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請寫一個程式,把輸入的阿拉伯數字轉成羅馬數字輸出。

羅馬數字的規則請參考

https://zh.wikipedia.org/wiki/%E7%BD%97%E9%A9%AC%E6%95%B0%E5%AD%97

輸入說明:

會輸入一個不超過1000的正整數

輸出說明:

請將相對於輸入數字的羅馬數字輸出

輸入範例:

14

輸出範例:

XIV
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 34979 - Available when: Unlimited - Due to: Unlimited
| 3.3k views

6 Answers

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Hidden content!
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int did(char a)
{
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** * ** * **** * return 100;
* * * * *** * * * * ** return 500;
** *** * * * ** * * ** * return 1000;
** * ** *** **
* * * * * 0;
}
int main()
{
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*** ** * int sum;
* *** * ** char s[1101];
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}
answered by (236 points)
0 0
prog.c: In function 'main':
prog.c:5:1: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
 ^
prog.c:5:2: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
  ^
prog.c:5:3: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
   ^
prog.c:5:4: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
    ^
prog.c:5:5: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
     ^
prog.c:5:6: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
      ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 while(scanf("%s",&a)!=EOF)
               ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 scanf("%s",&b);
         ^
prog.c:136:9: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
 int sum=abs(suma-sumb);
         ^~~
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
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int main()
{
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}
answered by (215 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before '.' token
 .
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
* * ***** * *** **
int main()
{
char *th[] = { * * ** * * ******* *
char *hun[] = { ** ** ** * ** ***** * *** **** * ********* ***** ** ** * ** **** * ** ** * ** **** ** * * * * * ** ***** ** * * * **** ** ** * };
char *ten[] = { * ** *** ** * ** *** *** * *** * * * ** ** * * * ** * ** ** * **** * * *** *** * ** * * * * **** * * * **** * * };
char *one[] = { **** * * *** * ** ** * *** **** *** ** * ** * * ** *** * * * * * * * * * * ** *** ** ** * * * * ******* ** *** ** * };
int input;

while( scanf( ** **** * * ** * *** **** ) != EOF )
** * * * ** * *** * th[ ** ** ], hun[ * * * ], ten[ ** * ], one[ * * * ] ); * * *
* * 0;
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * ** ** * ** *


int main()
{
char ******* * = { * * ** ** * ** ***** * * *** * * * * * * **** * };
char ** ** = { *** **** * * ** ***** * ****** ** * ** * * * * ** * ***** ** ****** ** ** * * * ******* * ** *** * * * * ** ** *** *** * * * };
char *ten[] = { **** * * * * * * ** *** * * * * * * * * ** * * * *** **** * * ***** *** ** * * * *** * ** ** ** ** * ** *** ** ** * * * * **** * ** ** };
char *one[] = { * ** * **** * *** ** * * ***** * * *** ** * **** **** * ** * * ******* * * **** ** ** * * *** ** * * * ** * ** * };

int input;

* * ** ** ** ** );
printf( * *** * * * * thousand[ ], hundred[ * * ], ten[ **** ], one[ input%10 ] );

return 0;
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * * * * * **
int main()
{

* *** * * * char ** ** *** = { * * * **** ** * * * ** * ** * ***** ** ***** };
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* * * * ** int n;

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** *** *** printf( *** * * * *** ** ** n/1000 ], hundred[ * ** ], ten[ ** ** ], one[ n%10 ] );

return 0;
}
answered by (160 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * ** * * *


int main()
{

** * * * ** * * * thousand[2][5]={ * * **** ** ** * ** };
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** ** * ** * input;
* *** * * * * * * *** * * scanf( * * ****** &input ) != EOF )
* *** ** ** *** ***** * ** ** *** *** **** * ** * * * * * ** * * * *** thousand[ input/1000 ], hundred[ (input/100)%10 ], ten[ (input/10)%10 ], one[ input%10 ] );

* * * *** ** *** * * 0;

}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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