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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
[Exercise]
Coding (C)
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
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Sep 29, 2016
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楊傑宇
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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}
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Hidden content! * * * * * ** *
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answered
Sep 29, 2016
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Hidden content!#include * * * *** ** *
#include *** * **
int main()
{
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Sep 29, 2016
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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}
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Sep 29, 2016
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Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
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}
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Sep 29, 2016
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Hidden content!#include <stdio.h>
int main()
{
* * ** * ** * *** * * year;
* ** ** * * ** * * ** ** * input year:\n");
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* * ** ** * * * * * * * * * ***** **** * * * * ** * * * days");
** * * ** * * * * *
** * * * ** 0;
}
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Sep 29, 2016
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Hidden content! * ** ** * * * *
* * * * ** *
** * * * ** * ** * main()
{
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* * * * * * *** * *** 0;
* * *** **
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Hidden content!#include ** ** * * ** * * *
#include * ** ** ** *
int main()
{
* * * * * * * ** * * * * * * * * year=0;
* ** * * * * * * ** * ** * * * ** * input the year\n");
* *** *** ** * * * * * * * * * * ** * * * * * ** &year);
** **** * ** * * * *** ** * * * ** * % 4 == 0 && year % 100 != 0)
* ** * * * ** * * ** * * * *
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* * * *** * * * ** * * ** * if(year %100==0 && year% 400!=0)
** ** * * ** * * * * *
* * ***** ** * ** ** * * ** * ** ** ** ** ** ** ** ** * * * ** ** ** * * * year is not leap year",year);
* ** * ** * ** ** * * **** *
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* * * * * * ** * * ** * * * * ** ** * ** * * * * * year is leap *** ** * * *
*** ** * * * * * **** ** * * ***
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*** * ** * * * * * *** *** ** * * *** ** * * * * * * *
}
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Sep 29, 2016
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
** * * * *** * * ** **** * * * * * ***** *** * * * * ** * * * *
* * * * * * ** * ** ** * * ** * *** ** ** * * * *
** * * ** * * * ***
* ** * ** * ** * * * * * * * * * *** * * *
* ** * ** *** * * * * * * * * * && year%100!=0)
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* * * ** * ** * * * * * * *** * * * ** * * * * * ** * *
* **** * * * * * ** * * * ** * ** * * * * * *** * * 0;
}
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