1 like 0 dislike
4.9k views
請設計一個程式,由使用者輸入一個數,程式會找出其所有因數後由小到大輸出。

sample input:

12

sample output

1 2 3 4 6 12
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 4.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include *** * *** **



int main()

{
* * * ** *** ******* j,n,k,g=0;


** *** * * *** ** * * * * ** **** * * * **
* *** * * ***** ******** num[j-1];
* ******** ** *** * * * *** * * * *
*** * ***** **** * * ***** * * * *** *** (0==j%n)
** *** * * * * ** * ***** *
** * * * ** ****** * * **
* * ****** *** **** *** **** ** * *
* ** **** **** * ** *


* * * **** * *** ** * **


****** * *** ** *** * ** *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * * ** ** ***



int main()

{
** * **** * * * * * ** * j,n,k,g=0;


** ** * * ** ** ** * ** * ****************
*** ** *** * * * * num[j-1];
** *** * * ** * **** * **** **
* ******* ** *** ** *** * **** **** *** * * ****** (0==j%n)
* * ******* ** ** *** ** * * ***
** ******* ** * * * ** ** *
*** * * * * * * ** * * * *
*** * ** * * ** * * * *
** * *** ** *** * * ** ** ****** ** ** ** * * ** * ** **

printf(" ");
* * * * * * * *


** * ** * * * * * *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * **** ***** *

using * * std;






* * * main()
** **


* ** **** * * * ** *** * n;
** ** *** * * *** ** ** *** n;
***** *** **** *** * (int i = 1;i n; i++)
*** ** *** * ****** ****** * int j = i;j ** i;j++
* * * * ** * ******* * * ** * '*';
*** * *** * **** *** ** * *** ** *** * ** '\n';


* * ** *** ** **** ***












* ** *** **** * ** **** * *** ** *** **** *** ** 0;

}
answered by (-98 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * *



int main()

{
* * * * * * ** * * ** j,n,k,g=0;


**** * * * *** * * * *** * ******** ** ***
* * ** * ***** * num[j-1];
* ** * ** ** ** * ** ** * *** *** *
** *** * ***** ***** *** * * * **** ** ***** (0==j%n)
* * ** * ****** * ***** *
*** ***** * * * * ** ****
* ** ** ** *** ** * * ** ** * **
** ** * ******
* * * **** ** ** * * ** * *** ** * * ****

printf(" ");
* *** * ** *


** * *** **** *** *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** * * *

#include * *** ******



int main()

{
* * * * ** ** * j,n,k,g=0;


** ** * * ** ** * * * * ** * * * ***
* * *** * * * **** ** num[j-1];
* * * **** *** **** * * * * *
** ** *** * *** ** * * * * *** * ** * (0==j%n)
* *** * * * * * * *
* * * *** ** ** * * * ** ***
****** ** * *** * ** ****
* * * ** *** *******



printf(" %d",num[k]);


*** * *** * * * * *** *





 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include ** *** *

#include ** ** * *** **



int main()

{
* **** *** ** * ** j,n,k,g=0;


* * * ** * * * ** ** * * ****** * ***** **
** * ** **** * ** ** num[j-1];
* *** ** **** ** ** * * * *** ***
******* * * * ** * *** * ** ** * (0==j%n)
** * *** * *** ** * * *
** * *** * ***
* * * * *** ** ** * * * *** **** **
***** **** *** *** *


** *** *** * ** *****


* ** *** * ** *** * *
* ** ** *

printf(" ");

 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * ***



int main()

{
** ** *** * **** * ** j,n,k,g=0;


* **** * **** * ** ******** * * ** * ** ** * *
* * * * * *** * num[j-1];
** ********* ** **** *** *** * *
** * * *** * * * ** * ***** *** ** ** *** ** (0==j%n)
* * *** * * * ** ** * **** **
* *** * * ** * *** * * *
***** ***** * *** * ***
** * ** *** * * **


* * ** ** * *** **


* * ** *** * ****** ****** * **



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** ** * * ** *



int main()

{
* * * ** * * ** j,n,k,g=0;


* ** * * ** *** * * * ** *** ** * *
* * ****** * ** ******* num[j-1];
*** **** ** *** * * * **** ***** ***
* **** ** ** *** * * * * ** * *** (0==j%n)
*** * ** ***** * ** *** * * * * *
* ** * * ** * * *** *
*** ** * * **** ** *** * **
* * * * *** ** * ** *


*** * ***** * ** **

if(k < g-1)
* * * * * * * * * * ** * ");
** ** ***** ** ** *



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include **** *** *



int main()

{
****** ** ***** ** * ** j,n,k,g=0;


**** ** *** * ** ******** * ** *** *** ** * *
** ** * * *** **** * * num[j-1];
* ** ** ** *** * * * * * * ** * ** *
* *** * ***** ***** * ** * ** * *** ** ** * * **** (0==j%n)
**** * * * ***
*** ** ** * ** * *
* * ** * * ** * * *** ** * ** * *** *
*** **** ** * * ** *


* ** * * ***** ** **

if(k!=g-1)
** ** * * * *** * *** *** ");
** * * ** * * * *



 return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** ** ** * ***



int main()

{
** * * *** ** * ** * j,n,k,g=0;


* **** **** ** ******** *** * * ******** *
* * * * * ***** ** num[j-1];
* * * * **** * ** ****** *
* **** ** ** ** * * **** ** ** ** *** * * *** (0==j%n)
* * * **** *** * ******* * ***
* ** * * * * **** *** *
* * ** ****** * ** **** *** *** **
* ** * *** ** *** * * *


**** ** * * ***** * * **
********* ***** **** * **



 return 0;

}
answered by (-122 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.240
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.4k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.5k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.5k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 11.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users