ** ** * ** ** * * ** * * ** are no ** * *** * in ** ** * ***** ** ** * *
* ** * * * * *

  
* * * **** ** * * * *** * ****  
**** ** * 0;

}
answered by (-216 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.240
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20299 - Available when: Unlimited - Due to: Unlimited
| 16 views
0 like 0 dislike
0 answers
[Resource] asked Dec 31, 2016 in 2016-1 程式設計(一)AD by laich (937 points)
ID: 20297 - Available when: Unlimited - Due to: Unlimited
| 17 views
0 like 0 dislike
121 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 11.4k views
0 like 0 dislike
54 answers
[Normal] Coding (C) - asked Oct 11, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 13021 - Available when: Unlimited - Due to: Unlimited
| 6.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users