1 like 0 dislike
1.8k views
請設計一程式,從使用者輸入的正整數中找出中位數輸出。使用者輸入的第一個數字N代表接下來會有多少個數字會被輸入,程式會從接下來的N個數中找出中位數輸出。輸出時請注意小數點尾巴的零不要輸出。

sample input:

4

1 2 3 4

sample output

2.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.8k views

18 Answers

0 like 0 dislike
Hidden content!
* * *** * * **



int main()

{
** **** * ** * ***** math[3], a, i;
* * ** ** *** * * sum, ava;


* * **** ** ** * **** * **** * * * * *** &a);
** *** * * **** * ** = 0;i < 4;i ++)
* ** **** * ** * *** ** ** * * * ** ** &math[i]);


* * * **** ***** * * = 0;i < 4;i ++)
* * ** ** ** * * **** * * * * ** * *** * += math[i];
** * * ** * * **** *** *** * *** * ** ** ** * = sum / 4;


** ** * * *** * * * * **** ** ** *** * * *** *** * * ** ***


****** *** * * * ** * * * *** *** ** * * ** * 0;

}
answered by (-114 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** ******** ******* * * *** * a,i;
**** * *** * * * * *** * *** ** * * *
* ** ** * * * * * *** * m,j,k;


******** * ** ** ** *** * ** math[100000];
** * *** ** * * ** **** * * * *
*** * ***** * *** *** ** * ** ****** * ** * ****** * *


** * ** * ** * * **** (a%2==0)

    {
****** *** * ******* ** * ** ** ** *** ** **
*** *** ****** *** *** **** ** ****** **** ** *
***** * * * * **** ** ** *** *** *** *
* * ** * ** * * * * ** ** * * ** * *** * * * **** * *

    }
* * * ** * *** * * * * if(a%2!=0)
** * *** * *** * ** ** * ** * * ** **** ** * *** * * * * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * ** * ** * * a,i;
* ** **** ** ** * * * * ** ** *** * *
** * * * * *** *** m,j,k;


** *** ** ** * * *** math[100000];
* ** * ** ** * * * ** *** * ****
* * ** * * **** * *** *** * * * * * *


* *** * ** * *** *** * (a%2==0)

    {
*** ** * *** * * **** ***** ** * * * ** * **** *
* * *** * * *** ** ** * * ***** ***** * * * * *
* * * * ** * * * * * * * **** * ** *****
*** ** ** * ** **** * * ** ****** * * * * **
* * * * * * ** * ** *
******* ** * ** ** * * * if(a%2!=0)

    {    m=math[a/2];
** * ** * * *** ** ******** *** *** ** * ** * * * *

}

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** ** * *** * * * * *** a,i;
**** ** * ** * *** ** ** * * * ** * *
**** *** ***** * ** * * ** m,j,k;


* * * * * * *** * **** math[100000];
* ** ** ** * * ** * *** *** **
* * ** *** ** ** * *** * ** * ** ** * ** * **


*** ***** ***** *** * * * (a%2==0)

    {
**** ** ** * * *** * ** * ****** **** * ** **
*** * *** * *** ** ** ** *** * * *** ** * * *
* ** * **** * * ***** **** * ** *** ******* * ** *
** ** *** *** ** ** **** * ** ****** ** * * * * * **** ** ***

    }
** ** * * ** ******* *** * if(a%2!=0)
********* ** * ** ** * * * ** *** * * *** * * ** * * * * * ** * ** ******

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include ** ** * * *

#include *** **** *******

#include *** * * ** *

int main()

{
** ******* * ** * *** * c;
* ***** *** *** * * ** a;
**** *** **** * *** * * * * *** * *** *** * *
** * * * * **** * b[a],i,j;




*** ** ** * * * ** ** (i=0;i<a;i++)
* ** ** ** * ** ** * * *
* **** ** * * * *** (j=0;j<a;j++)
* * ** ** * * **** *** * = c+b[j];


**** * *** * ** ***** *** ** = c/a;


* * * ** * * ** * *** **** **
** * * **** * * *** * 0;

}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
*** * * * ***** * * * * N;
**** * * **** * ** *** * * ** * *** *** * ** **
* ** * * * * * *** num[N],i;
**** * * * * ** ** * ave,sum=0;
** ***** * * ***** (i=0; i<N; i++)
* ** ** **** ****
* *** *** * ** * *** * *** * ** * * *** * * * ****** ** *** *** *
* *** * * * * * * *
* * * *** *** ** * * (i=0; i<N; i++)
** * ** * * * *** * *
* * ** * ** *** * *** * *** ** * ** = sum + num[i];
* * ** * * ***** * * **
** * **** ** ** ** ** * *** = sum / N;
* * * ** * ** **** * ** *******



}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main()

{
* * ** *** ** * * * N;
* *** * ** * * * *** ** *** ** * ** **
** * ** *** * ** * * * ** * num[N],i;
* ** * * * * ave,sum=0;
* * *** * * * (i=0; i<N; i++)
* ** * ** *** * **
** * **** **** * ****** ** * * ** *** *** * * * *** * ** *** ****** ** * ** *
* * ***** * * *
***** **** * ** ** * * * ** (i=0; i<N; i++)
* **** ** ** ** ****
* ** * * *** ** * ** * * ** * * * * * ** * * ** * = sum + num[i];
** ******** ** * ***
* ** **** * * * ** *** = sum / N;
*** **** * ** * * * ** * ** *** * * * **



}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include ** * ** *****

int main()

{
**** * * *** ** *** * * * n,anynum,p,sum,ans;
* * ** * **** * * *** * *** *** * ** * *


* * * ** * ** * ** (p = 0;p < n;p ++)
** ** *** ** * **
* ** **** * * **** * *** * * * * ** *** ** * * * ***
* ** **** ** *** *** ** * *** ** += anynum;


* *** **** **** * ** **
**** ** * ** ** = sum / n;
*** * * ***** * ** ** ** * ** * * ** ***


* * * * * * * * ***** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.114
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.5k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.9k views
0 like 0 dislike
112 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15426 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 8.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users