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5.4k 瀏覽
若一個正整數的奇數位數字和與偶數位數字和兩者差的絕對值是11的倍數,則這個正整數就是11的倍數,否則就不是11的倍數。

請寫一個程式來判斷輸入的數是不是十一的倍數。

 

輸入說明:

會輸入一個正整數N,N不會超過1000位。

 

輸出說明:

如果輸入的數字是11的倍數就在螢幕上輸出YES,否則就輸出NO。

 

輸入範例:

11111111111111111111111111111111111111111111111111

 

輸出範例:

YES
[考試] 最新提問 分類:2017-1 程式設計(一)AD | 用戶: (18k 分)
ID: 36178 - 從幾時開始: 2017-12-08 18:30 - 到幾時結束: 無限制
| 5.4k 瀏覽

19 個回答

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內容已隱藏
#include<stdio.h>
int main()
{
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最新回答 用戶: (202 分)
0 0
prog.c: In function 'main':
prog.c:8:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
   scanf("%s", N);
           ^
prog.c:48:7: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
       system("pause");
       ^~~~~~
0 0
prog.c: In function 'main':
prog.c:8:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
   scanf("%s", N);
           ^
prog.c:48:7: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
       system("pause");
       ^~~~~~
0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>

int main()
{
* * * * ** * *** * ** *** long long n;
** * * * ***** ** * * * * * * * *****
    {
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*** ** **** ** * *** ** ** * * * * ** * * * ** ***** * * **** * * ** * *
** ** * **** * ** *

* * * * * * * *** ** ** * * 0;
}
最新回答 用戶: (114 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{
* **** *** ** **** * input[10000];
* * *** * * ** * ** **** *** * * *
    {
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    }
** * * * ** ** *** ** 0;
}
最新回答 用戶: (30k 分)
修改於 用戶:
0 0
prog.c: In function 'main':
prog.c:7:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[10000]' [-Wformat=]
     while(scanf("%s",&input)!=EOF)
                   ^
prog.c:14:12: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
         if(abs(a-b)%11==0)
            ^~~
0 0
prog.c: In function 'main':
prog.c:14:12: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
         if(abs(a-b)%11==0)
            ^~~
0 0
prog.c: In function 'main':
prog.c:14:12: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
        ans=abs(a-b);
            ^~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
prog.c: In function 'main':
prog.c:13:12: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
         if(abs(a-b)%11==0)
            ^~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>
#include <string.h>
int main()
{
* * * * **** **** i,j,add=0,even=0;
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* ** * ** *** * * *

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* * ** * * * ** ** 0;
}
最新回答 用戶: (174 分)
修改於 用戶:
0 0
prog.c: In function 'main':
prog.c:10:13: error: 'i' undeclared (first use in this function)
     for(n=0;i=0;i<=a;i++) //\xe5\xa5\x87\xe4\xbd\x8d\xe6\x95\xb8\xe5\x81\xb6\xe4\xbd\x8d\xe6\x95\xb8\xe5\x88\xa4\xe6\x96\xb7,a<=10^999
             ^
prog.c:10:13: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:21: error: expected ')' before ';' token
     for(n=0;i=0;i<=a;i++) //\xe5\xa5\x87\xe4\xbd\x8d\xe6\x95\xb8\xe5\x81\xb6\xe4\xbd\x8d\xe6\x95\xb8\xe5\x88\xa4\xe6\x96\xb7,a<=10^999
                     ^
prog.c:12:18: error: invalid suffix "n" on integer constant
       if(c=a/10^(2n))
                  ^~
prog.c:17:22: error: expected ')' before ';' token
      for(n=0;i=0;i<=a;i++)
                      ^
prog.c:19:38: error: invalid suffix "n" on integer constant
                           if(d=a/10^(2n+1)
                                      ^~
prog.c:20:27: error: expected ')' before 'even'
                           even+=d;
                           ^~~~
prog.c:21:5: error: expected expression before '}' token
     }
     ^
prog.c:25:1: error: expected '}' before 'else'
 else
 ^~~~
prog.c: At top level:
prog.c:28:2: error: expected identifier or '(' before 'return'
  return 0;
  ^~~~~~
prog.c:29:1: error: expected identifier or '(' before '}' token
 }
 ^
0 0
prog.c: In function 'main':
prog.c:6:12: warning: zero-length gnu_printf format string [-Wformat-zero-length]
     printf("");
            ^~
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(a);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
prog.c:14:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<=strlen(a);i=i+2)
                ^~~~~~
prog.c:14:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:14:16: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:22:17: warning: incompatible implicit declaration of built-in function 'strlen'
      for(i=1;i<=strlen(a);i=i+2)
                 ^~~~~~
prog.c:22:17: note: include '<string.h>' or provide a declaration of 'strlen'
/tmp/ccEDkE9I.o: In function `main':
prog.c:(.text+0x51): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:6:12: warning: zero-length gnu_printf format string [-Wformat-zero-length]
     printf("");
            ^~
prog.c:7:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(a);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
prog.c:14:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<=strlen(a);i=i+2)
                ^~~~~~
prog.c:14:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:14:16: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:22:17: warning: incompatible implicit declaration of built-in function 'strlen'
      for(i=1;i<=strlen(a);i=i+2)
                 ^~~~~~
prog.c:22:17: note: include '<string.h>' or provide a declaration of 'strlen'
/tmp/ccuq6Kb5.o: In function `main':
prog.c:(.text+0x51): warning: the `gets' function is dangerous and should not be used.
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&a);
             ^
prog.c:13:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<=strlen(a);i=i+2)
                ^~~~~~
prog.c:13:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:13:16: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:21:17: warning: incompatible implicit declaration of built-in function 'strlen'
      for(i=1;i<=strlen(a);i=i+2)
                 ^~~~~~
prog.c:21:17: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&a);
             ^
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>
int main(void)

{
* **** * ** ********* *** num[1000];
* *** * * ** *** * i,a,b;
*** * * * *
* * * ** *** **** * ** ** a number:");
* ****** **** * * * * ** ** = 0; i<1000; i+2)
*** * * *** * ** ** * ***
* ** * * * * * * ** += num[i];
** ** ** * ** ** ** += num[i*2+1];
** * * ** *** ** ** **
** * *** *** * ** *
* * *** *** * **** * * ** == 0)
* ***** ******* ** ** ** ** * ****
* * * ** **** *** ** *
* *** ******* * * *****
* * ***** ** * **** ** * *** ** ** * *** *
* * ***** *
******* **** ** ** *** * 0;
}
最新回答 用戶: (212 分)
0 0
prog.c:1:2: error: invalid preprocessing directive #inlude
 #inlude<stdio.h>
  ^~~~~~
prog.c: In function 'main':
prog.c:8:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("Enter a number:");
     ^~~~~~
prog.c:8:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:8:5: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>
int main()
{
**** * ** * *** *** ** x;
* ** *** * * *** ****** * * enter a number\n");
*** ** * *** **** * * * ** * * * *
******* * * * * * ** *
** ** * * ** * * *** ** ** * **** * * * * * * ** ** *****
** * ** * * ** * * * ** ** *** ** ** *
** * * * * * * * * ** * ****** ** *** * **** * ** * ** *** ****
    
* *** * *** * *
}
最新回答 用戶: (172 分)
1 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>

int main()
{   
* *** ** ** *** ** *** * * a;
* ** * * * *** * * ** * *** * * your number:");
* ** *** * *** ** *** ** **** ** * * ****
* * *** ** *** ** * % 11 == 0)
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* * ** * **** ** ** ** *
**** * **** **** * * ******* *** ** ****
** * * * * **
** * * * ** * ** * ** ** *****
*** * ** * * * ******* * ** 0;
}
** * **** * * *
最新回答 用戶: (164 分)
0 1
prog.c: In function 'main':
prog.c:13:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("pause");
     ^~~~~~
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>

int main(){
******* * **** * ** * * *** *
** ** *** * ** * *** *** * num;
* ******* * ** * * **
** ** * * * *** ** *** *** * * * *** ** ** * * **
* ** * * * ** *****
    
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** * ** * ** ** * ****** * *** *
*** **** ** * **** * * *** * ********

* * * * ** * ****** * *** *
** * * ** * * * *
}
最新回答 用戶: (192 分)
修改於 用戶:
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&ch);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&ch);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1000]' [-Wformat=]
     scanf("%s",&ch);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>
#include<stdlib.h>
int main(void)
{
** * ** * * * *** *** in,a;
**** * * ** ****** ** * **** * ***
*** ** ** * * * * *
** * *** * * ** * *******
* ** *** ** * **
* * ** * * * *** * * ** * *
* **** * ** * * ** * * * * *** ** ** * ** **** * *
*** ** * * * * * * ** * * **
** * ** *** *** ** ** if (a!=0){
***** ** * *** *** ** * * ** * **** * *** * ***** * ** ** * ** *
* ** * * *** ** *** * * ** * *** * * ****
**** * *** ** *
system("pause");
return 0;

}
最新回答 用戶: (185 分)
0 0
prog.c: In function 'main':
prog.c:6:14: warning: format '%ld' expects argument of type 'long int *', but argument 2 has type 'long int' [-Wformat=]
     scanf("%ld",in);
              ^
0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>
int main()
{
* ** ** * ** ** * j, k = 0, l = 0;
* ** * ** * * * ** * str[10000] = {0};
* * **** * ** ** **** * * ** **** * * str);
**** * * **** * * * **** * * = 0;j < strlen(str);j ++)
* ** * * * ** *
******** * * * * ** *** * ** ** * ** ** * *** % 2)
* * ** ** ****** * * * * * * ** **** *** ** * ***
***** * * *** * * ** * * * * *** *** * * * ** * * += str[j] - '0';
**** * * * *** ** **** ** ** ***** * * *
* ** * * * *** *** *** ** * ** ** *
* ** ** * * * * **** ****** * *** * ****** **
**** ***** * * *** * * * ** * * **** * * ** ****** ** *** * *** * += str[j] - '0';
* * * ** * *** * * **** **** ** ***** **
** ** ** *********** **
***** ** *** * ******* ** - l) % 11 == 0)
* **** * *** *** ** * * * ** * * *** * * ** * *** * * * **
* ** * ** ******* * ***
*** ** * ** ***** * ** ** * * **** * * * * ** * ** * * *
}
最新回答 用戶: (18k 分)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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