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請寫一個程式,輸入任意字元,程式會輸出該字元相對應的十進位ASCII碼

輸入說明:

程式每次會輸入一個字元

輸出說明:

對於輸入的字元,請輸出相對應的十進位ASCII碼

輸入範例:

0

輸出範例

48
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 31094 - Available when: Unlimited - Due to: Unlimited

edited by | 10.4k views

29 Answers

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answered by (236 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (212 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (194 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (194 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
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answered by (194 points)
0 0
prog.c: In function 'main':
prog.c:5:11: warning: too many arguments for format [-Wformat-extra-args]
    printf("\xe7\xa8\x8b\xe5\xbc\x8f\xe6\xaf\x8f\xe6\xac\xa1\xe6\x9c\x83\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x80\x8b\xe5\xad\x97\xe5\x85\x83",c);
           ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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Hidden content!
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answered by (194 points)
0 0
prog.c: In function 'main':
prog.c:6:5: warning: implicit declaration of function 'getch' [-Wimplicit-function-declaration]
   c=getch();
     ^~~~~
/tmp/ccnbCj2o.o: In function `main':
prog.c:(.text+0x1f): undefined reference to `getch'
collect2: error: ld returned 1 exit status
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Hidden content!
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answered by (100 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
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answered by (174 points)
edited by
0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
0 0
prog.c: In function 'main':
prog.c:6:12: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%c",&c);
            ^
0 0
prog.c: In function 'main':
prog.c:6:12: warning: format '%c' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
    scanf("%c",&c);
            ^
0 like 0 dislike
Hidden content!
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answered by (194 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
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answered by (228 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
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