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請設計一程式,使用者輸入一個正整數N,程式會輸出相對應的費氏數列第N項。

sample input:

10

sample output:

55
[Exercise] Coding (C) - asked in 作業 by (18k points)
ID: 16861 - Available when: Unlimited - Due to: Unlimited
| 3.8k views
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44 Answers

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Hidden content!
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main()



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answered by (-34 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>

#include <math.h>

int fibonacci(int number)

{
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}




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answered by (-50 points)
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Hidden content!
*** * *** * **** * *
* ** ** * * ** *
**** ** * *** ** *



int fib(int number)

{





int a, b = 1, c = 1, f =0;


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return 0;
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}



int main()

{

int num, fibon;


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* * ** * *** * * ** ** * * ** *



return 0;



}
answered by (-98 points)
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Hidden content!
#include * * *******

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#include ** * * * *** **



int ** *** (int number)

{
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}

}



int main()



{
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}
answered by (-120 points)
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Hidden content!
#include **** ** *

#include ** *** * * *

#include ** ** ** * *



int f(int number)

{
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}



int main()

{
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***** ** *** ** *** * = f(number);
** * ** *** ** * ***** ** fs);
* * ** * * * * 0;

}
answered by (-52 points)
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Hidden content!
* * * **** * * ** ** *** * * * * **** * printf */
* * *** ** ** *** ** * * ** **** * *** **** * * pow */
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long F(long n)

{
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}

void main()

{
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}
answered by (-248 points)
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Hidden content!
#include **** **

#include * * * * *
* * *** ** *** *** *



int main()

{
* * * ****** num = 0,sum = 0,i = 0,j = 0;
***** ** * *** ** * * * ** ** **** **
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*** ** *** ***** = 0;j < i;j ++)
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* * * **** * **** *


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* * ***** * * *** ** * ** *
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}
answered by (-122 points)
0 like 0 dislike
Hidden content!
* *** *** * *** *
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int * * *



{
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}
answered by (-24 points)
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Hidden content!
* * * * * * ** *** *** * ***** * ***** * ** printf */
* ** ** ** * ** * * ** * ** * ** **** * *** pow */
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long F(long n)

{
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}

void main()

{
**** * *** n;
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** * ** * ** ** ***** F(n));

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include *** *** * **

#include **** * ***

#include ***** ***



int f(int number)

{
*** ** **** * i, fsum[number];
* * * * * * ** = 1;
* *** ** **** * ** = 1;
* *** ** ********* * **
** **** ** * **
* ** ** *** * = * * * **


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** * * ** * ** ** ** * ** * ** * **** ** ***** = fsum[i-1] + fsum[i-2];
* * ** ** * ***** ** *** ***
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}



int main()

{
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** ***** *** * ** * ** * * ** &number);
********** * ** * = f(number);
* *** ** * * * **** * ** ***** fs);
* * ** * ***** * * ** * * 0;

}
answered by (-52 points)
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