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We will use this function to proceed and store the result 

void find_two_largest(int a[], int n, int *largest, int *second_largest);

* When passed an array a of length n, the function will search a for its largest and second-largest elements, storing them in the variables pointed to by largest and second_largest respectively.

寫 find_two_largest() 函數。陣列做為函數參數 找出最大值跟第二大值。

Finish the code below to match the input and output. Pointer is required. 請使用指標。

#include <stdio.h>

void find_two_largest(int a[], int n, int *largest, int *second_largest);

int main(void)
{
	int n, largest, second_largest;
	scanf("%d", &n); //Numbers will be entered
	int a[n];
    //Enter n integers separated by spaces
	for (int i = 0; i < n; i++)
		scanf(" %d", &a[i]);

	find_two_largest(a, n, &largest, &second_largest);

	if (n == 0)
		// Your code here
		//Print No numbers were entered.
	else if (n == 1)
		// Your code here
		//Print Only one number was entered. Largest: 
	else
		// Your code here
		//Print Largest: , Second Largest:

	return 0;
}

void find_two_largest(int a[], int n, int *largest, int *second_largest)
{
	// Your code here (Using pointer to finish)
}

Example input:

0

Example output:

No numbers were entered.

Example input:

1
67

Example output:

Only one number was entered. Largest: 67

Example input:

5
5 6 7 8 9

Example output:

Largest: 9, Second Largest: 8

 

[Exercise] Coding (C) - asked in Chapter 12: Pointers and Arrays
ID: 38251 - Available when: Unlimited - Due to: Unlimited

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58 Answers

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Hidden content!
#include <stdio.h>

void find_two_largest(int a[], int n, int *largest, int *second_largest);

int main(void)
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Hidden content!
#include <stdio.h>

void find_two_largest(int a[], int n, int *largest, int *second_largest);

int main(void)
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answered by (-167 points)
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Hidden content!
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answered by (-285 points)
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answered by (-168 points)
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prog.c: In function 'find_two_largest':
prog.c:33:17: warning: comparison between pointer and integer
         if(a[i] > largest){
                 ^
prog.c:35:21: warning: assignment makes pointer from integer without a cast [-Wint-conversion]
             largest = a[i];
                     ^
prog.c:36:25: warning: comparison between pointer and integer
         } else if (a[i] > second_largest
                         ^
prog.c:37:21: warning: comparison between pointer and integer
             && a[i] < largest){
                     ^
prog.c:38:28: warning: assignment makes pointer from integer without a cast [-Wint-conversion]
             second_largest = a[i];
                            ^
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#include * **** *** *
#include * ** * ** *


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* * * *

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* ****** * * ** *


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** * * * **** * **


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prog.c: In function 'find_two_largest':
prog.c:10:11: warning: comparison between pointer and integer
  if (a[i] > largest)
           ^
prog.c:12:16: warning: assignment makes pointer from integer without a cast [-Wint-conversion]
        largest = a[i];
                ^
prog.c: In function 'main':
prog.c:40:14: warning: missing terminating " character
       printf("Only one number was entered. Largest:%d,&largest);
              ^
prog.c:40:14: error: missing terminating " character
       printf("Only one number was entered. Largest:%d,&largest);
              ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:41:3: error: expected expression before '}' token
   }
   ^
prog.c:41:3: error: expected ';' before '}' token
prog.c:44:14: warning: missing terminating " character
       printf("Largest: %d, Second Largest: %d,&largest, &second_largest);
              ^
prog.c:44:14: error: missing terminating " character
       printf("Largest: %d, Second Largest: %d,&largest, &second_largest);
              ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:45:3: error: expected expression before '}' token
   }
   ^
prog.c:45:3: error: expected ';' before '}' token
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#include * * * ** ** ** *
#include **** *** * *** *


void ****** *** a[], int n, int *largest, int *****
{
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*** * * * ** * *** int i, * ** ** ** ** ** *
* *** ** * * ** * ** *******
* * * ** ** ** * * * * ******
* * * ** ** * ** ** for (i=0; * * * i++)
** **** ** * * * * *** {
*** * * ** ** ***** * * * ** * ********* *** *
* * * * * * * ** ** *** * ** ****** * ** *
** ** * * * ** ***** *** * * ** * }
* ** * * ** ** ** *** * }
* * * * * *** ** * **
*** ****   **** **** * *** ** ** ** * %i, * **** * *

* * * * ** ** * * * * for (i=0; * * ** i++){
* * ** ** ** * * * * **** ***** * * * *** ** * * * ** * ******* * * ** ** * **** *** * *
*** ** * * ** * * ** **** * *** ** *** * * ** * * * * * * * * * * * ***** ***
** ** * ** * * ** ** ** * * **** }
**** * ** *** * }
* * *** * ** ** * ** * * ** * * * *** ***
* ** *** *** **** *** ** *** ** *** * * ** * **** * Largest: * ** *** **** *****

* *** *** ** }
}

void * * * a[], int n, int *largest, int *** * *

int ** *
{


* * * * ****** int n, largest, **** **

*** * * * ****** *** * * *
* ** *** * int a[n];

** *** for (int i = 0; i < n; i++)
** * * * * * * ** * * *** * * * ***** * * *

* ** ** * * * ** ** n, * ** * ***** * *** *


* ***** **** *** return 0;
}
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Case 0: Correct output
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