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AC 20161005 作業 1
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請設計一個程式當使用者輸入一個分數(介於0-100間)，程式會輸出相對應的等第
90-100 => A
80-89 => B
70-79 => C
60-69 => D
0-59 => F
輸入範例1
100
輸出範例1
A
輸入範例2
59
輸出範例2
F
[Exercise]
Coding (C)
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Oct 5, 2016
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Shun-Po
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Hidden content!#include * * * * **
main()
{
* * grade;
* * * * ** * * * ** ** ** ** * * * * **
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}
answered
Oct 5, 2016
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410523034
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Hidden content!#include <stdio.h>
int main()
{
float i;
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}
answered
Oct 5, 2016
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CHONGYAOWEI
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Hidden content!#include * * ** * * *
int *
{float a;
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return 0;}
answered
Oct 5, 2016
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410523022
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Hidden content!#include <stdio.h>
int main ()
{
*** * * * ***** * * ** num;
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if (num >=90)
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* * * * *** * * ** * * * ** * 0;
}
answered
Oct 5, 2016
by
410425014
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Hidden content!#include <stdio.h>
int main()
{
int grade;
* * *** * * * * * ** *
scanf("%d", &grade );
if (grade >= 90){
* * * * * * * ** * * ** ** * * * * A");
}
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*** ** * ** * **** ** * * * ** * * * B");}
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}
return (0);
}
answered
Oct 5, 2016
by
loyfree0706
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Hidden content!#include <stdio.h>
main()
{
* * * * ** *** ** * ** * number=0;
* * *** *** * * * * * * * * ** * ** * * * * * * * * * &number);
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answered
Oct 5, 2016
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Doloa
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Hidden content!#include <stdio.h>
main()
{
* *** ******** *** *** ** * number=0;
* ** ** * *** * * * * *** * * * *** * &number);
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}
answered
Oct 5, 2016
by
Doloa
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int a = 0;
printf("請輸入成績");
scanf("%d",&a);
if(a>=90)
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else
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}
answered
Oct 5, 2016
by
SRFX
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Hidden content!#include<stdio.h>
int main(void)
{
* * ** * * * * ** num;
* * ** *** * * * * * * * * * * * ** * **
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}
** * * * * ** ** * * * 0;
}
answered
Oct 5, 2016
by
蘇瑋朝
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * **** ** * * grade=0;
*** ** * ** ** * *** ** * ** * **** * ** * * ** * **** *
** * ** ** * *** ** * ** * * * * * ** ** ** &grade);
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* * ** * * * * * * * *** * if(grade>= 80)
* * * ** * * * * *
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**** ** * * ***** * ** * if(grade >= 70)
** * * * * * *** *** * ** *
* ** * ** * ** ** * * * ** * ** * * * * * * ** * * %f 成績C", grade);
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* ** * ** * ** *** * ** * ** * *** * * ** * * * * * %f 成績D", grade);
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* * * ** * * * * ** ***
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** ** *** * * * * ** ** *
* * *** * ** * * * **** **** 0;
}
answered
Oct 5, 2016
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