10/12 Exercise: Complete a program with output format

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Please take a look at the uncompleted program in the bottom and fill in the gaps with properly output format to complete the program in order to display the following output:
把還沒完成的程式寫完
Remember: Direct output or cheated output is always forbidden.

#include <stdio.h>
int main()
{
    int x = 21, y = 0xa , z = 077;
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", y);
    printf("______________ \n", y);
    printf("______________ \n", y);
    printf("______________ \n", z);
    printf("______________ \n", z);
    printf("______________ ", z);
    return 0;
}

Required output:

21
 21
15
25%
A
 a
10
77
077
63

 

[Exercise] Coding (C) - asked in Chapter 3: Formatted Input/Output by (12.1k points)
ID: 26463 - Available when: Unlimited - Due to: Unlimited
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87 Answers

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Hidden content!
#include <stdio.h>
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answered by (-498 points)
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Case 0: Correct output
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Hidden content!
#include <stdio.h>

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answered by (-249 points)
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Case 0: Correct output
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Hidden content!
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Hidden content!
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Hidden content!
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answered by (-304 points)
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Case 0: Correct output
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Hidden content!
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answered by (-168 points)
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>
int main (void)
{
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}
answered by (42 points)
0 0
prog.c: In function 'main':
prog.c:4:18: error: 'a' undeclared (first use in this function)
     int x=21,y=0*a,z=077;
                  ^
prog.c:4:18: note: each undeclared identifier is reported only once for each function it appears in
prog.c:5:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("15\n",x);
            ^~~~~~
prog.c:6:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("21\n",x);
            ^~~~~~
prog.c:7:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("21\n",x);
            ^~~~~~
prog.c:8:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("63\n",x);
            ^~~~~~
prog.c:9:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("a\n",y);
            ^~~~~
prog.c:10:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("A\n",y);
            ^~~~~
prog.c:11:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("10\n",y);
            ^~~~~~
prog.c:12:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("077\n",z);
            ^~~~~~~
prog.c:13:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("77\n",z);
            ^~~~~~
prog.c:14:15: warning: spurious trailing '%' in format [-Wformat=]
     printf("25%",z);
               ^
prog.c:14:12: warning: too many arguments for format [-Wformat-extra-args]
     printf("25%",z);
            ^~~~~
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answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:4:17: error: 'oxa' undeclared (first use in this function)
   int x= 21, y= oxa, z = 077;
                 ^~~
prog.c:4:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:14:15: error: unknown conversion type character 0xa in format [-Werror=format=]
   printf("%.30\n", z);
               ^
prog.c:14:10: error: too many arguments for format [-Werror=format-extra-args]
   printf("%.30\n", z);
          ^~~~~~~~
cc1: all warnings being treated as errors
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