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Please take a look at the uncompleted program in the bottom and fill in the gaps with properly output format to complete the program in order to display the following output:
把還沒完成的程式寫完
Remember: Direct output or cheated output is always forbidden.

#include <stdio.h>
int main()
{
    int x = 21, y = 0xa , z = 077;
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", x);
    printf("______________ \n", y);
    printf("______________ \n", y);
    printf("______________ \n", y);
    printf("______________ \n", z);
    printf("______________ \n", z);
    printf("______________ ", z);
    return 0;
}

Required output:

21
 21
15
25%
A
 a
10
77
077
63

 

[Exercise] Coding (C) - asked in Chapter 3: Formatted Input/Output by (12.1k points)
ID: 26463 - Available when: Unlimited - Due to: Unlimited

edited by | 15.1k views

87 Answers

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Hidden content!
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int main()
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answered by (-336 points)
0 0
prog.c: In function 'main':
prog.c:6:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("15\n",x);printf("25%%\n",x);
        ^~~~~~
prog.c:6:25: error: too many arguments for format [-Werror=format-extra-args]
 printf("15\n",x);printf("25%%\n",x);
                         ^~~~~~~~
prog.c:7:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("A\n",y);printf(" a\n",y);
        ^~~~~
prog.c:7:24: error: too many arguments for format [-Werror=format-extra-args]
 printf("A\n",y);printf(" a\n",y);
                        ^~~~~~
prog.c:8:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("10\n",y);printf("77\n",z);
        ^~~~~~
prog.c:8:25: error: too many arguments for format [-Werror=format-extra-args]
 printf("10\n",y);printf("77\n",z);
                         ^~~~~~
prog.c:9:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("077\n",z);printf("63\n",z);return 0;}
        ^~~~~~~
prog.c:9:26: error: too many arguments for format [-Werror=format-extra-args]
 printf("077\n",z);printf("63\n",z);return 0;}
                          ^~~~~~
cc1: all warnings being treated as errors
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Hidden content!
#include <stdio.h>

int main (void)
{
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answered by (-107 points)
0 0
Case 0: Correct output
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answered by (-329 points)
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>
int main()
{
int x=21,y=0xa,z=077;
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answered by (-336 points)
0 0
prog.c: In function 'main':
prog.c:6:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("15\n",x);printf("25%%\n",x);
        ^~~~~~
prog.c:6:25: error: too many arguments for format [-Werror=format-extra-args]
 printf("15\n",x);printf("25%%\n",x);
                         ^~~~~~~~
prog.c:7:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("A\n",y);printf("a\n",y);
        ^~~~~
prog.c:7:24: error: too many arguments for format [-Werror=format-extra-args]
 printf("A\n",y);printf("a\n",y);
                        ^~~~~
prog.c:8:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("10\n",y);printf("77\n",z);
        ^~~~~~
prog.c:8:25: error: too many arguments for format [-Werror=format-extra-args]
 printf("10\n",y);printf("77\n",z);
                         ^~~~~~
prog.c:9:8: error: too many arguments for format [-Werror=format-extra-args]
 printf("077\n",z);printf("63\n",z);return 0;}
        ^~~~~~~
prog.c:9:26: error: too many arguments for format [-Werror=format-extra-args]
 printf("077\n",z);printf("63\n",z);return 0;}
                          ^~~~~~
cc1: all warnings being treated as errors
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Hidden content!
#include <stdio.h>
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answered by (-196 points)
0 0
Case 0: Correct output
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Hidden content!
#include <stdio.h>



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answered by (-107 points)
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answered by (-304 points)
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Case 0: Correct output
0 like 0 dislike
Hidden content!
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answered by (-140 points)
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Hidden content!
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answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:14:12: error: too many arguments for format [-Werror=format-extra-args]
     printf("A\n", y);//A
            ^~~~~
prog.c:15:12: error: too many arguments for format [-Werror=format-extra-args]
     printf("a\n", y);//a
            ^~~~~
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

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answered by (-258 points)
0 0
Case 0: Correct output
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